Working of Edge-Triggered D Flip Flop

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  • เผยแพร่เมื่อ 2 ต.ค. 2024
  • The D-type flip-flop or Data Latch has only one input referred to as the “D”, or data input, plus a clock input, CLK along with the usual two outputs, Q and Q. The D-type flip-flop transfers its digital data between the input and its outputs, after a delay of one clock pulse and so the “D” part is also referred to as a “delay” input.
    click here for more details:
    eevibes.com/di...
    #Dflipflop #flipflops #eevibes #digitaldesign #dld #digitallogicdesign #electricalengineering #latches #sequentialcircuits #synchronous

ความคิดเห็น • 13

  • @bsteinmetz400
    @bsteinmetz400 7 หลายเดือนก่อน +4

    Thank you for the help learning!

    • @eevibessite
      @eevibessite  7 หลายเดือนก่อน +1

      Kindly subscribe and share and help to grow :)

  • @gmMujrim
    @gmMujrim 3 หลายเดือนก่อน +2

    I used headphones to listen and heard your breath sound showing how much nervous you are but appreciate you for your well-defined and best lecture ❤

  • @jesseschlothauer6745
    @jesseschlothauer6745 8 หลายเดือนก่อน +3

    The one thing that I think this video missed was, what happens on the falling edge of the clock signal? I worked it through myself and it looks like the output would remain the same. Other than that, very helpful thank you

    • @eevibessite
      @eevibessite  8 หลายเดือนก่อน +2

      Yes, true. If a flip flop is positive edge triggered, then input will be effective only on the rising edge of clock, and there will be no change on falling edge. For negative edge triggered flip flop, output will be changed on the falling edge of the clock signal and no change at the rising edge.

  • @preetham36
    @preetham36 6 หลายเดือนก่อน

    very clear explanation , thankyou mam

    • @eevibessite
      @eevibessite  6 หลายเดือนก่อน

      thank you for acknowledgement. Kindly subscribe and help to grow

  • @chinmayswami9358
    @chinmayswami9358 4 วันที่ผ่านมา

    How did do you decide which output of NAND gate to compute first and pass it to next NAND gate? Because the sequence of choosing NAND gate is changing the outcome

    • @eevibessite
      @eevibessite  4 วันที่ผ่านมา

      Because we are starting with the minimum information and NAND gate is the only gate whose output can be predicted with this min info.

  • @ahmadjaradat3011
    @ahmadjaradat3011 11 หลายเดือนก่อน +2

    Very very nice explanation !!!!

    • @eevibessite
      @eevibessite  11 หลายเดือนก่อน

      Thank you. Kindly like and subscribe

  • @leonardoilpuma2245
    @leonardoilpuma2245 ปีที่แล้ว +1

    Very very nice explanation !!!!