Amazing explanation❤. You didn't just throw equation and started bullshit talk like other TH-camr, rather you explained it in logical and beautiful way so that even before exam students can understand easily (Edit :- plz cover more topic like Bode plot, Nyquist Plot, Etc. i have exam in 4 days 😢😅)
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Hello Sir, I am stuck at a mcq question with the same transfer function. The characteristic equation of a closed - loop system is Which of the following statements is true? Options: 1. It's roots are always real. 2. It cannot have a breakaway point in the range -1
Pay Attention!! In such types of questions you have to go through each option to check the validity. Option-1: You have to simply solve the characteristics equation and find the multiple values of "s". If any values are not complex poles then it will be true. Option-2: Just locate the poles on the real axis and check for the existence of the root locus, you will get the idea whether breakaway point is required or not and if required then between which poles it shall exist. Option-3: Number of roots located at infinity directly depends on availability of poles/zeros in the question. You can find it using the following expression; *Number of roots located at infinity = (Number of poles - Number of zeros) Option-4: Just go through the same process as in option-1 i.e. find the values of poles and then plot on the s-plane it will be clear whether there is complex poles exits or not. If there are further doubts, just let me know! Stay connected! Enjoy the learning😊
@@triple.e.sudhanshu Thank you for the reply sir, I still have one doubt though. The Characteristic Equation will be 1+G(s)H(s)=0, correct? so to solve it what should be the value of k that I should choose?
@@cypherop7287 In this case, the whole graph of root locus is depicted towards the LHS of s-plane, it's already a stable system. If the root locus crosses the imaginary axis and goes towards the RHS of the s-plane then system becomes unstable and to find the range of unstablity you need to apply RH criteria.
@@mr.umerworld5402 Firstly, you have to find the characteristic equation and derive the function of 'K' subsequently differentiate the function with respect to "s" and then solve the polynomials. You will get multiple values of "s" then select the proper value according to the question as a break away point.
sir how can you confirm the direction of arrow of locus originating from pole at -1 goes toward right side and locus starting from pole at zero goes toward left side, why cant it be the opposite plz clarify ?
Pay attention!! 1. As per the root locus property, locus exists on the real axis on the left side of individual pole/zero if the total number of poles & zeros are odd in s-plane on the right side of that individual pole/zero. 2. Further, the other property of RL is that all the locus emanates from poles and terminates at zeros. Now, as per your doubt in this question the locus exists between 0 & -1 that & both are poles which means locus will start from poles. Therefore locus will start from -1 towards the origin and other locus will start from origin towards the -1 subsequently they will collide at some particular point and that point is calculated as BREAK-AWAY POINT in order to understand the bifurcation of locus on the s-plane.
The locus has the property that whatever shape it will take at an emanating point, same shall be followed up to the infinity. In this question, the locus is bent towards the left side of the s-plane in alignment with asymptotes so it will never cross the imaginary axis and it will follow the 90° upward up to infinity.
Amazing explanation❤. You didn't just throw equation and started bullshit talk like other TH-camr, rather you explained it in logical and beautiful way so that even before exam students can understand easily
(Edit :- plz cover more topic like Bode plot, Nyquist Plot, Etc. i have exam in 4 days 😢😅)
@@rockingediting652 Thanks a million for such a wonderful observation & your kind gesture ❤️
And I will try to upload the videos asap!
Thanks sir aj mara paper ha or ap ke video dakh kar sari smj a gayi impressive love from pakistan
Bhut bahut dhanyawad bhaiya ji ....ye topic mere liye bahut tough tha lekin aap to ese bahut hii ashan kr diye hai ❤❤❤
Kya sikhaya hai bhaiya, proper concept , to the point, clarity wahhh 🔥
Shukriya😊
This topic is so tough for me before,but the way you covered each small point clearly,it helps a lot.. thanks sir, ✨
Thank you sir❤
All the visitors are requested to SUBSCRIBE the channel to get the contents on time!!!
👉Your small act of taking subscription will increase the frequency of uploading contents.
👉All the contents related to the subjects shall be uploaded including easy, moderate and difficult numerical solutions in easiest way.
😊I'm glad that you like the content, stay connected, enjoy the learning, have blast in the exams and drop your doubts in the comment box.
This is such an amazing explanation.It is such a complicated topic that you made so easy sir.
Thank you dear❤️🙏
WAAH... BHUT BHUT DHANYAWAD BHAIYA.
What a clear explanation and Knowledge 👏👏
Subscribed!!!
thank you✨
Thank u sir, ....One of the best professor 💥
@@horjeet8704 ❤️
Very nice teaching... Please continue
thank you!
bhaiyaa you are a saver for me in exam time..😍🙌
@@all.abt.shivangiii That means a lot to me 😊
Hello Sir,
I am stuck at a mcq question with the same transfer function.
The characteristic equation of a closed - loop system is
Which of the following statements is true?
Options:
1. It's roots are always real.
2. It cannot have a breakaway point in the range -1
Pay Attention!!
In such types of questions you have to go through each option to check the validity.
Option-1: You have to simply solve the characteristics equation and find the multiple values of "s". If any values are not complex poles then it will be true.
Option-2: Just locate the poles on the real axis and check for the existence of the root locus, you will get the idea whether breakaway point is required or not and if required then between which poles it shall exist.
Option-3: Number of roots located at infinity directly depends on availability of poles/zeros in the question.
You can find it using the following expression;
*Number of roots located at infinity = (Number of poles - Number of zeros)
Option-4: Just go through the same process as in option-1 i.e. find the values of poles and then plot on the s-plane it will be clear whether there is complex poles exits or not.
If there are further doubts, just let me know!
Stay connected!
Enjoy the learning😊
@@triple.e.sudhanshu Thank you for the reply sir, I still have one doubt though. The Characteristic Equation will be 1+G(s)H(s)=0, correct? so to solve it what should be the value of k that I should choose?
@@Makarov-- Solve the numerator and denominator independently you will get the values of zeros and poles respectively without considering 'K'.
Thank you so much sir for this super beautiful lecture❤❤❤❤❤❤❤❤❤❤❤
❤️
very well explained....
bro you deserve so much followers, how come are you so underrated💔🙏🏻
Very nice explanation ❤
😊
what will be the stability of the system? how can we determine the stability? do we have to use RH array to find stability?
@@cypherop7287 In this case, the whole graph of root locus is depicted towards the LHS of s-plane, it's already a stable system. If the root locus crosses the imaginary axis and goes towards the RHS of the s-plane then system becomes unstable and to find the range of unstablity you need to apply RH criteria.
Bhaii aap yrr bhagwan se kamm nhi ho
....bhott bhott dhanyawad 😭😭
Shukriya bhai ❤️ such a kind words...lekin mai bhagwan nhi hu mujhe insan hi rehne do 😅🙏
sahi bat he rishi bhai
@@RajGupta-yx4yw 😂😂hn bro
Good explanation
@@Manzoorbaloch-s5q Thank you!
sir where is the video for root locus rules i am unable to find it
@@DamanS-vn8ov It has been deleted due to some issues, will be re uploaded.
Nice explanation sir.
Thank you! Niraj😊
Neso Academy ❌
Triple E Sudhanshu ✅
@@nutcase7541 Unexpected 😳🥹🥹🙏
Thnx bahut acha apne samjhaya
Thank you sir ❤❤❤
Very nice sir thank u 🎉
Sir ye break point apny direct kesy polynomial bna dia plz tell
@@mr.umerworld5402 Firstly, you have to find the characteristic equation and derive the function of 'K' subsequently differentiate the function with respect to "s" and then solve the polynomials. You will get multiple values of "s" then select the proper value according to the question as a break away point.
Where is 11 rules vedio Please provide link It will very helpful
@@amazingfacts-uv4kf Due to some reason the video was deleted it will be uploaded back asap
Sir baki ke videos nahi mil rahe like root locus property wala jo aap Chanel pe check karne ko bole?
Ha kuchh issue tha usme delete krna pda use...i will re-upload that video.
Hnn jaldi kariye parso exam hei
Rh wale ka bhi kuch kariye sir
whatsapp me i will teach uh for your exams....until i start uploading the contents
Thankyou sir.. very well explained sir 👏
sir how can you confirm the direction of arrow of locus originating from pole at -1 goes toward right side and locus starting from pole at zero goes toward left side, why cant it be the opposite plz clarify ?
Pay attention!!
1. As per the root locus property, locus exists on the real axis on the left side of individual pole/zero if the total number of poles & zeros are odd in s-plane on the right side of that individual pole/zero.
2. Further, the other property of RL is that all the locus emanates from poles and terminates at zeros.
Now, as per your doubt in this question the locus exists between 0 & -1 that & both are poles which means locus will start from poles. Therefore locus will start from -1 towards the origin and other locus will start from origin towards the -1 subsequently they will collide at some particular point and that point is calculated as BREAK-AWAY POINT in order to understand the bifurcation of locus on the s-plane.
crossover on imaginary axis is
not calculated why please explain sir
The locus has the property that whatever shape it will take at an emanating point, same shall be followed up to the infinity. In this question, the locus is bent towards the left side of the s-plane in alignment with asymptotes so it will never cross the imaginary axis and it will follow the 90° upward up to infinity.
Perfect 😭😭😭😭❤️❤️❤️❤️❤️ mashallah 💖💖💖
Sir S1 , S2 , S3 ke values kase liya pls bata dijiye 17:07
s=1=0 karo to s=--1 aa jaega
Can you please make videos on Bode Plot( Linear Control Systems)?
I will cover each and everything...stay connected 😊
Sir parso exam hei bode plot aur polar plot ka bhi thoda dijiye sir
Sir Bode plot ka lecture upload kijye
On 9th it will be uploaded.
Sir , root locus ke rules wala video ni milra apka ... share it please in comment
Actually, I deleted that video due to some issue but soon I will upload again!
Nice explanation
Bagar calculator ka s ka values kasy find kry kasy solve hoga
Sure! I will make a separate video for this.
Check the latest video!
Maine is par video upload kr diya hai
20:31 pe thetha 2 straight kese hoga 270 degree hain na?
Measure 270 degree anticlockwise you will get the angle!
GOAT🗿🗿
@@ayushgupta22 💚🙏
sir i am getting 2s^3+10s^2+16s+6
should i divide by 2.....
Rules wali video lectures??
Allow me 2 days!
1 + G(s)H(s) = 0 and then K ka value kese nikala hai ? Pls help
In which part? Mention the time of the video please
14:28
Hr kisi video m angle of departure (180 - fi) h or angle of arrival (180 +fi)... LekinApne dono ka formula( 180 - fi) likha h ...kyu😅???
There is no calculation of angle of departure/arrival in this question😅
I love you
😅🙏