Grignard Reagent Reaction Mechanism
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- เผยแพร่เมื่อ 5 ก.ย. 2024
- This organic chemistry video tutorial discusses how to use the grignard reagent to reduce ketones and aldehydes into secondary and tertiary alcohols. It also explains how to reduce esters and acid chlorides to alcohols using the grignard reagent.
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4:28 Why magnesium will insert the carbon atom?
Thanks from Tamilnadu India 😍😀
thankyou for this video! You have selected the best questions and the right amount of questions for this topic! I really appreciate it!
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@7:03 Why didn't O get protonated at this moment? Why did it kick the OCH3 out instead?
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Thanks man these are really great to watch
Why is at times the h30+ is written under the arrow and other times it isnt even though its still used
Thanku sir ..I had confusion in this part
Highest grade on my O Chem 1 final. High A in the class. Gracias.
thanks for your teaching!!
Can't thank you enough man! I was facing doubts in grignard reagent and this cleared everything!
And a quick question. For the compound in 9:45 won't a ring expansion be more favourable before the addition of the -R group?
this is an SNAE mechanism! rearrangement is only possible when a carbocation is formed. this reaction involves carbanion nucleophile and no carbocations are formed, so no rearrangements
Thanks! Cleared my concept very well!
Great explanation!
So, the Ch3Ch2, we use it twice because we need the oxygen to be negative in order for it to do the proton transfer of hydronium? So it can be an alcohol?
Thankyou , your deep explanation is attached to show more than one video and you are show everything in rxn ,what I to do.
India (Hindi)
My man's carrying my entire organic department staff
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wdym
Doesnt it matter that you change the position of the CH3 Group in the first example?
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At 7:14 why didn't the O¯ get protonated and turned into an alcohol instead?
Thanks alot. Now wherever I see RMgX I won't make mistakes.
Thank you once again.
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9:28 are there supposed to be that many carbons attached to the grignard reagent?
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could you please make a discussion about Reaction of Grignard Reagents with Epoxides
thank you
Im learning from these this one just seemed like you were going kind of fast.
excellent video my man. keep up the great work
THANK YOU SIR
is attack by GR always SN2? is there a possibility of rearrangement or ring expansion?
Very good
At 3:35, if we had to name this structure would be it be (A) 1-ethyl cyclohexanol or (B) 1-ethyl cyclopentanol? If its (B), why? when counting the longest chain starting with the ethyl group
Very efficient!
Great session
At 12:18 I believe this is an epoxide ring opening under basic conditions so the OH lands on the more substituted atom, please correct me if I’m wrong
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What I really want to know though is what happens to the Mg2+ and the Br- and also the H2O? 🤔😩
The MgBr is actually attached to the O- that was broken but it is not shown in the video. When an acid or hydronium is added than this attacks the MgBr bond and replaces it with a hydrogen thus giving an OH group. Your byproduct would then be a OHMgBr or ClMgBr depending on what you used to remove that MgBr group from the O- group.
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How do you know what side to put your reagent on? I keep thinking that you could choose either or because you’ll still end up with the same answer..? 08:26 I’ve seen others put their reagents on the aldehyde side and they’ve gotten it the answer right.
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Best explanation ❤
I’m struggling to understand how you could only have three carbons and end up with four in the end ?
Thank you for your help!
God bless you
Thanks
This better than my teacher
so basically grignard agent perform nucleophilic substitution ? i'm new to this i ain't getting things fast
It's technically a base which would abstract an acidic hydrogen if any. If there are no acidic hydrogens, it undergoes substitution
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How do you know of the Carbon is partially positive or negative?
When carbon is attached to a more electronegative atom like O of N ..the more electronegative atom attracts the shared pair of electrons from the electron cloud towards itself ..so it develops partial negative charge.
We really appreciate for your help
thank you so fucking much
where did we get the 2 carbons to add to the 4 carbon chain on the last problem?
example 4 at 7:34 why are there 2 ch2ch3 to react with??
in the first example why does the CH3 have a negative charge
@shammah namallam The Carbon has a -4 charge and the each hydrogen has a +1
What if you created a grignard reagent with bromobenzene and magnesium, then bubbled carbon monoxide through the solution?
Love from india
if there is not indication that there are 2 equivalents of grignard reagent then will the product be ketone?
would be aldehyde with only 1 equivalent of grignard
no nvm, 1 eq of grignard means the reactant is aldehyde or ketone, but the products will always be alcohols for the girgnard reagent. 2 eq of grignard means reactant is ester or acid chloride and the product will be an alcohol with 2 R groups. For 1 eq of grignard that reacts with either aldehyde or ketone, product will also be alcohol but with only 1 R group
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Great video!
Had to go to this video after seeing a legendary meme about the reagent.
Who would've guessed a well edited clip of black'n'white daffy duck would be so funny?
Helped me a lot thanks
Thank you very much.. This is what I need now
Denhxv82 5 run to take 8 hours and turn
6:53 how do I know something is a good leaving group?
the less basicity one group is ,the better it acts as a leaving group
The more stable the leaving group is as an individual the better the leaving group
(in the case of CH3O- the negative charge is on oxygen which is highly electronegative and hence the molecule is stable)
Which is individually stable that is gud leaving group
I feel like you completely skipped over explaining how you got to benzoic acid
Awesome! Thank you
Any one know the program he using in explication ?
Why upon reacting ethyl chloride you have included mgbr ethyl instead of using mgcl, but the grignard reagent cl
great explanation!!!!