MCAT Physics Practice: Horizontal & Vertical Movement

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  • เผยแพร่เมื่อ 11 ก.ย. 2024

ความคิดเห็น • 2

  • @kareemsarakbi107
    @kareemsarakbi107 7 หลายเดือนก่อน +1

    Hey Ace can i do this instead? I wanted to make sure I can think about acceleration in x and y direction? Thanks for the help in advance
    deltaY= Voyt + 1/2at^2 (in y)
    45 = 0 + 1/2 10 t^2
    t= 3
    Now go to x direction
    deltaX= Voxt + 1/2at^2 (in x)
    1/2at^2 (in x) is zero since no acceleration in X direction
    deltaX= Voxt
    deltaX= 9 x 3
    deltaX = 27

    • @acethemcat
      @acethemcat  7 หลายเดือนก่อน

      Yup! It's just a different way of getting the same result. If you think about it, v=d/t is just that larger equation when a=0.