I love how a sub-9 minute video explains better on flux, flux density, and flux linkage better than a textbook does in 10 pages ahaha great video my guy
Thanks! Very clear. Just a quick question. In the last equation, we have 2 variables to find out. Magnetic field (B) and Fi (flux). I have to have one of those to be able to solve the equation as the N and A are easy to be found out. So, how could I work out either of those two variables? Many thanks.
So, would you say that two opposing magnets would have a greater magnetic flux density than two magnets that are attracted to one another, at the same distance apart?
It depends where you are measuring the flux density. Directly between the two magnets, there would actually be zero flux when the magnets are repelling (if you google the field diagram you will see what I mean). But when they are attracting there is flux between them. Hope that helps!
@LovattPhysics I have two N52 Magnets Size 2"L x 1"W x 3/8"H and Magnet wire 18Awg, I will have One Magnet face North and other South But I need to make One Magnet wire Coil that both Magnets rotating 360 degrees in center of One Coil to produce at least 14 Volt and light up 150 watts light bulb, How many turns of magnet wire I need to do or have to produce what i'm looking for the out put. I look forward to your reply
I’m not sure I can answer that without knowing much more details like size of coil, mag field strength, distance from coil to magnet, how the magnet is turning, etc. - my advice would be to start with a small number of turns (eg 10) and measure the output. The output should be directly proportional to the number of turns in the coil so you could calculate it from there. Sorry I can’t be more specific!
I am working N48 57 x 45 for Eddy Current Brakes . I an using multiple magnets. My question is how to increase my field strength that can be felt at longer distance to influence conductor to produce high eddy current and resultant braking force. Should I stack magnets or place magnets N-S N-S. Or any other orientation you may suggest to benefit from N48 magnets.
You have said that B is the magnetic field strength/intensity; which is not correct. B is the magnetic flux density, and H is the magnetic field strength/intensity. Please edit your video, because people may misunderstand or get confused. Thanks. btw, you asked in which course this video is in use to us; personally I'm using it for Electric Machinery course in EE.
Thanks for this - the IB specify the letter B, and that magnetic flux density is equivalent to magnetic field strength, so B is used for both. This is because there is never a consideration of magnets in different mediums at IB level so the permeability is assumed to be constant. Hope that makes sense!
For Flux Density, I don't understand: if, at any point near the proximity of a magnet, there is always a magnetic force acting on an object, why say that there are more of these lines on one area than another? if that were the case, then that would imply that at some points near the proximity of the magnet there would be NO forces at all acting on the aforementioned object.
Good question. Lines are just a visual way of representing the magnetic field. An oversimplification. A more correct way would be to have different shades perhaps, with a darker shade closer to the ends of the magnet, but then you lose the directionality of the field. In Physics there is a lot of simplification in order to make abstract concepts more easy to visualise. Hope that makes sense!
Barney Twist - good question. Magnetic field intensity (otherwise known as magnetic flux density) is basically the same as magnetic field strength - they are two ways of describing the same thing.
Barney Twist yes, you’re right, they should be the same but instead we have Tesla and Weber per sq meter. But try converting each of these units into base SI units and see what you get. They should both give you kg.s^-2.A^-1. So really they are the same, we have just given them 2 different names!
Thank you once again... l did some research sir and l found out that B = μ0H and the unit of μ0 are 1/metres (m^-1) and the units of magnetic field intensity(H) are (wb/m) which is not equal to the tesla (wb/m^2) l am stuck here
Barney Twist sorry I misunderstood your initial question. The H field is not normally taught at IB or A-level to my knowledge so I was confused! I have also done a bit of research now, and to put it simply the difference between H and B fields is that H is dependent on the material the magnet is made from and the material through which the field travels. For example, for two identical magnets in a vacuum H is directly proportional to B and the only difference is the units. If you start to look at the field inside the magnetic material, or if the magnet is inside a material with a different permittivity to a vacuum and that is when you start to see the difference in H. Which course are you studying? I am interested to know where the H field is included in your studies. If you need any more help you can catch me at lovattphysics(at)gmail(dot)com!
thanks for the best simplified and practical explanation. in the videw it show F=iBL , i read in some different physic book that magnetomotive force F= Ni. can you please give more clarification about what different between this two different formula for F.
One in a billion, A is the area of the plane itself. The plane is usually formed by a coil of wire, so if the wire is coiled in a circle of radius r, A=pi r^2. Hope that helps!
Hi, thanks for the comment! Cos vs. Sin is all to do with what our reference angle is. Remember that Cos90 = 0 and Sin90 = 1, Cos0=1 and Sin0 = 0. So in this case, the angle that we're talking about is the angle between the normal to the plane of the coil and the magnetic field lines. If this angle is 0 degrees then the magnetic flux through the coil is at a maximum, so we use Cos, because Cos is at a maximum at 0 degrees too. However, if we were talking about the angle between the field lines and the plane of the coil, then the flux would be highest when this angle was 90 degrees, so we could use Sin. Hope that helps. If you need any more info - I've also replied to your email so we can discuss on there. LP
from my electromechanic engineering book i have another formula used for the force (Mmf , magnetomotive force), as can be seen from bellow page scan from the book. F= ΦR (where Φ is the magnatic flux, and R is the reluctance) Φ = BA R= l/uA (is is the permeability) so F = Bl/u my question, why are the two formulas not matching (the first formula from your youtube, the second formula from the book)? What did I miss and mistaken? F= ΦR (where Φ is the magnatic flux, and R is the reluctance) Φ = BA R= l/uA (is is the permeability) so F = Bl/u my question, why are the two formulas not matching (the first formula from your youtube, the second formula from the book)? What did I miss and mistaken? And i have to thank you for the awesome and informative video
@ Naoki Satryo Anggito well if you have the induced or even the initial supplied emf then you may use faradays electromagnetic induction law emf= -N(PHI)/TIME where phi= BA or if its just flux then you dont need N if you want to find the velocity then use emf= -N(PHI)x DELTA SPEED/DELTA DISTANCE
If you're talking about the final problem, the "surface" of area is vertical in the form of the coil, so the normal is horizontal and parallel to the magnetic field direction, cos(0) = 1
I love how a sub-9 minute video explains better on flux, flux density, and flux linkage better than a textbook does in 10 pages ahaha
great video my guy
Most textbooks are useless tbh
This was one of the best explanation I have seen. I like the use of the scale!
Sir you are rescuing my degree! Your videos are fantastic, please never stop! :) It is really really appreciated.
At 4:15 theres a mistake, at 90 degrees cosTheeta will be 0 and therfore no magnetic flux will be produced.(correct me if i am wrong)
Absolutely right! Well spotted :)
Yes cuz the angle when the magnetic field passing through is perpendicular is 0 and cos 0 is one. You are correct
Thanks! Very clear. Just a quick question. In the last equation, we have 2 variables to find out. Magnetic field (B) and Fi (flux). I have to have one of those to be able to solve the equation as the N and A are easy to be found out. So, how could I work out either of those two variables? Many thanks.
This video is perfect in every way.
trying to teach myself magnetism during covid with no support and flux linkage has been confusing me for days until i saw this.
Awesome! So glad it was useful! 😀
In the initial F = IBL, is L the length of the coil overall, or the wire that makes up the coil?
The wire that makes up the coil!
So, would you say that two opposing magnets would have a greater magnetic flux density than two magnets that are attracted to one another, at the same distance apart?
It depends where you are measuring the flux density. Directly between the two magnets, there would actually be zero flux when the magnets are repelling (if you google the field diagram you will see what I mean). But when they are attracting there is flux between them. Hope that helps!
Good video how much some times the value of flux?
@LovattPhysics I have two N52 Magnets Size 2"L x 1"W x 3/8"H and Magnet wire 18Awg, I will have One Magnet face North and other South But I need to make One Magnet wire Coil that both Magnets rotating 360 degrees in center of One Coil to produce at least 14 Volt and light up 150 watts light bulb, How many turns of magnet wire I need to do or have to produce what i'm looking for the out put. I look forward to your reply
I’m not sure I can answer that without knowing much more details like size of coil, mag field strength, distance from coil to magnet, how the magnet is turning, etc. - my advice would be to start with a small number of turns (eg 10) and measure the output. The output should be directly proportional to the number of turns in the coil so you could calculate it from there. Sorry I can’t be more specific!
@@lovattphysics6366 why my reply back to you is not showing???
@@wingedbull1257 not sure - I can’t see it either!
I am working N48 57 x 45 for Eddy Current Brakes . I an using multiple magnets. My question is how to increase my field strength that can be felt at longer distance to influence conductor to produce high eddy current and resultant braking force. Should I stack magnets or place magnets N-S N-S. Or any other orientation you may suggest to benefit from N48 magnets.
You have said that B is the magnetic field strength/intensity; which is not correct. B is the magnetic flux density, and H is the magnetic field strength/intensity. Please edit your video, because people may misunderstand or get confused. Thanks.
btw, you asked in which course this video is in use to us; personally I'm using it for Electric Machinery course in EE.
Thanks for this - the IB specify the letter B, and that magnetic flux density is equivalent to magnetic field strength, so B is used for both. This is because there is never a consideration of magnets in different mediums at IB level so the permeability is assumed to be constant. Hope that makes sense!
For Flux Density, I don't understand: if, at any point near the proximity of a magnet, there is always a magnetic force acting on an object, why say that there are more of these lines on one area than another? if that were the case, then that would imply that at some points near the proximity of the magnet there would be NO forces at all acting on the aforementioned object.
Good question. Lines are just a visual way of representing the magnetic field. An oversimplification. A more correct way would be to have different shades perhaps, with a darker shade closer to the ends of the magnet, but then you lose the directionality of the field. In Physics there is a lot of simplification in order to make abstract concepts more easy to visualise. Hope that makes sense!
Thanks for your amazing explanation
Hie sir thank you for the nice video....sir whats the difference between magnetic field strength(B) and magnetic field intensity (H)?
Barney Twist - good question. Magnetic field intensity (otherwise known as magnetic flux density) is basically the same as magnetic field strength - they are two ways of describing the same thing.
Thank you sir but how come the units of B and H are different? aren't they suppose to be the same if its the same thing
Barney Twist yes, you’re right, they should be the same but instead we have Tesla and Weber per sq meter. But try converting each of these units into base SI units and see what you get. They should both give you kg.s^-2.A^-1. So really they are the same, we have just given them 2 different names!
Thank you once again... l did some research sir and l found out that B = μ0H and the unit of μ0 are 1/metres (m^-1) and the units of magnetic field intensity(H) are (wb/m) which is not equal to the tesla (wb/m^2) l am stuck here
Barney Twist sorry I misunderstood your initial question. The H field is not normally taught at IB or A-level to my knowledge so I was confused!
I have also done a bit of research now, and to put it simply the difference between H and B fields is that H is dependent on the material the magnet is made from and the material through which the field travels. For example, for two identical magnets in a vacuum H is directly proportional to B and the only difference is the units. If you start to look at the field inside the magnetic material, or if the magnet is inside a material with a different permittivity to a vacuum and that is when you start to see the difference in H.
Which course are you studying? I am interested to know where the H field is included in your studies. If you need any more help you can catch me at lovattphysics(at)gmail(dot)com!
thanks for the best simplified and practical explanation. in the videw it show F=iBL , i read in some different physic book that magnetomotive force F= Ni. can you please give more clarification about what different between this two different formula for F.
what a lifesaver! i finally get it oh my goodness
Is A the area the plane sweeps through when it moves or the area of the plane?
One in a billion, A is the area of the plane itself. The plane is usually formed by a coil of wire, so if the wire is coiled in a circle of radius r, A=pi r^2. Hope that helps!
Fantastic video!
Thanks! :)
why we use cos..not a sin...can i get more details about it
Hi, thanks for the comment! Cos vs. Sin is all to do with what our reference angle is. Remember that Cos90 = 0 and Sin90 = 1, Cos0=1 and Sin0 = 0. So in this case, the angle that we're talking about is the angle between the normal to the plane of the coil and the magnetic field lines. If this angle is 0 degrees then the magnetic flux through the coil is at a maximum, so we use Cos, because Cos is at a maximum at 0 degrees too. However, if we were talking about the angle between the field lines and the plane of the coil, then the flux would be highest when this angle was 90 degrees, so we could use Sin. Hope that helps. If you need any more info - I've also replied to your email so we can discuss on there. LP
from my electromechanic engineering book i have another formula used for the force (Mmf , magnetomotive force), as can be seen from bellow page scan from the book. F= ΦR (where Φ is the magnatic flux, and R is the reluctance)
Φ = BA
R= l/uA (is is the permeability)
so F = Bl/u
my question,
why are the two formulas not matching (the first formula from your youtube, the second formula from the book)? What did I miss and mistaken?
F= ΦR (where Φ is the magnatic flux, and R is the reluctance)
Φ = BA
R= l/uA (is is the permeability)
so F = Bl/u
my question,
why are the two formulas not matching (the first formula from your youtube, the second formula from the book)? What did I miss and mistaken?
And i have to thank you for the awesome and informative video
Sir, is there any other formulas to find flux linkage besides that formula? thank you
@
Naoki Satryo Anggito well if you have the induced or even the initial supplied emf then you may use faradays electromagnetic induction law
emf= -N(PHI)/TIME where phi= BA or if its just flux then you dont need N
if you want to find the velocity then use
emf= -N(PHI)x DELTA SPEED/DELTA DISTANCE
Amazing. Thank you
Flux are the field lines passing through a body
Finally i know what is Flux Linkage
GREATNESSSSSSSSSS, THANKK YOU VERY MUCH I HOPE YOU THE BEST!!!
You’re most welcome :)
So nice
Great video.
Thank you sir, the video is very clear
Loved this, u helped me !
Awesome 🤩
Thank you.
Good Teaching, Thank you.
thank you so much
Thank you so much, helped a lot.
You’re welcome! Thanks for the comment :)
Cheers
thank you! this was helpful. :))
probably on the wrong side of the internet again you’re welcome! Thanks for watching :)
cos(90)=0 right.... so
If you're talking about the final problem, the "surface" of area is vertical in the form of the coil, so the normal is horizontal and parallel to the magnetic field direction, cos(0) = 1
Magnetism - Important Terms / चुंबकत्व - महत्वपूर्ण शब्द th-cam.com/video/P_rn0yPJc-Y/w-d-xo.html
nice you're married, nice ring