"Unveiling The Secret Of Conservation" The Law Of Mass And Definite Proportion Explained!"
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- เผยแพร่เมื่อ 8 ก.ย. 2024
- In this video, we delve into the intriguing realms of the Law of Conservation of Mass and the Law of Definite Proportion.
Whether you're a student, educator, or just someone curious about the wonders of chemistry, this video is tailored for you! Gain a solid understanding of these laws and appreciate their significance in the broader scientific landscape.
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Pls sir ..when are you starting tutorial for jupeb
1.percentage of Cu in sample1 =2.01÷2.25 ×100= 89.3%
Percentage of O in sample 1= 0.24÷2.25 × 100= 10.7%
2. Percentage of Cu in sample 2= 2.18× 100 ÷2.44 = 89.3%
Percentage of o in sample 2= 100% - 89.3% = 10.7 %
3.percentage of Cu in sample 3= 0.24×100÷2.25 = 89.3%
Percentage of o in sample 3= 100%- 89.3%= 10.7%
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In sample 1 the percentage composition by mass of cu in cuo is :
2.01÷ 2.25 ×100÷1= 89.3%
Percentage comp.by mass in oxygen cuo is :
0.24÷2.25×100÷1= 10.7%
In sample 2
The percentage composition by mass of cu in cuo is :
1.92÷2.15×100÷1 = 89.3%
Percentage composition of oxygen in cuo is:
0.23÷2.15×100÷1=10.7%
Sample 3 the percentage composition of mass of cu in cuo is:
2.18÷2.44×100÷1= 89.3%
Percentage composition of oxygen in cuo is:= 0.26÷2.44×100×1=10.7%
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Percentage composition of Cu in sample 1 is 89.3%
Percentage composition of O in sample 1.is 10.6%
Percentage composition Cu sample 2 is 89.3%
Percentage composition O sample 2 10.6%
Percentage composition of Cu 3 89.3%
Percentage composition of O sample 3. 10.6%
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