Grignard Reagent Reaction Mechanism
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- เผยแพร่เมื่อ 7 ก.พ. 2025
- This organic chemistry video tutorial discusses how to use the grignard reagent to reduce ketones and aldehydes into secondary and tertiary alcohols. It also explains how to reduce esters and acid chlorides to alcohols using the grignard reagent.
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4:28 Why magnesium will insert the carbon atom?
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@7:03 Why didn't O get protonated at this moment? Why did it kick the OCH3 out instead?
Thank you for making me understand the addition of 2 R-groups.
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At 12:18 I believe this is an epoxide ring opening under basic conditions so the OH lands on the more substituted atom, please correct me if I’m wrong
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4:14 how can you make it Grignard reagent without dry ether
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At 7:14 why didn't the O¯ get protonated and turned into an alcohol instead?
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Thanku sir ..I had confusion in this part
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Can't thank you enough man! I was facing doubts in grignard reagent and this cleared everything!
And a quick question. For the compound in 9:45 won't a ring expansion be more favourable before the addition of the -R group?
this is an SNAE mechanism! rearrangement is only possible when a carbocation is formed. this reaction involves carbanion nucleophile and no carbocations are formed, so no rearrangements
9:28 are there supposed to be that many carbons attached to the grignard reagent?
Love from Bangladesh 😘.
Thank you once again.
So, the Ch3Ch2, we use it twice because we need the oxygen to be negative in order for it to do the proton transfer of hydronium? So it can be an alcohol?
At 3:35, if we had to name this structure would be it be (A) 1-ethyl cyclohexanol or (B) 1-ethyl cyclopentanol? If its (B), why? when counting the longest chain starting with the ethyl group
Thanks! Cleared my concept very well!
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Why is at times the h30+ is written under the arrow and other times it isnt even though its still used
Had to go to this video after seeing a legendary meme about the reagent.
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Great session
Best explanation ❤
Doesnt it matter that you change the position of the CH3 Group in the first example?
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A very useful video, thanks!
This better than my teacher
How do you know what side to put your reagent on? I keep thinking that you could choose either or because you’ll still end up with the same answer..? 08:26 I’ve seen others put their reagents on the aldehyde side and they’ve gotten it the answer right.
Thank you kind sir!
Very efficient!
example 4 at 7:34 why are there 2 ch2ch3 to react with??
is attack by GR always SN2? is there a possibility of rearrangement or ring expansion?
We really appreciate for your help
where did we get the 2 carbons to add to the 4 carbon chain on the last problem?
great explanation!!!!
Thank you for your help!
could you please make a discussion about Reaction of Grignard Reagents with Epoxides
thank you
Im learning from these this one just seemed like you were going kind of fast.
6:53 how do I know something is a good leaving group?
the less basicity one group is ,the better it acts as a leaving group
The more stable the leaving group is as an individual the better the leaving group
(in the case of CH3O- the negative charge is on oxygen which is highly electronegative and hence the molecule is stable)
Which is individually stable that is gud leaving group
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At 4:49 was in the carbon partial -?
No
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I’m struggling to understand how you could only have three carbons and end up with four in the end ?
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Buonara really got me
Why upon reacting ethyl chloride you have included mgbr ethyl instead of using mgcl, but the grignard reagent cl
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One question...if we add to the ester one mole of grignard reagent...will the reaction stop to the ketone? For example...if we have the solution of the ester and we add slowly and dropwise one mole of the grignard reagent in ether/THF solution ...will it stop to the ketone?
Yes if you are using only one equivalent
Any one know the program he using in explication ?
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