Exercise 1.2 class 11 NBF | Ex 1.2 class 11 NBF | National book foundation

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[@Calculus.Corner]

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In which college you are studying

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insha'Allah allah pak will give you reward on this insha'Allah

[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

Thank you for your kind words! I'm glad to have been able to assist you and your fellow math learners.

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[@Calculus.Corner]

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[@Motivational_Guide-l7z]

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[@Calculus.Corner]

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[@IjazAhmed-qo3yg]

Are you from learners acadmey

[@M_I_H_R]

​@@shazianaveed2739 Probably Sir Atif Ahmed

[@nasirawan795]

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Well explained 🎉🎉

[@Calculus.Corner]

Thanks dear

[@aleezy_30]

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[@Calculus.Corner]

You're welcome! I'm glad I could help clarify things for you.

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Sir you are doing a marvelous job. Mashallah,May Allah bless you​@@Calculus.Corner

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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You think wrong

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@scarehickory4935]

Sir Q5 ma numbers ya constants k complex le skte h?
For example
Z1=a+bi
Iski jagah
Z1=1+2i

[@huzaifasattar4738]

Mind blowing hy yara
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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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Well explained.....

[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

InshaAllah

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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[@Calculus.Corner]

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God bless you

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[@Calculus.Corner]

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Dear speed lecturer bhtt lengthy ho jaty hn warna es ly ap stop kr k b Dak skty hn ya per speed b Kam kr k Dak skty hn

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[@Calculus.Corner]

Welcome 💐💐

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Sir physics ke numerical start Karwa de

[@shadowedtruths304]

ur efforts are appriciatable i was facing a real difficulty to solve maths thanks alot to u sir 😊

[@shadowedtruths304]

in q 3 is it compulsry to solve it conversly too???

[@Calculus.Corner]

Most welcome dear ❤️

[@Calculus.Corner]

Yes dear it's compulsory if given in question if and only if

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@@Calculus.Corner tysm

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Amazing explanation and guidelines ❤ 3:38

[@Calculus.Corner]

Thanks

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[@Calculus.Corner]

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I only understand yours method

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i was worried about 11th but your videos are amazing! great explanation, concise, simple and informative. please continue uploading, we need to study 9 out of 9 chapters from you ☺️

[@Calculus.Corner]

Thank you so much for your kind words! I'm thrilled to hear that my videos have helped alleviate your worries about 11th math. That's exactly why I'm here - to make math more accessible and enjoyable for you and your fellow students!
Don't worry, I'll definitely continue uploading videos to cover all 9 chapters of 11th math. I'll make sure to keep my explanations concise, simple, and informative, so you can easily understand and retain the concepts.

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sir so helpful please upload more execrise as early as possible in aug our sendup exam and 5 chapters are included i know it is very difficuilt for you but plz uplooad as early as possible

[@Calculus.Corner]

Thanks so much dear InshaAllah I try my best uploaded first 5 chapters before Aug your sendup

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💞

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[@Calculus.Corner]

Inshallah uploaded as soon

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[@Calculus.Corner]

Welcome

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please make review exercise also

[@MaazAbid-b7y]

4:54 sir I think we have to use commutative property under multication for complex numbers to prove the statement, as the question is saying that use algebraic properties to prove the statement and also we can not let numbers as the question says "algebra"

[@Calculus.Corner]

Yes dear it's also true 💯%

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[@Calculus.Corner]

Okay sure but you can check the playlist 2.2 tak uploaded hn Baki b uploaded soon InshaAllah

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[@Calculus.Corner]

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very nice sir great lectures bas ik choti si request thi kay question jab solve ho jaye tu bas 2 sec kay baad transition kiya karein thora sa side pay ho kay takey pause karney ka time mil jaye or board wala question phir dekh sakein ik dafa akhir ma, and again really appreciate your lectures

[@Calculus.Corner]

Thanks so much InshaAllah try my best next time

[@JCclips2411]

Asslam-o-alikum Sir
First of all sir ap buht acha parahte hain
Acha Sir mene poohna tha k Question 2 me hum Z1 Z2 ko koi khas number lene k bajaye Commutative property of multiplication use kar sakte hain for e.g
L.H.S (Z1.Z2)(Z3.Z4)
=Z1.Z2.Z3.Z4 EQ 1
=(Z1.Z3)(Z2.Z4) Middle Side
Again by eq 1 Z3(Z1.Z2)Z4
So this proves all sides
I hope me apni baat samjha sakka
Plz guide sir

[@Calculus.Corner]

W s dear thanks so much yes your right you can also apply properties it's true 💯👍

[@JCclips2411]

@@Calculus.Corner Thanku so much Sir
Ap reply bhi jaldi dete hain aur parhate bhi buht acha hain
Mene apne tamam doston ko apk channel ka link forward kia hai or Subscribe karne k liye bhi kaha hai

[@Calculus.Corner]

Thanks so much dear 💓

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[@atifali-sr9qz]

Properties use krna must hai .ya method board ma accept ni ho ga

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[@Calculus.Corner]

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love u sir

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absolutely awesome❤❤

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Thanks sir ❤

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Bhai pr math kiyu parh raha?

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Commendable!!!😊
New sub :)

[@Calculus.Corner]

Thanks a lot 😊

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also watch NBF academy usss mei mam bhot acha parhati hai

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sir keep doing great work

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Really legend ho sir g

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Sir It would be so nice of you if you also start uploading Physics lectures of new physics book 2024 version

[@Calculus.Corner]

Sorry dear m surf math k hi lecturer hi upload krta hn

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Awesome sir mashallah

[@Calculus.Corner]

Thanks so much dear

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Keep it up sir🎉🎉😊

[@Gamingwithzarib]

Sir in question number 2 you have to use algebraic properties of complex number i.e associative , commutative not to let a value of Z.
Thanks

[@Calculus.Corner]

Yes dear also use algebraic property of complex numbers both method are correct

[@Gamingwithzarib]

@@Calculus.Corner Ok thanks u sir.
Ok can u please guide me more about if and only if ? I didn't understand clearly.

[@Starlightbrothers459]

Qno2 should be proved generally by algebraic properties

[@Calculus.Corner]

Yes you are right

[@Dailyfacts-v2v]

Great sir 🤗

[@Calculus.Corner]

Thanks

[@PlaybackM-yu1ip]

❤❤❤❤❤❤❤❤❤❤❤❤❤ thanks sir

[@Calculus.Corner]

Welcome dear 💐

[@PlaybackM-yu1ip]

@Calculus.Corner sir g this is nothing I have no words to thank you love you sir may god bless you and help you and give you success in every stage of life.....ameen❤️❤️❤️❤️❤️❤️❤️❤️

[@Aiman-Malik-AM-20]

Sir, Can you provide the link of your video in which you've proven:
|z| = √x2+y2..
Also,
In Q7 you've taken √|x|2+|y|2 = |z|.
however, in our book,
|z| = √x2+y2.
so are they both the same things? 36:51

[@Calculus.Corner]

First see this Question no#7 th-cam.com/video/4CsuzbAvqbI/w-d-xo.html
In this lecturer I can explain |z| =√x2+y2

[@Calculus.Corner]

Also these things are the same yes

[@Aiman-Malik-AM-20]

@@Calculus.Corner Ok thank you sir

[@Calculus.Corner]

Welcome

[@fbise-n6k]

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[@shahzaibjutt168]

Sir l appreciate you ❤

[@Calculus.Corner]

Thank you so much