Control Systems (EBB 320): Solving for an exact point on a Root locus, by hand.
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- เผยแพร่เมื่อ 11 พ.ย. 2015
- A short tutorial showing you how to use your Casio fx-99ES PLUS to solve for the exact point on a root locus for problem 9.22 in the Norman S. Nise Textbook. This intern lets you solve for the gain needed for the system
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Howzit, I realised I made a mistake solving for the gain in the first part, I typed +15 in my calculator instead of +12 This with the fact that I made my sigma positive gave me a way off answer.
The gain should have been is 248.68. Sorry for the mistake.
keep working, nice
omg i have been doing this by hand for the past 6 years. this video changed my life lol
Nice video! Came here from Brian Douglas' root locus videos. Highly appreciate this.
This man has a moerse strong "howzit"! I can respect that.
You saved 1 question of my paper.👍👍
thank you, man . You're so great !
Greetings from the University of Pretoria, student of Prof. I.K Craig. EBB 320 :-)
Nice video by the way.
Glad the video helped.
Thank you very much for the video, it did help a lot :)
Thank you very much, you saved my life 🌺 I might get an A in control system cuz of your help
I'm really glad I could help!
Excelent explication! Very Thanks!
Thank you, nice work
thank you you made my day!
Man, thank you life saver
can you please tell me how to get the value of sigma and omega if complex poles are also included?
Thanks for the vid :)
Perfect!
Nice Effort Sir, What will be When we have a poles in our question? kindly make a video of that as well
THANKS
Video starts "Howzit".. my immediate thought "this guy is from South Africa" hahaha
What song is this?
+JP Stardom darude - sandstorm
For the third angle (theta p3) can't you simply take 180-69=111 degrees? I think you solved it correctly but you drew the theta lying in the 69 degrees sharp angle instead of it going from zero degrees on the x-axis to 111 degrees. Thanks for the video it is quite relieving!
+Nelis Brink You definitely can, but this only works for when you have a pole at the origin. But with that said if you have 5 poles, with one being at the origin, your calculator will pull amps to solve that, so if you can simplify its life by saying one of the angles will be 111 degrees, it will speed up the computational time greatly.
Ewald Erasmus what if there is any zeros the procedure is same for that ?
Ali Omer: I can't exactly remember if it's the same but I have a feeling it is. Sorry this was fromany years ago and I can't remember it all.
Ewald Erasmus I tried this method is not correct when there is a zero in system so then how can we solve the problem as we have to find compensated zero in every problem , how we can find a point and k
pls try to do this one
wrong method why positive angle for poles? your method works for onlly those case where net angle 180(2k+1) and angle of pole on the right side of root locus is zero
Muhammad Saad Tariq you will see I explain that it should be negative. But it makes no difference because all of them are negative. You can include the signs if you want and you will get the same answer
I dont get what he is calculating for the third angle, shouldn't its value just be 69??
well