An impulse J is applied on a ring of mass m along a line passing through its centre O and the ring
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- เผยแพร่เมื่อ 5 ก.ย. 2024
- An impulse J is applied on a ring of mass m along ,a line passing through its centre O ,and the ring is placed on a rough horizontal surface. ,The linear velocity of center of ring once ,it starts rolling without slipping will be,
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Sir solve remaining questions also pls
Thanks 😊 sir
Most welcome
Sir why u have not consider mvR in final situation as in question it says pure rolling means both translational and rotatonal motion so we have to take both the momentums naa???? Pls replyyy
Sir ne directly add kia hai... Agr mvr lete toh mvr + Iw ata.. Iw=mr^2 × v/r= mvr ata jo ki finally whi ans deta hai
Sir in final angular momentum will we not consider mvr ? (V= velocity after pure rolling)
Sir ne directly add kia hai... Agr mvr lete toh mvr + Iw ata.. Iw=mr^2 × v/r= mvr ata jo ki finally whi ans deta hai