Complete garbage. You never explained why the current linking the flux d-phi is pi*x^2 /pi*r^2. Why is that current linking the Flux d-phi? d-phi flux is passing through the Differential area assumed. Why would d-phi link current in other part? And your rake English accent makes it even more irritating.
Thank you very much. Excellet video! Very clear. It would be great if you put up more for 3-phase lines, composite conductors (same stuff about capacitance, etc.)?
Very well explained Sir. I did not understand the flux getting multiplied with x^2/r^2 part though. Could you please clarify ?
he doesn't understand it either, this is just word for word from some textbook
This video was so informative that maximum doubts regarding internal flux linkages were cleared. Thank you so much
Thanks. I am glad it was helpful !
My confusions gone away after watching your video . Thanks
Nice explanations👏
Thank you 🙂
Thank you !!! Don't know why textbooks are so secretive as to how these laws flow together XD. Great explanation !
I am glad it was helpful :) All the best !
Nice explanation sirr ...easy to understand
I am glad it was helpful :) All the best !
Nice explanation.....
Thank you. I am glad it was helpful :) All the best !!!
Explained very well sir. Thanks a lot.
Wow this is very good, Thank you Sir alot, you killed it, very good explanation.
Thank you very much for giving me a valuable topics such like that.
Did you used ampers circutal law for closed loop magnetic field
Thank you for your detailed explanation.
it was helpful to me!
Glad it was helpful :) Thank you!!
Thank you sir , this is so helpful....
I am glad it was helpful :) All the best !
Every thing is ok sir....sir make vedios about bundled conductors and gmd gmr....
Sure.. I will take the feedback.. All the best :)
I am confused with what u are doing ! need more better explanation.
Thanx for a good explanation..... 🙂🙂🙂
I am glad it was helpful :) All the best !
great video brother thank you
Thank you for the kind words.. Glad it was helpful..
Complete garbage. You never explained why the current linking the flux d-phi is pi*x^2 /pi*r^2. Why is that current linking the Flux d-phi? d-phi flux is passing through the Differential area assumed. Why would d-phi link current in other part? And your rake English accent makes it even more irritating.
Thanks for the video .very well explained
Thank you very much. Excellet video! Very clear. It would be great if you put up more for 3-phase lines, composite conductors (same stuff about capacitance, etc.)?
Great work sir
I am glad it was helpful :) All the best !
nice videos sir, but i didn't understand the ix to i ratio analogous to N
You are amazing man! Thank you BEAST!!!
I am glad it was helpful :) All the best !
thanku very much its very nice video sir plg also share other video
Glad it helped :) Thank you!
very very good explanation
Sir please tell how to this by energy density
Transition of British accent (0:01) to Indian accent (1:35)
please make videos on inductance & capacitece calculations.
thank you so much sir...it helped me a lot. :)
Thanks. I am glad it was helpful !
Why we take dl
the unit of flux should be weber not weber/m as you have considered the width to be dx and length to be 1 and flux=B.A
great explanation
better accent compared to other indian guys !!
haven't seen the whole video , will you please just tell me an easy definition of flux linkage?
How dis you find dl?
dl هي محيط الدائرة ☺️
+حمودة يا كبير thanks i got it
Please external flux link line conditions. .please upload vido
reaaaaaaaaaaaaaaaaaaaaaly helpful thank you alot
Thank you sir
I am glad it was helpful :) All the best !
Thanks so much brother
awesome. thank you
Thanks :)
SHUBHAM GUPTA you are welcome. Hope it was helpful :)
great...
Thank you,.
awesome
Thank you. Hope the videos are helpful :)
Just a tiny suggestion, pre-writing might be better and use a pen+ pencil & stationery.
Fluxe DENCUTY find no
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Not complete solution. U r following the books
Great explanation