Solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity v m

Solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity v m/s. If sphere climbs upto height h of a smooth inclined plane, then the value of v is
Solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity v m/s.,If sphere climbs upto height h of ,a smooth inclined plane, then the value of v is,

[@mryuvraj196]

Sir aapne rough wala case bata ke concept or clear kar diya excellent explanation sir 👍 😊

[@APGKiDuniya]

God Bless You and Keep Watching

[@educationjaipur]

Sir, I have never seen so good explanation of such type of problem. Thanks sir

[@APGKiDuniya]

यह शब्द मेरे लिए बहुत उत्साहवर्धक है धन्यवाद मित्र

[@SahilDas333]

Sir this question was really tricky...

[@manishakabsuri2493]

Very very very very very........♾️ nice

[@APGKiDuniya]

GOD BLESS YOU....KEEP WATCHING

[@rakshitpathak8109]

wonderful explanation sir

[@madheshmuthu7940]

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[@puneetGurjar-id4vv]

Thank you very much sir 😊

[@APGKiDuniya]

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[@ScrubsAndSkills]

I always rely on your video solutions for physics. Nobody gives such excellent explanation anywhere on youtube. Add more and more questions please so that i can always learn from you. 🫶🏼

[@Krishna_Saw]

Mera bhi answer yahi aa raha hai but coaching ke sir pata nahi kyu rotational and translational both kinetic energy ko potential energy me convert kar ke answer √(10gh/7) bata rahe hai.

[@Supriyadubey_mbbs]

👍👍

[@anuj7836]

Best explanation

[@jayashreeshanmugam4871]

Superrrr 1st view

[@APGKiDuniya]

How you get Video

[@surendersingh1660]

Thank you so much sir 😊