Hey Leah, can you please make a couple of more videos in this series 1. regarding the protection of the ketone group in a compound where aldehyde and ketone both are present. 2. some complex practice questions. That'll be a lot of help. Thanks
Great video thanks! Just one question, my professor had the other alcohol on the diol attacking the electrophilic carbon center kicking off the water, whereas you had the oxygen resonate to kick off the water. Does it matter which way the water leaves? Again, Thanks!
I'm sorry, but I don't offer tutoring through TH-cam comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
What if we have a compound that contains an aldehyde as well as a ketone and we have to predict what would be the major product after reaction with Ethylene Glycol/H+ then LAH?
As yourself: which is more reactive between the aldehyde and ketone? OR if you have enough catalyst, they may BOTH be protected and then LAH wouldn't reduce either
GREAT VIDEO my question is if the diol used has the hydroxyl groups in the middle like butan-2,3-diol does the mechanism proceed the same as it did with the 1,2-ethandiol
Glad you like it! Yes, the mechanism would proceed in the exact same way. In your particular example, the only difference would be a couple of extra methyl groups present on your cyclic acetal. All electron-pushing arrows would follow the same pattern.
Hi thank you for your help but in the formation of acetal from hemiacetal are you sure H2o+ won't leave on its own? because my professor didn't make the pi bond from lone pair on O and simply said this is an SN1 reaction and H2o+ is a good leaving group so it would leave on its own followed by a NA by the second alcohol.
I'm confident in my mechanism, but you should always know what your teacher wants you to draw. The water is a good leaving group, but rather than form a carbocation, I believe the preference would be to allow carbon to follow the octet rule and give the positive charge to oxygen.
Thanks a lot, your videos are helping a looooot! I just have one question.. If we have a normal alcohol with only one OH group, the product is going to be with 2 O atoms that are not bonded with C atoms chain, and if we have an alcohol such as 1,4- diol with 2 OH groups, the 2 O atoms are going to be bonded with an C atoms chain (''monster''); am I right? TIA!
I'm sorry, but I don't offer tutoring through TH-cam comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
I'm learning this right now in Orgo II. Perfect upload timing, thank you!!
That's awesome! glad to help
You are simply the best, LEAH. You made my organic chemistry 1 so easier and you still making the 2 as well. BRAVO! Keep up with the good work
Thanks Bernard! Always glad to help. :)
Finally..some good teaching when I needed it... thanks
Glad it was helpful and you're welcome!
you might be my favorite person in the world. thank you so much for your amazing videos
Awww! thanks! and you are very much welcome! :)
You just saved my homework grade. One of the best online science teachers with out a doubt
Thanks! Glad I could help!
Hey Leah, can you please make a couple of more videos in this series
1. regarding the protection of the ketone group in a compound where aldehyde and ketone both are present.
2. some complex practice questions.
That'll be a lot of help. Thanks
Thank you for the suggestions
you're saving my life
So happy to help!
One word - Excellent.
Thanks so much!
Thnku so much..
Respect for u from india
You're very welcome
Only video of this mech I could find thx
you're so welcome
Thank you , ure explanation is very helpful mam😁😁
You're very welcome!
Am I the only one who sees a smiley face around the cyclic acetal protecting group @ 2:08, or am I just turning crazy?
You aren't the only one
Orgo makes you see things! Try looking at the budweiser logo without seeing a chair conformation 🤣🤣
Very nice and helpful ,,,thanks a lot ❤❤❤❤
You're very welcome!
Best explanation...thanks..
You're very welcome
This was so helpful, thank you!
You're so welcome!
Thank you, Mam!
You're very welcome
Great video thanks! Just one question, my professor had the other alcohol on the diol attacking the electrophilic carbon center kicking off the water, whereas you had the oxygen resonate to kick off the water. Does it matter which way the water leaves? Again, Thanks!
I'm sorry, but I don't offer tutoring through TH-cam comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
Finally I got the answer for my MCAT question!
Glad the video helped!
Thank you!
You're welcome!
What if we have a compound that contains an aldehyde as well as a ketone and we have to predict what would be the major product after reaction with Ethylene Glycol/H+ then LAH?
As yourself: which is more reactive between the aldehyde and ketone? OR if you have enough catalyst, they may BOTH be protected and then LAH wouldn't reduce either
GREAT VIDEO my question is if the diol used has the hydroxyl groups in the middle like butan-2,3-diol does the mechanism proceed the same as it did with the 1,2-ethandiol
Glad you like it! Yes, the mechanism would proceed in the exact same way. In your particular example, the only difference would be a couple of extra methyl groups present on your cyclic acetal. All electron-pushing arrows would follow the same pattern.
Thank u so much!!
You're welcome!
Hi thank you for your help but in the formation of acetal from hemiacetal are you sure H2o+ won't leave on its own? because my professor didn't make the pi bond from lone pair on O and simply said this is an SN1 reaction and H2o+ is a good leaving group so it would leave on its own followed by a NA by the second alcohol.
I'm confident in my mechanism, but you should always know what your teacher wants you to draw. The water is a good leaving group, but rather than form a carbocation, I believe the preference would be to allow carbon to follow the octet rule and give the positive charge to oxygen.
@@Leah4sci herh mbaaa
Thanks
You're very welcome
I LOVE YOU THANKYOUUUU
You're welcome!
Thanks a lot, your videos are helping a looooot! I just have one question.. If we have a normal alcohol with only one OH group, the product is going to be with 2 O atoms that are not bonded with C atoms chain, and if we have an alcohol such as 1,4- diol with 2 OH groups, the 2 O atoms are going to be bonded with an C atoms chain (''monster''); am I right? TIA!
you are right
I'm sorry, but I don't offer tutoring through TH-cam comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
@@Leah4sci kmfd!!!!!!
Very good
Glad you like it!
Thank u sooooo much
You're welcome!
Leah4sci omg!!!!! I can't believe u replied i love u so much u are my idol ❤❤
Very nice mam
Thanks Muhammad
HOW DO U REMOVE THE ACETAL
The acetal protecting group can be removed by the addition of acid in water. It would be an acid-catalyzed hydrolysis of the acetal.
Thanks mam
You're welcome :)
Great
thanks
Thanks bae
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Methanamine r u mad it’s not that it is methylamine (a previous video)
Hey it is methanamine as well ..... she's not mad
I could be, who knows?
Ketones form ketals, not acetals.
According to current IUPAC rules, ketals are a subset of acetals. The term "acetal" encompasses both aldehyde-derived and ketone-derived structures.
Can you provide in hindi please I m from India 🇮🇳
Thanks for the suggestion, but this is something I do when I have extra time, so providing in Hindi isn't something I can do right now.