I think after the removal of H2O from the oxonium ion so formed, O from the initial ring coordinates lone pair to the 1° carbocation then forming a six membered ring. But for that 1° carbocation needs to be formed and the product I said has peroxy linkage which is very unstable.
Can someone please help me? If I were to get the cyclic acetal structure formed after I did the protection group reaction, what would KMnO4 do to the cyclic acetal? Will it break it to for two carboxylic acids or not react with the cyclic acetal group?
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You can remember this as the PAD-PEAD(protonation,elimination,addition,deprotonation) mechanism.
Thank you so much! This made it so much easier to remember
I wonder why my O chem professor never covered this? This is all over the MCAT and DAT thanks man!
Hey, is there a great mcat practice book you recommend? I'm taking it next year
@@Michelle-rv9ns Kaplan is pretty solid
my ochem professor covering it and it goes hands in hand with my MCAT studying!!!
The Villian studying ochem??? Incredible
we have in 12the class😂😂
It was really nice... Love from India ❤
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JEE peeps take note, this question came in Mains 2021.
Thanks bhai
Thanks buddy❤
Ok bro
Hey your vids for algebra got me a 100% on a test thank you!
At 6:00 didn't you form a ketal and not an acetal since you started with a ketone?
Conventionally, all acetals and ketals are called as acetals right now
@@taylorteehungpiao4814 dude thank you
5:43 why didn't you use the water to deprotonate turning it into h3o+, is this feasible in this type of reaction?
5:21 why do we need to form the carbonyl again, why can't we just react it with CH3-OH and the OH2 leaves?
9:37 could the acid remove the alcohol, leaving water, instead of remove the protecting group?
You would get an unstable primary carbocation, so I don't think that would happen
I think after the removal of H2O from the oxonium ion so formed, O from the initial ring coordinates lone pair to the 1° carbocation then forming a six membered ring. But for that 1° carbocation needs to be formed and the product I said has peroxy linkage which is very unstable.
Protecting group 7:23
Ma'am u r great ❤❤
So helpful, thank you
To be honest, you were only saying what you were drawing, nothing was really explained to my understanding. I prefer other of your videos to this.
hi do you mind putting your carbohydrate video back up ? I was watching it and now it says its deleted.
Can someone please help me? If I were to get the cyclic acetal structure formed after I did the protection group reaction, what would KMnO4 do to the cyclic acetal? Will it break it to for two carboxylic acids or not react with the cyclic acetal group?
lol the same question from 7:24 came in my test
Man, I don't know how you do this but damn...smh. Thank you
Hi, Please can you tell the programm do you use for drawing the molecules and chemistry reactions .. thank you so much in advance
bruh that stuff could be literally done on mspaint
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At 1:40, isn't it Ketal instead of Acetal? bc your staring product is a cyclic ketone?
It is a Ketal. May be he thought the structure was an aldehyde
It's there a protecting group site?
wow thanks for the video
Thank you once again.
Why is acetone not good at protecting a 1,3-diol but is good at protecting a 1,2-diol?
Idk man
It is what it is I guess
Thank you!!!
Good video
Good man
Nice
🥰
still useful but you were really better than this. too fast!!!