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it's -1-3y
The 1 in your answer should be negative, sox= (-1-3y)/(y-2)
yes me too
thanks!This kinda help me to understand our lecture better...
I solved it a little bit different. The first time I got x=(3y+1)/(2-y), the second time x=(-1-3y)/(y-2).After substituting y with different numbers, both functions had the same x outcomes. Are the two function equations correct in this case?
yes, both are correct, it's like 1/2 = -1/-2
That should be negative 1 sir!!!! If count from range to domain youll see the digference
Mistake at the end!
haha I'm so going to use a happy face instead of x on my exam this friday
hows it going haha
@@water6133 Graduating as a Software Engineer this summer :D Khan Academy ftw!
@@Macky91SWE whoa, that is cool!
@@Macky91SWE have you found a job
🤯
You killed a puppy.
You zmade a miztake
you made a mistakethe smiley face should be frowny face:(
it's -1-3y
The 1 in your answer should be negative, so
x= (-1-3y)/(y-2)
yes me too
thanks!
This kinda help me to understand our lecture better...
I solved it a little bit different. The first time I got x=(3y+1)/(2-y), the second time x=(-1-3y)/(y-2).After substituting y with different numbers, both functions had the same x outcomes. Are the two function equations correct in this case?
yes, both are correct, it's like 1/2 = -1/-2
That should be negative 1 sir!!!! If count from range to domain youll see the digference
Mistake at the end!
haha I'm so going to use a happy face instead of x on my exam this friday
hows it going haha
@@water6133 Graduating as a Software Engineer this summer :D Khan Academy ftw!
@@Macky91SWE whoa, that is cool!
@@Macky91SWE have you found a job
🤯
You killed a puppy.
You zmade a miztake
you made a mistake
the smiley face should be frowny face
:(