Same, I don’t understand a thing of what my teacher says, I guess that’s why people don’t go to his classes anymore, they’re so unorganized and not understandable XD
Omg! I got PTSD just watching this video 😖. I’m now a freshman in college and I remember watching your videos religiously junior year when I was taking AP Physics 1. You helped me pass the AP test with a 4. Because of that 4 I don’t have to take any science classes in college 😭. Thank you so much! I recommended your videos to my friends and my cousins who are currently taking physics. Hope the best for your channel man and will keep recommending your channel to all the crazy people I know who decide to enroll in a physics class😂🙏🏽.
This is my first time watching a video on your channel, sir, and I have to say, this is very commendable! You explain so well and I love the small skits. It makes it interactive, and your explanations are extremely detailed! Thank you sir!
hey Mr. P, you are the first physics channel I have watched where I learned and was entertained at the same time. I cannto express how much I enjoy these videos and how valuable they are to my understanding. You not only teach but also understand the common questions that we as students may encounter when hearing this for the first time. Thank you so much man!
Thank you so much! Super cool to see someone passionate about physics that also understands how to make an interesting video, Hopefully I graduate soon but ill never stop watching!
Sir your videos are really awesome and I am very blessed to learn from you. Sir a request from my side , sir can you please make videos on ray and wave optics. 🙂🙂
You guys are the best. Thank you so much. I have been trying and trying to figure out the situation with that d and r^2 trip in the equation.🤪 Thank you. Thank you so much for clarifying that. And also for brilliantly demonstrating why the electrostatic force is stronger than the gravitational force (even though that’s counter intuitive) You guys are so, so great . thank you 🙏
7:08 So mathematically if we want to observe a force at any point in a dipole due to both the charges .the negative sign of force (from -q(suppose)) will give us the direction of force (i.e. towards -q(attractive)) and while calculating the net force this sign wont have any meaning (like in algebra 2-6 = -4; here *minus sign* used for subtracting and we just have to add them vectorially?
The charge of 0.056N which from Q2 is acting on Q1, then how it's acting to the right? from Q1. Should you say acting from Q2 to Q1 since Q2 is the charge in questing that's attracting?
How is there a right arrow from charge 3 onto 1. i thought the arrow will be pointing on left ? Why ? Cause from what I heard from charge 2 onto 1 it points to the right cause charge 1 onto 2 has equal and opposite. Thank you.
Since F = kq(1)q(2)/r² And x² + y² = r² We can therefore conclude in the xy coordinate plane that F = kq(1)q(2)/x²+y² P.s. I know this is not true and that electric force probably has nothing to do with the polar coordinate concepts, but it's interesting how in math and physics, there are similar variables used which represents different things
In the exercise of the 3 charges, what if the charges are Q1(+) ----- Q2(-) ----- Q3 (+). Would have 2 attractive forces on Q2 : 0,0056 from Q1 to the right and 0,0056 from Q3 to the left. Now since Q1 and Q3 and equally charged, adhering to the law, these would repel each other, thus weakening the attractive forces Q1Q2 and Q2Q3. I would then assume you would have to divide the repulsive force between Q1Q3 by 2 and subtract that Force-value from the attractive force-value Q1Q2 and Q2Q3 to obtain the final (and correct) value's for Fq1q2 and Fq2q3. Correct ?
The fact that Q1 and Q3 both repel each other does not impact the force from Q1 on Q2, or the force from Q3 on Q2. At least, not at this snapshot in time. Given that Q1 and Q3 are identical and equidistant from Q2, the net electrical force on Q2 adds up to zero. Indeed, Q1 and Q3 do repel each other, and if free to move, would accelerate away from Q2 and the forces on Q2 would decrease in magnitude. Assuming they both accelerate away at the same rate (i.e. masses are identical as well as charges and no other forces are involved), they both will decrease in magnitude by the same amount after a given time. The force on Q2 would continue to add up to zero.
E=MC2 energy equals mass times the speed of light squared. But light has a rate of induction, not a speed… it’s only referring to the distance between two points. Also, Static electricity and gravity are one in the same thing. So is Force and Energy, and they are always equal. F=E. Gravitational Electrical and Magnetic forces are all Energy-Mass Equivalences. There is only one force in nature, and that is pressure mediation. Call it whatever you will. It’s doesn’t change anything…
Is the subtle implication that large mssses can overcome electrical charge? Is it that suppose Earth and Mars are both partially positive, are they attractive because of gravity while electric charge isn’t strong enough to repel them?
There is a charge/mass ratio where it is possible in theory for the gravitational force and the electrostatic force to both add up to zero on both objects, but it is rare you will ever encounter this. In fact, we can calculate just how many missing electrons the Earth and Mars would need for this to happen. Assuming the Earth and Mars had the same charge-to-mass ratio, and assuming both are positive, Earth would need a 3.22*10^33 missing electrons, and Mars would need 3.44*10^32 missing electrons, in order for the electric force to completely nullify the gravitational force between them. I don't know where you are getting your information that Earth or Mars is positively charged. The Earth excluding the atmosphere does have a net negative charge, but there is a positively charged atmosphere to accompany it. At the scale of astronomical bodies, electrostatic forces are close to negligible, and gravitational forces govern. At the scale of subatomic particles, the reverse is true.
your teaching is awesome and innovative........ a single doubt stucks in my head that "why the denominator is r(square) rather than r " , (square) is a 2 dimensional and (distance and radius) is one dimensional . every book there is r(square) but how and why r(square) is not there . please reply :) :) :)
Good question. It has to do with how the fields spread out in 3-dimensional space. Think of each charge as a source of electrical "spray paint", that it sprays in a spherically symmetric pattern. When second charge experiences this "spray paint", consider a spherical shell at the position of this second charge, where the "spray" stops. The force will be proportional to the density of this "spray paint" on the inner surface of this spherical shell. A spherical shell's area is proportional to the square of its radius. Hence, the density of the "spray paint" will be inversely proportional to the square of its radius, and so will the force it represents. In a more in-depth version of electrostatics, you learn about Gauss's law, and how Coulomb's law is a special case of it. There is a concept called electric flux, that is what that imagined "electrical spray paint" really is. Any closed surface has a total electric flux, that equals the net charge enclosed divided by the universal constant epsilon_0. This is the integral form of Gauss's law, which is related to the differential form, divergence of E = rho_e/epsilon_0. You see the k in Coulomb's law will get replaced with 1/(4*pi*epsilon_0), to show how it is a special case of Gauss's law, and you see that the 1/(4*pi) and 1/r^2, when put together, indicate that electrical force is inversely proportional
Sir please give me the link of your video on " electric field due to ring of charge " . there are many videos of diff* prof. On youtube , but your videos are really benefitial for me , i understand the topics. So easily with your videos as compare to others . 😢 And now i am too confused i could not understand this topic 😢 .. Help me !
My assumption is that you are looking for my video "Thin Ring Electric Field". You can find it on this webpage, along with a bunch more useful videos for you. www.flippingphysics.com/ap-physics-c.html#em
If more students knew how thorough and clear you explained things you would have millions of subscribers. You need to find a way to get yourself known to all those students left to fend for themselves in mediocre public education systems.
Just in time! I begin my units on Electricity and Magnetism tomorrow. Excellent video as always. Thank you so much for all of your efforts!
You are very welcome. I hope your students enjoy E&M!
Been 4 yrs bro , did you pass your course? Or almost
WTF this man is literally the best teacher ive ever met in any subject on anywhere. I actually understood it all without writing anything down!
Thanks, Bo.
how I wish my professors would teach physics this way. My life wouldn't be miserable
Same, I don’t understand a thing of what my teacher says, I guess that’s why people don’t go to his classes anymore, they’re so unorganized and not understandable XD
Omg! I got PTSD just watching this video 😖. I’m now a freshman in college and I remember watching your videos religiously junior year when I was taking AP Physics 1. You helped me pass the AP test with a 4. Because of that 4 I don’t have to take any science classes in college 😭. Thank you so much! I recommended your videos to my friends and my cousins who are currently taking physics. Hope the best for your channel man and will keep recommending your channel to all the crazy people I know who decide to enroll in a physics class😂🙏🏽.
Thank you for recommending my videos to my friends, however, it does make me a little sad that you no longer take any science classes. ☹️
You made it so simple to understand that a middle schooler would understand it too, respect
This is my first time watching a video on your channel, sir, and I have to say, this is very commendable! You explain so well and I love the small skits. It makes it interactive, and your explanations are extremely detailed! Thank you sir!
Welcome aboard!
hey Mr. P, you are the first physics channel I have watched where I learned and was entertained at the same time. I cannto express how much I enjoy these videos and how valuable they are to my understanding. You not only teach but also understand the common questions that we as students may encounter when hearing this for the first time. Thank you so much man!
You are absolutely welcome my friend!
I wish you're my physics teacher for real! Thank you!
New subscriber here~
Better than doing the full readings! Explains the confusion I had!
Our professor links your videos to our classes all the time! Super thankful for your videos!!!
Great! I am glad to help you learn.
i am from india .your video made my concepts stronger
Helpful for JEE Aspirants, Thank you
Agreed. The physics is the same in The United States and India!
My teacher doesn't teach us anything so i have to resort to TH-cam lol. Thanks dude, youre doing wonders for my grades.
Sorry. Glad to help!
THE WAY OF YOUR TEACHING IS INCRIDIBLY GOOD ! THANKS ALOT. SIR.
You are a great teacher!I always understand whatever u teach
That is wonderful!
Thank you so much! Super cool to see someone passionate about physics that also understands how to make an interesting video, Hopefully I graduate soon but ill never stop watching!
the best ever physics teacher i have ever seen hats off to you sir :)
Thanks!
Very helpful to solidify my understanding for my test tomorrow, thanks so much man!
Good luck on your test tomorrow!
I haven't seen prof/ teachers being mindful of explaining why we use micro coulomb in numericals. And now I know why we do.
YOU JUST SAVED MY GRADE 🙏
This is the second or third video of yours I've watched. They're always helpful and entertaining- I'm subscribed now! Thank you sir!
Welcome to my channel and best of luck with the studies!
I wish I had a physics teacher like dis🥺🥺
your teaching method is so unique and i loved every moment of the class.God bless you.
Thank you! 😃
Brilliant and entertaining. Thank you!!
I begin Calc-based Physics 2 next week! Thank you for this!
You are welcome. Best of luck!
Thank you so much, you do an incredible job. Keep up the great work. By the way you helped me pass the AP 1 test last year!
Wonderful!
REALLY ENJOYED YOUR VIDEO NEVER BEFORE WS PHYSICS THIS INTRIGUING
Glad you enjoyed it!
wow. came across your channel today and you do such a great job at explaining the material. thank you so much
Even though im in regular physics not AP is is very helpful! Thanks for saving my test grade lol
You made the concept so easy to grasp. Thankyou!
Glad it was helpful!
Love love love!! Well thought out and helpful. Thanks for these videos!
Thanks for the love!
Thank you so much. And I'm enjoying the video so much, it's not making me sleepy at all. Instead it's so funny and fun to watch.
Glad to keep you awake!
i like your teaching techniques its very interesting and i can easily understand
Great job.awesome teaching skills with entertaining.
Useful for jee aspirants.
Love from india🥰🥰
Thank you! 😃
i just learned so much more in this video Ahhhh thankssss!
You are welcome
Exceptional,,
I wonder I could also form three ,experts students for me during my exams 😄
Thanks for explaining I had a test on this. Life saver.
OMFG THEY LOOK JUST LIKE U!!! THATS CRAZZZZZZY!!!
Wow 😲 I benefited from this video. This has helped me
Your videos are so educative and entertaining! :)
I do my best!
Sir your videos are really awesome and I am very blessed to learn from you. Sir a request from my side
, sir can you please make videos on ray and wave optics. 🙂🙂
Today I first time your video wonderful video ❤❤
You guys are the best. Thank you so much. I have been trying and trying to figure out the situation with that d and r^2 trip in the equation.🤪 Thank you. Thank you so much for clarifying that. And also for brilliantly demonstrating why the electrostatic force is stronger than the gravitational force (even though that’s counter intuitive)
You guys are so, so great . thank you 🙏
I am very glad to have helped you learn!
I cant believe. Explanation is awesome. But why there is less views? Great man . Pls dont stop making videos.
Hopefully I will never have to stop making videos. Oh, and I hope I'll get more views eventually. 😇
@@FlippingPhysics pls continue doing video tutorials, it really especially this time of pandemic. Ty
new subscriber
brilliant explanation , congratulation great job continue
So nice and educative sir
Thanks, you never fail to not bore me even for a single second, with bob,billy and bow🌈🌈
Thanks!
extremely entertaining and educational, thanks
You are very welcome!
Your videos are so interesting
I clicked on this video because of your awesome hair and I learned a lot too.
Amazing easily explained tnx 🎉🎉
I love your videos! I hope you have more for when I get to uni for engineering lol
your teaching technique is best
Glad you think so!
Sir your method of teaching is very nice.
Studying EE and I'm back to this video to refresh on Coulomb's Law for my electromagnetics class haha thank you so much!
Good to have you back!!
7:08 So mathematically if we want to observe a force at any point in a dipole due to both the charges .the negative sign of force (from -q(suppose)) will give us the direction of force (i.e. towards -q(attractive)) and while calculating the net force this sign wont have any meaning (like in algebra 2-6 = -4; here *minus sign* used for subtracting and we just have to add them vectorially?
I love the way you teach!
I like the way you're teaching😂💙💙
thank you so much i have a end of term in a few mins
Thank you!! Sending Love from the Philippines
This is very well explained, I can't thank you enough but thank you
You're very welcome!
Awesome video. Thanks
Dang, what a great video, I wish I could just watch these videos instead of attending my physics class. Thanks!
Glad to help you learn!
You're videos are the best!
Thanks!
What do electrons say when they move?? Charge!!! :) btw the vid was awesome u were So Charged!!!!! ;)))
Ha Ha Ha.
The charge of 0.056N which from Q2 is acting on Q1, then how it's acting to the right? from Q1. Should you say acting from Q2 to Q1 since Q2 is the charge in questing that's attracting?
Hey how will I going to solve for electric force if the distance is in C and not a meter thank you!
How is there a right arrow from charge 3 onto 1. i thought the arrow will be pointing on left ? Why ? Cause from what I heard from charge 2 onto 1 it points to the right cause charge 1 onto 2 has equal and opposite. Thank you.
Thanks i missed a session in class today
Since
F = kq(1)q(2)/r²
And x² + y² = r²
We can therefore conclude in the xy coordinate plane that
F = kq(1)q(2)/x²+y²
P.s.
I know this is not true and that electric force probably has nothing to do with the polar coordinate concepts, but it's interesting how in math and physics, there are similar variables used which represents different things
And very frustrating at times.
@@FlippingPhysics oh yeah definitely if ur dealing with them in the same field
is this Leonard from big bang
yes
Sir.. if q3 was negative and q2 positive.. is net force -0.11N.. towards left
IMMA NEED YOU TO DO A CALCPHYSICS 2 PLAYLIST PLEASE
In the exercise of the 3 charges, what if the charges are Q1(+) ----- Q2(-) ----- Q3 (+). Would have 2 attractive forces on Q2 : 0,0056 from Q1 to the right and 0,0056 from Q3 to the left. Now since Q1 and Q3 and equally charged, adhering to the law, these would repel each other, thus weakening the attractive forces Q1Q2 and Q2Q3. I would then assume you would have to divide the repulsive force between Q1Q3 by 2 and subtract that Force-value from the attractive force-value Q1Q2 and Q2Q3 to obtain the final (and correct) value's for Fq1q2 and Fq2q3. Correct ?
The fact that Q1 and Q3 both repel each other does not impact the force from Q1 on Q2, or the force from Q3 on Q2. At least, not at this snapshot in time. Given that Q1 and Q3 are identical and equidistant from Q2, the net electrical force on Q2 adds up to zero.
Indeed, Q1 and Q3 do repel each other, and if free to move, would accelerate away from Q2 and the forces on Q2 would decrease in magnitude. Assuming they both accelerate away at the same rate (i.e. masses are identical as well as charges and no other forces are involved), they both will decrease in magnitude by the same amount after a given time. The force on Q2 would continue to add up to zero.
I hate physics but you kinda make me enjoy it
I consider that a win.
Great video
Epic! At 1:31 .
E=MC2 energy equals mass times the speed of light squared. But light has a rate of induction, not a speed… it’s only referring to the distance between two points. Also, Static electricity and gravity are one in the same thing. So is Force and Energy, and they are always equal. F=E. Gravitational Electrical and Magnetic forces are all Energy-Mass Equivalences. There is only one force in nature, and that is pressure mediation. Call it whatever you will. It’s doesn’t change anything…
Our textbook uses the unit vector form but with a negative sign making negative forces repulsive and attractive forces positive.
In my experience calculus-based physics uses that vector form of the equation, and algebra-based physics uses this scalar form.
Flipping Physics I forgot to mention I was in AP Physics C : Electricity and magnetism (did AP Physics C Mechanics last year in junior year) :)
Yo bobby's my favorite he's a chad
Really good!
Would you say these videos are sufficient enough to self-study the concepts for e&m? Im trying to possibly self-study this for fun lol
Absolutely. I would use this list of videos: www.flippingphysics.com/ap-physics-c-em.html
Wowwwwww wht a way of teaching
Thanks!
Is the subtle implication that large mssses can overcome electrical charge?
Is it that suppose Earth and Mars are both partially positive, are they attractive because of gravity while electric charge isn’t strong enough to repel them?
There is a charge/mass ratio where it is possible in theory for the gravitational force and the electrostatic force to both add up to zero on both objects, but it is rare you will ever encounter this. In fact, we can calculate just how many missing electrons the Earth and Mars would need for this to happen. Assuming the Earth and Mars had the same charge-to-mass ratio, and assuming both are positive, Earth would need a 3.22*10^33 missing electrons, and Mars would need 3.44*10^32 missing electrons, in order for the electric force to completely nullify the gravitational force between them.
I don't know where you are getting your information that Earth or Mars is positively charged. The Earth excluding the atmosphere does have a net negative charge, but there is a positively charged atmosphere to accompany it. At the scale of astronomical bodies, electrostatic forces are close to negligible, and gravitational forces govern. At the scale of subatomic particles, the reverse is true.
@@carultch it’s hypothetical
I never intended to insinuate that the earth is positive
Why is there a 12 and a 21 as subcripts to F vectors in Newton's 3rd Law Force Pairs?
Please see: www.flippingphysics.com/third-law.html
thank you so much, sir
your teaching is awesome and innovative........ a single doubt stucks in my head that "why the denominator is r(square) rather than r " , (square) is a 2 dimensional and (distance and radius) is one dimensional . every book there is r(square) but how and why r(square) is not there . please reply :) :) :)
Good question. It has to do with how the fields spread out in 3-dimensional space. Think of each charge as a source of electrical "spray paint", that it sprays in a spherically symmetric pattern. When second charge experiences this "spray paint", consider a spherical shell at the position of this second charge, where the "spray" stops. The force will be proportional to the density of this "spray paint" on the inner surface of this spherical shell. A spherical shell's area is proportional to the square of its radius. Hence, the density of the "spray paint" will be inversely proportional to the square of its radius, and so will the force it represents.
In a more in-depth version of electrostatics, you learn about Gauss's law, and how Coulomb's law is a special case of it. There is a concept called electric flux, that is what that imagined "electrical spray paint" really is. Any closed surface has a total electric flux, that equals the net charge enclosed divided by the universal constant epsilon_0. This is the integral form of Gauss's law, which is related to the differential form, divergence of E = rho_e/epsilon_0. You see the k in Coulomb's law will get replaced with 1/(4*pi*epsilon_0), to show how it is a special case of Gauss's law, and you see that the 1/(4*pi) and 1/r^2, when put together, indicate that electrical force is inversely proportional
thanks
micro means 10 raised to -6 so it must be +/-5 x 10^-6
I have a problem with some phrases, which is "I don't mind, go ahead".
Electrifying!
nice
Sir please give me the link of your video on " electric field due to ring of charge " . there are many videos of diff* prof. On youtube , but your videos are really benefitial for me , i understand the topics. So easily with your videos as compare to others . 😢 And now i am too confused i could not understand this topic 😢 .. Help me !
My assumption is that you are looking for my video "Thin Ring Electric Field".
You can find it on this webpage, along with a bunch more useful videos for you.
www.flippingphysics.com/ap-physics-c.html#em
@@FlippingPhysics thank you sooo much sir ☺️
I didn't get the answer in second question after determining the electric force
Saving lives fr
I thought you get 1coulomb by 6 x 10 to the 18th power
If more students knew how thorough and clear you explained things you would have millions of subscribers. You need to find a way to get yourself known to all those students left to fend for themselves in mediocre public education systems.
I try. It's not an easy task.
awesome
If I could just be as smart as these 3 guys in my class lol
I think we all feel that way.
I clicked because I saw Leonard from big bang theory
رائع جدا
شكر!