This guy he is a genius he has helped me to understand in all my natural sciences and mathematics. I don't have enough words for him but all I can say is that may God continue blessing with whatever you need in your life. You have helped me personally through out my university life for 4years. Last but not the least please don't stop with what you do continue to help the future generation 💪🙏🙏❤
great video! just some advice- keep the picture of the final product up for a few seconds longer- i can’t pause the video fast enough to see the product alone
Cette vidéo m'a rendu moins bête 😀, merci beaucoup Monsieur.L'anglais est vraiment très important pour la poursuite des études supérieures, dommage pour moi car je ne comprends pas...( BABOKA, DEPUIS LE CAMEROUN)
You are the best.... I want to be like you... Since my year 1 I have been using year video... Now I am a chemistry Tutor I am still watching your videos.. for proper explanation.. Thanks alot
Can't thank you enough man! I was facing doubts in grignard reagent and this cleared everything! And a quick question. For the compound in 9:45 won't a ring expansion be more favourable before the addition of the -R group?
this is an SNAE mechanism! rearrangement is only possible when a carbocation is formed. this reaction involves carbanion nucleophile and no carbocations are formed, so no rearrangements
How do you know what side to put your reagent on? I keep thinking that you could choose either or because you’ll still end up with the same answer..? 08:26 I’ve seen others put their reagents on the aldehyde side and they’ve gotten it the answer right.
At 3:35, if we had to name this structure would be it be (A) 1-ethyl cyclohexanol or (B) 1-ethyl cyclopentanol? If its (B), why? when counting the longest chain starting with the ethyl group
So, the Ch3Ch2, we use it twice because we need the oxygen to be negative in order for it to do the proton transfer of hydronium? So it can be an alcohol?
Had to go to this video after seeing a legendary meme about the reagent. Who would've guessed a well edited clip of black'n'white daffy duck would be so funny?
When carbon is attached to a more electronegative atom like O of N ..the more electronegative atom attracts the shared pair of electrons from the electron cloud towards itself ..so it develops partial negative charge.
no nvm, 1 eq of grignard means the reactant is aldehyde or ketone, but the products will always be alcohols for the girgnard reagent. 2 eq of grignard means reactant is ester or acid chloride and the product will be an alcohol with 2 R groups. For 1 eq of grignard that reacts with either aldehyde or ketone, product will also be alcohol but with only 1 R group
The MgBr is actually attached to the O- that was broken but it is not shown in the video. When an acid or hydronium is added than this attacks the MgBr bond and replaces it with a hydrogen thus giving an OH group. Your byproduct would then be a OHMgBr or ClMgBr depending on what you used to remove that MgBr group from the O- group.
Yes. The mechanisms is the same for every reactant. This is the beauty of organic chemistry. Once you learn the mechanisms, if you are given a new molecule, the mechanisms will always be the same.
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tnx
The word "thank you" is not enough for your efforts! It helps us a lot! Love from Tamilnadu,India❣
Sis I'm also from Tamilnadu
@@thangam5006 🙌
You are right, This video is helpful... And I'm also from Tamilnadu...
@@ganeshsriram4941 :)
I'm not from Tamil Nadu but I'm from India
This vidéos are so well explained, and help a lot to understand more easily the dark side of organic chemestry, so i need to say : Big thanks!
This guy he is a genius he has helped me to understand in all my natural sciences and mathematics. I don't have enough words for him but all I can say is that may God continue blessing with whatever you need in your life. You have helped me personally through out my university life for 4years. Last but not the least please don't stop with what you do continue to help the future generation 💪🙏🙏❤
From zambia
Thank you for all your videos, I passed both organic chemistry courses with good grades because of you
Teacher nehi padhate the kya😕
@@theobanai tujhe teacher nehi padhate? Tu yaha kya kar raha hae ghochu?
I needed this so bad last semester, thanks for making it now anyway.
Hope you're making millions by now my dude
hope he does....he deserves it totally
So basically, since feb. 2020, you've been my instructor. And THANK YOU SO MUCH.
This video jusy came in really clutch for my 1st orgo 2 exam. Really preciate ypur vidoes they helped me through physics too
you are the reason i do well in my exams and tests
great video! just some advice- keep the picture of the final product up for a few seconds longer- i can’t pause the video fast enough to see the product alone
Cette vidéo m'a rendu moins bête 😀, merci beaucoup Monsieur.L'anglais est vraiment très important pour la poursuite des études supérieures, dommage pour moi car je ne comprends pas...( BABOKA, DEPUIS LE CAMEROUN)
you made me fall in love with chemistry through your videos
You are the best.... I want to be like you... Since my year 1 I have been using year video... Now I am a chemistry Tutor I am still watching your videos.. for proper explanation..
Thanks alot
you deserve an award of some kind. you are the reason I'm passing my final in 2 hours :)
😂
Thanks from Tamilnadu India 😍😀
4:28 Why magnesium will insert the carbon atom?
4:14 how can you make it Grignard reagent without dry ether
mann..... i wish could hire u privetely as my chemistry olympic mentor
@7:03 Why didn't O get protonated at this moment? Why did it kick the OCH3 out instead?
You are the best tutor!!!
Thank you for making me understand the addition of 2 R-groups.
thankyou for this video! You have selected the best questions and the right amount of questions for this topic! I really appreciate it!
Thank you for your video 🙏🏽 it is really helping me following from Kenya
My man's carrying my entire organic department staff
Thank you sir... you are a life saver... wallah
you are the most intelligent teacher i ever know !! thanks
first time i feel like im understanding ochem!!! thank u so much! :)
thaank you so so much
you are brilliant and your teaching style is amazing
9:28 are there supposed to be that many carbons attached to the grignard reagent?
Surely a nice video with good explanation and high order jee leve questions
wdym
Thanks sir !!!!
Great love from INDIA.
You really help me often!!
At 7:14 why didn't the O¯ get protonated and turned into an alcohol instead?
You are a saving grace! Thank you so much
nice bhai
Thanks man these are really great to watch
Thank you very much I am from Iraq and you help me by this lessons
Thank you so much sir 💖from TN(India)
Thanks alot. Now wherever I see RMgX I won't make mistakes.
Highest grade on my O Chem 1 final. High A in the class. Gracias.
Can't thank you enough man! I was facing doubts in grignard reagent and this cleared everything!
And a quick question. For the compound in 9:45 won't a ring expansion be more favourable before the addition of the -R group?
this is an SNAE mechanism! rearrangement is only possible when a carbocation is formed. this reaction involves carbanion nucleophile and no carbocations are formed, so no rearrangements
A big „thank you“ from Germany 😇👌🏽
Thanku sir ..I had confusion in this part
Thanks! Cleared my concept very well!
Great explanation!
Thankyou , your deep explanation is attached to show more than one video and you are show everything in rxn ,what I to do.
India (Hindi)
excellent video my man. keep up the great work
At 12:18 I believe this is an epoxide ring opening under basic conditions so the OH lands on the more substituted atom, please correct me if I’m wrong
6:53 how do I know something is a good leaving group?
the less basicity one group is ,the better it acts as a leaving group
The more stable the leaving group is as an individual the better the leaving group
(in the case of CH3O- the negative charge is on oxygen which is highly electronegative and hence the molecule is stable)
Which is individually stable that is gud leaving group
Thank you so much for solving my problem ❤
How do you know what side to put your reagent on? I keep thinking that you could choose either or because you’ll still end up with the same answer..? 08:26 I’ve seen others put their reagents on the aldehyde side and they’ve gotten it the answer right.
thanks for your teaching!!
At 3:35, if we had to name this structure would be it be (A) 1-ethyl cyclohexanol or (B) 1-ethyl cyclopentanol? If its (B), why? when counting the longest chain starting with the ethyl group
Am so proud of you
Awesome vid, can't say it enough.I smacked that sub button
Doesnt it matter that you change the position of the CH3 Group in the first example?
So, the Ch3Ch2, we use it twice because we need the oxygen to be negative in order for it to do the proton transfer of hydronium? So it can be an alcohol?
Love from Bangladesh 😘.
example 4 at 7:34 why are there 2 ch2ch3 to react with??
Appreciate you Mr.💯
Best explanation ❤
JEE 2025 attendance here ❤
This better than my teacher
Thank you once again.
is attack by GR always SN2? is there a possibility of rearrangement or ring expansion?
That's really some morrison boyd lvl shit mann!! ❤❤❤
You're such a gem
At 4:49 was in the carbon partial -?
No
Any one know the program he using in explication ?
Anyone prep for iit jee 2024
Neet 2024 here
Csir here ❤🎉
how did it go ?
Iit 2025 name L.Aditya
@@lakshmananiyeraruna738PW sa Aya hai ra sir ka lecture ka baad
Omg Thank you!!! This helped a lot
thanks for all your videos
Buonara really got me
thank you sir☺
A very useful video, thanks!
thank you so much for this video! your explanation made everything easy to understand
Great session
3:30 wouldn't the ring expand to form a six-membered ring?
no it wont since ring expand to attain stability but here it doesnt matter
@@shouryasrivastava5966 umm... aren't the products that are more stable are more likely to form?
@@ritikshukla1788 negative charge is at oxygen so ring wont expand
@@shouryasrivastava5966 i guess i need to look more into the ring exapnsions...thanks btw
Thank you for your help!
Thank you very much.. This is what I need now
Denhxv82 5 run to take 8 hours and turn
Had to go to this video after seeing a legendary meme about the reagent.
Who would've guessed a well edited clip of black'n'white daffy duck would be so funny?
could you please make a discussion about Reaction of Grignard Reagents with Epoxides
thank you
We really appreciate for your help
Why is at times the h30+ is written under the arrow and other times it isnt even though its still used
Great video!
Thank you kind sir!
How do you know of the Carbon is partially positive or negative?
When carbon is attached to a more electronegative atom like O of N ..the more electronegative atom attracts the shared pair of electrons from the electron cloud towards itself ..so it develops partial negative charge.
if there is not indication that there are 2 equivalents of grignard reagent then will the product be ketone?
would be aldehyde with only 1 equivalent of grignard
no nvm, 1 eq of grignard means the reactant is aldehyde or ketone, but the products will always be alcohols for the girgnard reagent. 2 eq of grignard means reactant is ester or acid chloride and the product will be an alcohol with 2 R groups. For 1 eq of grignard that reacts with either aldehyde or ketone, product will also be alcohol but with only 1 R group
This videos is more usfull to us
thank you
Just realised this guy's comments section is filled not just with a single country ppl
3:40
Very efficient!
What I really want to know though is what happens to the Mg2+ and the Br- and also the H2O? 🤔😩
The MgBr is actually attached to the O- that was broken but it is not shown in the video. When an acid or hydronium is added than this attacks the MgBr bond and replaces it with a hydrogen thus giving an OH group. Your byproduct would then be a OHMgBr or ClMgBr depending on what you used to remove that MgBr group from the O- group.
Helped me a lot thanks
great explanation!!!!
Im learning from these this one just seemed like you were going kind of fast.
Love from india
where did we get the 2 carbons to add to the 4 carbon chain on the last problem?
What if you created a grignard reagent with bromobenzene and magnesium, then bubbled carbon monoxide through the solution?
Is this how Girgnard reagents always react? With every other reactant? ?
Yes. The mechanisms is the same for every reactant. This is the beauty of organic chemistry. Once you learn the mechanisms, if you are given a new molecule, the mechanisms will always be the same.
so basically grignard agent perform nucleophilic substitution ? i'm new to this i ain't getting things fast
It's technically a base which would abstract an acidic hydrogen if any. If there are no acidic hydrogens, it undergoes substitution
how to move from R-CO2H to R-CH2-CO2H.....plz help me
Erndt ester synthesis.