This video saved my life. I don't understand how I can sit in a class for and hour and a half for a week and not have a clue as to what I'm doing, then watch a less than 20 minute TH-cam video and catch on the first time. Thank you!!!!
honestly, your an amazing teacher. literally learned everything in just 18 min, rather then spending days. your students are lucky to have you as a teacher.
Either I totally blanked in my chemistry lecture or you really are a better teacher! Made it simple and explained it really well with the example equations! Thanks for posting this, the Crash course video gave no help at all! So glad I found this.
That moment when a stranger in a youtube video is better at teaching you chemistry than the guy with the PHD you pay and wake up for early in the morning. I really do love the internet. Thank you, MrHren.
Thank you so much! I have a chemistry test tomorrow over PH, solutions, gas laws, & energy. PH is the only thing I did not understand completely, this helped greatly!
Thank you. It makes more sense to me now. I was tired so reading the book didn't help when understand when to use these problems. It was very informative.
Thanks for the video, it was useful even though we're not suppose to learn pOH. Although I'll be using it in my calculations. You helped me a great deal!
Dear Maya, in this case you won't be able to calculate the pH of NaNO3 because it is neither an acidic nor a base, so it doesn't have the potential to affect any solution's pH. And in the case you were comparing 2 actual acidics, please consider that the pH is determined by the number of H+ it provides once dissociated multiplied by the concentration. That is: if your acidic is H2SO4 0.1 M, then you wil calculate de pH this way: - Log (0.1 x 2).
Kaitlyn Wagner Glad they are helping. There are quite a few on most general chemistry subjects. If there is something you need that isn't on there let me know and I'll try to get one made for you.
Someone asked how to calculate ph without a calculator.... Its an estimation but it works... for this example: 6.5 x 10 ^-4 to find the first digit of pH take the absolute value of the exponent of the concentration and subtract 1: 4-1=3 to find the decimals of pH take the main value (6.5) and subtract from 9: 9-6.5 = 2.5 you get 3.25... it is obviously not as exact as 3.19 but is close enough for the MCAT a few more examples: -log( 1x10^-7) = 7.00 .... our estimation 6.8 -log( 3.2x10^-9) = 8.49 .... our estimation 8.58 -log( 5x10^-2) = 1.30 .... our estimation 1.4 -log( 5x10^-13) = 12.30 .... our estimation 12.4
The concentration of H and OH isn't always the total concentration of the molarity of the acid or base. This only happens when it's a strong base or acid where we can assume total ionization. Usually teachers don't give strong bases or acids in quizzes/exams because that's too easy....
Thank you so much! My chem teacher is really mean (everyone is either too smart or too afraid to ask her questions in class, and she moves really fast), so this helped a lot. I have a question regarding the ACT list of formulas you show near the end of the video, and the question is: Do we get a reference guide like that as well during the regular chemistry reagents this year, or do we only get to use our reference books?
+Ben Garza Sorry this is a bit late but I am not sure what you would get to use on your reagents exam. I would guess you will be provided with a formula sheet but I can't be sure. I would encourage you to ask your teacher!
You are as awesome as your voice is....you make this so easy though the calculator part was funny :P you should probably get a better camera and do more youtube.....diamondplaybutton awaits
Hey congrats this is very clear thanks!!!!! Just a doubt: About Kw. Shouldn't be: Kw = H + OH ? So OH shouldn't be: OH = Kw - H ? And H: H = Kw - OH ? Or is it Kw = H x OH ? Thank you!
I was wondering, if you are given that a base like NaOH has a ph of 12, I know that the [OH-] is 0.01M and the [H+] is 1.0 *10^-12. My question is for the use of the equation n=cv what concentration do I use in th formula OH or H
for the Kw problem, I calculated : 1.0 x 10^-14 / 3.6 x 10^-5 = 2.77777778E-20 = 2.7 x 10^20...for the answer...can you double check the answer on the video...I noticed that the student gave the answer to you that time, instead of you inputting the info into the calculator yourself....
MonarchDrax 2.777etc. e-20 is what is calculated. Apparently the student that gave me the answer rounded incorrectly and went to 2.7 instead of 2.8. The exact correct answer, with sig figs, would be 2.8e-20 though I wouldn't have marked them wrong for a simple rounding error. Though, knowing the student, they probably just didn't feel like saying the rest of the wording in their calculator. Thank you for asking about it btw!
Does anyone know how to solve problems like this: when calculating pH, how do you determine which of two acids is more acidic if you are given the same molarity? For example 0.1 M NaNO3 and 0.1 M KCH3CO2.
Lol what's wrong with this class. kids in my chem course wouldn't even blurt out asking these question without being looked at like an idiot hahahahahhaha
![Calculating pH, pOH, [H+], [H3O+], [OH-] of Acids and Bases - Practice](http://i.ytimg.com/vi/UiK37I159fc/mqdefault.jpg)
![กี่หมื่นฟ้า | Your Sky Series EP.1 [2/4]](http://i.ytimg.com/vi/qJbQs_nhjD4/mqdefault.jpg)
This video saved my life. I don't understand how I can sit in a class for and hour and a half for a week and not have a clue as to what I'm doing, then watch a less than 20 minute TH-cam video and catch on the first time. Thank you!!!!
honestly, your an amazing teacher. literally learned everything in just 18 min, rather then spending days. your students are lucky to have you as a teacher.
Either I totally blanked in my chemistry lecture or you really are a better teacher!
Made it simple and explained it really well with the example equations! Thanks for posting this, the Crash course video gave no help at all!
So glad I found this.
Charli Young Thanks for the positive comments! I am happy it was helpful.
"I just wanted to be on the recording" beginning of video haha
1:15 "sorry I just wanted to be on the recording"
Whole lesson in 15 minutes, easily explained with students even asking helpful questions throughout you might have. "Cut it out Usif!"
What a great professor. I'm so happy I found this video. I'm feeling confident.
great teaching. these kids don't know how lucky they are.
That moment when a stranger in a youtube video is better at teaching you chemistry than the guy with the PHD you pay and wake up for early in the morning. I really do love the internet. Thank you, MrHren.
I love the disruptive little boy...he gave me life!
THIS HELPED SO MUCH! AH THANK YOU SO MUCH! from a stressed out biomedical science student!
Thank you. I am glad to hear that. Let me know if you have any questions I can help with!
Thank you so much! I have a chemistry test tomorrow over PH, solutions, gas laws, & energy. PH is the only thing I did not understand completely, this helped greatly!
Thank you. It makes more sense to me now. I was tired so reading the book didn't help when understand when to use these problems. It was very informative.
Great lesson. Explained but at a quick pace, straightforward.
Awesome example. The peanut gallery in the back ground had me crackin up. LOL
I understand your explanation better than my chemistry teachers. Thank you !!!
Thank you for helping me understand this 30 min before my test you made very easy
Awesome video, very to the point and clear. Thank you!
I am from Iraq, I followed your explanation and understood, thank you
Thanks so much, I would've failed my chemistry test without this video
I love this interactive classroom feel that your vids have,thank you so much and keep doing what your doin:)
12 years later and this video helped me out so much on my chem exam🙏🏽 thank you so much for explaining it so well!
Honestly thank god for this video, or I wouldn't have any chance of passing my chem test tomorrow !
Thank my lord And savior for TH-cam videos
This teacher's such a baller. And Youseff is just causing ruckus LMAO
i did not understand anything in school
this is the best thing that happened to me
Sher Ahmed Glad it helped!
+Sher Ahmed self learning is always the best way to learn .. god bless MrHren
+its a good video me too ddnt andastand at skul Sher Ahmed
8:54 the kid "who knew it" LOL
LOL this guy's reaction and attitude to his students
Thank you so much for this video, it's literally the only thing standing between me and a failing grade
Thanks Mr.Hren~! Im doing terrible in chemistry, the videos help a lot.
Thank you very much, this helped clear up my college chem 2 lecture.
I finally understand! Thank you beyond words!!!!
Thanks for the video, it was useful even though we're not suppose to learn pOH. Although I'll be using it in my calculations. You helped me a great deal!
Glad to know it helped. If you need anything else check out my other videos. They cover most of the topics you will see in a general chemistry class.
Dear Maya, in this case you won't be able to calculate the pH of NaNO3 because it is neither an acidic nor a base, so it doesn't have the potential to affect any solution's pH. And in the case you were comparing 2 actual acidics, please consider that the pH is determined by the number of H+ it provides once dissociated multiplied by the concentration. That is: if your acidic is H2SO4 0.1 M, then you wil calculate de pH this way: - Log (0.1 x 2).
what I get taught In an hour, I learn it in 18 mins, thankyou
. these videos are saving me right now.thanks!
Kaitlyn Wagner Glad they are helping. There are quite a few on most general chemistry subjects. If there is something you need that isn't on there let me know and I'll try to get one made for you.
Someone asked how to calculate ph without a calculator.... Its an estimation but it works...
for this example: 6.5 x 10 ^-4
to find the first digit of pH take the absolute value of the exponent of the concentration and subtract 1: 4-1=3
to find the decimals of pH take the main value (6.5) and subtract from 9: 9-6.5 = 2.5
you get 3.25... it is obviously not as exact as 3.19 but is close enough for the MCAT
a few more examples:
-log( 1x10^-7) = 7.00 .... our estimation 6.8
-log( 3.2x10^-9) = 8.49 .... our estimation 8.58
-log( 5x10^-2) = 1.30 .... our estimation 1.4
-log( 5x10^-13) = 12.30 .... our estimation 12.4
nice...i finally got it after watching so many different TH-cam video
Great stuff, helped a lot! Thanks!
"You guys are sitting next to each other now, how cute" 16:03 Hahah.. This class kills me.
Thank you for the simplicity of the video.
Awesome teaching!! i understood everything compared to what my professor taught me.
+jameelea mckoy
Thanks. I'm glad it helped you out. Isn't chemistry awesome?
+MrHren Yes it is! Do you have any other videos on the ionization of amino acids. Also as it relates to titration and the zwitterion form
taking biochem, too? i graduated some time ago and went into biochemistry after i got a job and i had to relearn everything
I needed this so much you make things so easy!
You made it very understandable.
Thank you.
thanks man! I have my chem exam tomorrow!
Thank you very much! This really help me with my homework!
Helped a lot!! Great job
The concentration of H and OH isn't always the total concentration of the molarity of the acid or base. This only happens when it's a strong base or acid where we can assume total ionization. Usually teachers don't give strong bases or acids in quizzes/exams because that's too easy....
Thank you!!! you explained very easy!!
fernanda reyna I'm glad it helped!
thanks!!
Thank you so much! My chem teacher is really mean (everyone is either too smart or too afraid to ask her questions in class, and she moves really fast), so this helped a lot. I have a question regarding the ACT list of formulas you show near the end of the video, and the question is: Do we get a reference guide like that as well during the regular chemistry reagents this year, or do we only get to use our reference books?
+Ben Garza
Sorry this is a bit late but I am not sure what you would get to use on your reagents exam. I would guess you will be provided with a formula sheet but I can't be sure. I would encourage you to ask your teacher!
MrHren It is fine, but thanks for giving advice about it, I appreciate it.
Entertaining class
Do you have video on Acids and Bases and using the ICE method?
this helped me a lot. thank you very much.
This is great revision. Thank you.
Such a good teacher, my professor sucks
i didn't understand that form book in class but u make it easier for me thx .
Lifesaver! Thanks so much!
Why do we take the AntiLog of -4.32 in while calculating the H ion concentration? Why don't we take -Anti-Log of 4.32?
This helped a lot! Thank you.
best video ever, I subscribed :)
Thanks. Great video, really helped :)
***** Thanks!
Awsome vid man.
Thanks. I appreciate it!
You are as awesome as your voice is....you make this so easy though the calculator part was funny :P
you should probably get a better camera and do more youtube.....diamondplaybutton awaits
Hey congrats this is very clear thanks!!!!!
Just a doubt:
About Kw.
Shouldn't be:
Kw = H + OH
?
So OH shouldn't be:
OH = Kw - H
?
And H:
H = Kw - OH
?
Or is it
Kw = H x OH
?
Thank you!
It is Kw = H x OH. You might be thinking of pH+pOH=14. Hope that helps!
MrHren
Yes ok, it helps a lot! Thanks :)
Very useful, thank you.
I was wondering, if you are given that a base like NaOH has a ph of 12, I know that the [OH-] is 0.01M and the [H+] is 1.0 *10^-12. My question is for the use of the equation n=cv what concentration do I use in th formula OH or H
Very good teacher...my college teacher is terrible
Those kids must feel famous now lol
Some of those kids are clueless though. pH=3.19. Kid in the back: "3.19 moles????" LOL
awesome ! very helpful BUT our professor don't let us use calculators lol what do i do then?
i want that green TI 30, mine is boring dark blue
SO helpful omg wow!
Yay, thank you. Big help :)
*clears throat* guy*
Can this guy be my teacher? Haha
Thank you so much!!!!
for the Kw problem, I calculated : 1.0 x 10^-14 / 3.6 x 10^-5 = 2.77777778E-20
= 2.7 x 10^20...for the answer...can you double check the answer on the video...I noticed that the student gave the answer to you that time, instead of you inputting the info into the calculator yourself....
I did the math and he is correct what you got is off
MonarchDrax
2.777etc. e-20 is what is calculated. Apparently the student that gave me the answer rounded incorrectly and went to 2.7 instead of 2.8. The exact correct answer, with sig figs, would be 2.8e-20 though I wouldn't have marked them wrong for a simple rounding error. Though, knowing the student, they probably just didn't feel like saying the rest of the wording in their calculator. Thank you for asking about it btw!
Does anyone know how to solve problems like this: when calculating pH, how do you determine which of two acids is more acidic if you are given the same molarity? For example 0.1 M NaNO3 and 0.1 M KCH3CO2.
Lol what's wrong with this class. kids in my chem course wouldn't even blurt out asking these question without being looked at like an idiot hahahahahhaha
Skid
I found this YOUSEFul.
Awesome
now i am less screwed for my chem final tomorrow
So freaking helpful lol
Some of these students need behavior management or focus meds.
Could it be at around 16:05 someone says" your sitting next to each other now, f*+k you"?
Is this Ben Afflek?
Thanks :)
That one Yossef kid was beig a little annoying but other wise this was a pretty helpful video
thank you
thnx!
Thanks
that's right
sorry i just wanted to be on recording.
I
Same as last comment
The students in the background make this video.
like dat
these kids lol
Yes!! First comment first like and first veiw!!!
stop usef... haha