Ag2O is a basic oxide & in aqueous solutions undergo hydrolysis to give a basic solution , which is used as a base. Further Silver Iodide precipitates , since its soluability product is low.
Just a small doubt, What will be the product when CH3I (methyl iodide) is added to CH3-NH2 (primary amine) ? Will the product be CH2=N(CH3)3 ? Note: Here, equals sign (=) is a double bond and, minus sign (-) is a single bond.
Stereochemistry deals about cis and tra in this case but jee syllabus only 8 membered alkene ring can show cis and trans variations because of its large size so it is less hindered .in the case of cis it is same as the usual one and in case of trans the ring is passes over it , now when I say ring that means one of the carbon-carbon bond so that it can from trans , trans in 8 membered ring brings stability due to less dipole moment and in other rings which have less than 8 carbons in it ,the trans type brings instability due to angle strain as rest all carbons are sp3 hybridized so angle between them should be 109.5°
Passing 12th grade chem cause of you! Thanks
Chyeahhhhh
Ag2O is a basic oxide & in aqueous solutions undergo hydrolysis to give a basic solution , which is used as a base.
Further Silver Iodide precipitates , since its soluability product is low.
Very clear and fun lesson
Thanku so much sir...this video really helped a lot👌👍🙏
I think u r right
May i know which class you are??
This is nice. You just made me understand this 🙂🙂
Helped a lot, so thankful 🥺❤️
Thank you good explanation
Can you help me with this reaction:
HOCH2CH2CH3 + CH3I (excess)
Thanks
Just a small doubt,
What will be the product when CH3I (methyl iodide) is added to CH3-NH2 (primary amine) ?
Will the product be CH2=N(CH3)3 ?
Note: Here, equals sign (=) is a double bond
and, minus sign (-) is a single bond.
CH3I+ CH3NH2---∆-->CH3NHCH3+HX
( 2°amine)
Could you please tell me how to avoide OH ion to nucleophilic substitution with methyl iodide...??
Thanks , sir it is a very useful video
Sure
incredible!
I wonder how CH3I makes -NH2 into -(CH3)3+... somebody knows?
thank you
this is very nice❤
Helped alot , thanks 👍
Thank you so much, this was awesome
Thanks
Good explanation sir...
Good
thank you soo much :)
Nice..
Aymeen
hi sir , i didn't understand that stereochemistry part , its bit difficult
Stereochemistry deals about cis and tra in this case but jee syllabus only 8 membered alkene ring can show cis and trans variations because of its large size so it is less hindered .in the case of cis it is same as the usual one and in case of trans the ring is passes over it , now when I say ring that means one of the carbon-carbon bond so that it can from trans , trans in 8 membered ring brings stability due to less dipole moment and in other rings which have less than 8 carbons in it ,the trans type brings instability due to angle strain as rest all carbons are sp3 hybridized so angle between them should be 109.5°
Metoo