1. I think the very first step should be measuring the degree of unsaturation. 2. For ensuring which one is e/f, you can go for chemical shift calculation.
After the molecular ion undergoes the McLaferty rearangent, it forms the Cationic Radical fragment you have drawn, where the new OH formed is now bound to an sp3 carbon, whereas the ester oxygen ends up sp2 hybridized after the carbon atom it was originally bount to, breaks off to form a neutral fragment. What I learn here is that through the McLaferty rearrangent of the Molecular Cationic Radical, a smaller Cationic Radical fragment forms containing the rearranged gamma hydrogen. As this species is also a CATION RADICAL, it is detected by the MS detector. Thanks.
Man, I just found your videos and they are really good, you talk very clearly and show every step of the thinking behind the problem. I was searching for videos like that so I could see someone actually working on determining structures from spectra and it helped me a lot. About the UV, it's probably just confirming the existence of conjugation, I think. The more conjugated the molecule, the higher the max wavelength it absorbs in UV-VIS region. The spectra shows an absorption at 260 nm, so it must have some conjugation, but not too much as it falls in the UV region, not in the VIS.
Hello sir I'm from Pakistan..I want to ask about the solving all the spectrum with concluding result..I mean I want to use iR,HNMR,CNMR and Mass spectrum to conclude structure
That was pretty helpful. Though you can note that an odd electron ion or an even mass fragment (here it’s at m/z 122) formed through fragmentation of an even mass molecule would result from a rearrangement. This rearrangement here is McLafferty concerted rearrangement that would happen when a gamma sp3-hybridized carbon has a hydrogen atom that transfers to the heteroatom (here it’s the oxygen) with alpha-beta bond to the double bond being cleaved. Note that for an ester it’s a special case rearrangement considering the oxygen atom of the alcohol chain to be alpha with respect to the double bond. Hope this helps.
Are you referring to the carbon NMR? Since this is a DEPT experiment, only the carbons that have H's bonded to them are showing up. It is not a normal carbon NMR! Hopefully this answers your question?
![Structure Determination from Spectra (1) (H NMR, C NMR, IR) [Ketone, Ester, Carboxylic Acid]](http://i.ytimg.com/vi/u8TUJW3iGos/mqdefault.jpg)
For a copy of the tables I use click here: drive.google.com/file/d/0BwOceMKQTVFxRTh1Szl4aTh0eE0/view
Thank you, how do I contact you directly
It says I require access to the folder can you please do that
Hello , I just need access to the folder
2:30 that’s something called “overtone” created from the carbonyl
1. I think the very first step should be measuring the degree of unsaturation.
2. For ensuring which one is e/f, you can go for chemical shift calculation.
This was really helpful thanks, maybe running through how to get the Molecular formula when you don't have it would be a plus
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It was a little bit zdfggg but
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This doesn’t explain why you think the ways that you do! During the video you should be explaining why you came to those assumptions
The small peak at 3400 in IR is the overtone from the carbonyl.
It's quite brilliant!!! Thank you for sharing. Regards from China
i have confusion about CH splitting ?? ....
After the molecular ion undergoes the McLaferty rearangent, it forms the Cationic Radical fragment you have drawn, where the new OH formed is now bound to an sp3 carbon, whereas the ester oxygen ends up sp2 hybridized after the carbon atom it was originally bount to, breaks off to form a neutral fragment.
What I learn here is that through the McLaferty rearrangent of the Molecular Cationic Radical, a smaller Cationic Radical fragment forms containing the rearranged gamma hydrogen. As this species is also a CATION RADICAL, it is detected by the MS detector.
Thanks.
My only criticism is that it would be nice to see the NMR data listed out....2H (triplet), etc. along with the actual chemical shift data.
God bless you....I’m now loving organic chemistry 😊🎉❤
hi, it would be really useful if you could include pdf of those chart
Man, I just found your videos and they are really good, you talk very clearly and show every step of the thinking behind the problem. I was searching for videos like that so I could see someone actually working on determining structures from spectra and it helped me a lot. About the UV, it's probably just confirming the existence of conjugation, I think. The more conjugated the molecule, the higher the max wavelength it absorbs in UV-VIS region. The spectra shows an absorption at 260 nm, so it must have some conjugation, but not too much as it falls in the UV region, not in the VIS.
Kkkii
MMA
Aid
It doesn’t matter what it was good 😊 but I love ❤️ so you know me lol 😆 just let us keep
You should apply double bond equivalent to proved double bond
This video was very helpful! Thank you for sharing your wisdom and time!
Hello sir I'm from Pakistan..I want to ask about the solving all the spectrum with concluding result..I mean I want to use iR,HNMR,CNMR and Mass spectrum to conclude structure
thanks for your useful video. I will have an exam on friday, this video is awesome
Great! Glad to hear it and good luck on Friday!
The peak at 122 on MS is called a McLafferty rearrangement and it includes a loss of a whole molecule ( a neutral molecule fragmented off). 😊
That is a very usefull video thanks from Türkiye💌💌💌
Hi sir
This is Dipak from india
Please give examples on TOCSY AND COSEY Spectra
Very helpful 😊😊😊I'm like Organic is my favorite right now 😊🔥🔥🔥💃💃💃
It seems you did not assign the carbonyl carbon in C-NMR!
The peak you are wared about around 3350 is the overtone of C=O
Sir i have an NMR data of my sample can you interpret it?.
Sir also include CNMR spectrum with these two spectrums
hello
can I get you chart for IR and H NMR or all what you have ?
Hello! For a copy of the tables I typically use click here: drive.google.com/file/d/0BwOceMKQTVFxRTh1Szl4aTh0eE0/view
I need some help, Is there anyway I could communicate with you Tony?
Hi Amal! You can email me at: Tony.ChemistryExplained@gmail.com
Matur nuwun nggih pak. Kula dados ngertos amargi panjenengan 😊
This is really helpful thank you so much sir
Good explanation, thank you Sir
That was pretty helpful.
Though you can note that an odd electron ion or an even mass fragment (here it’s at m/z 122) formed through fragmentation of an even mass molecule would result from a rearrangement. This rearrangement here is McLafferty concerted rearrangement that would happen when a gamma sp3-hybridized carbon has a hydrogen atom that transfers to the heteroatom (here it’s the oxygen) with alpha-beta bond to the double bond being cleaved. Note that for an ester it’s a special case rearrangement considering the oxygen atom of the alcohol chain to be alpha with respect to the double bond. Hope this helps.
good young man , wish for you all the good
Thank you
Please solve on C14H15N
Thanks
Really a great video!
Thanks!
It was very nice lecture.
Thanks...good structure determination detective work...cheers
thanks from india
the aromatic region should show 4 lines instead of 3 ?! 1 more for the carbon connected to the ester carbonyl?!!!
Are you referring to the carbon NMR? Since this is a DEPT experiment, only the carbons that have H's bonded to them are showing up. It is not a normal carbon NMR! Hopefully this answers your question?
got it , thanks a lot i find your videos very helpful
Thanks for sharing, it helped me a lot!!! regards from Spain!
Thanks a lot, Sir
THANK YOU:D