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You are most welcome Manit Singh. For more videos like this, download COACHENGG App from Google Playstore or from the link below: play.google.com/store/apps/details?id=com.rdnc.coachengg
Thank you for the kind feedback Kumar Gaurav. Really glad that you liked our work . You can get access to more videos like this on our android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.
Thank you Bocha Sridhar. For more videos like this, download the COACHengg APP from playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg
You are most welcome Mohd Sameer. Really glad that you liked our work. You can also Download the COACHengg APP from playstore: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, tests and doubt discussion forum and you can access it for a small monthly subscription fee.
You are most welcome Surendra Kumar Verma. For more videos like this, Download COACHENGG App from Google Playstore or from the link below: play.google.com/store/apps/details?id=com.rdnc.coachengg
Thank you Aayush Bisht. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Sir can we derive velocity at any instant t if we project the ball along the horizontally making no angle?? If yes then should we write i cap for velocity along x and y cap for velocity along y??? Plzz solve
Yes Samridhi. If you throw the ball horizontally from a height 'h' you can solve it just like a normal projectile. Use i cap for the motion along ground and j cap for the motion along the y-axis
Thank you Sachin. Really glad that you liked our work. You can also Download the COACHengg APP from playstore: play.google.com/store/apps/details?id=com.rdnc.coachengg. All our content is organized there subject wise and Chapterwise along with assignments, tests and doubt discussion forum
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Hi Nikhil. Acceleration does not depend on the magnitude or direction of the initial velocity. Acceleration depends on the net force acting on a body. In the case of projectile motion, only one force is acting, i.e, mg, which acts in the vertical direction. That is why acceleration is in the vertically downward direction.
Sir how is the horizontal acceleration zero? Because when we are throwing it is obvious that we are applying a horizontal force on it . So shouldn"t there be any horizontal acceleration? Plz do clear it . It is my yearlong doubt.
Hi Himangshu. In discussing projectile motion the object is given an initial velocity (due to application of some forces by your hand, or by a gun etc.) . The analysis is done after this action. Once the ball leaves your hand or the bullet leaves the gun, there is no other force acting on it apart from gravity.
Displacement along y axis = final y coordinate - initial y coordinate = (-h) - (0). I have discussed how and why I chose the co-ordinate system in the first 3 minutes of the video
You are most welcome Aditi Choudhary. For more videos like this, download COACHENGG App from Google Playstore or from the link below: play.google.com/store/apps/details?id=com.rdnc.coachengg
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the relation between y (vertical position) and x (horizontal position) is a quadratic equation. The graphs of quadratic equations are parabolic in shape.
@@COACHengg4u if we talk about horizontal projection in which object is drooped (thrown horizontally straight) from a height then what will happen because starting point is already the highest point and it will continue moving towards the ground.
You are most welcome Joydeep Paul. For more videos like this, download COACHENGG App from Google Playstore or from the link below: play.google.com/store/apps/details?id=com.rdnc.coachengg
Thank you Raj Saini. Really glad that you liked our work. You can get access to more vidoes like this on our android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.
Thank you Nisha Sharma. For more videos like this, download the COACHengg APP from playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg.
Thank you. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Thank you Nisha Sharma. For more videos like this, download COACHENGG App from Google Playstore or from the link below: play.google.com/store/apps/details?id=com.rdnc.coachengg
Glad that we could help you Captain Sups_Xd. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
You are most welcome cbse education. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.
Very nice sir! Thanks a lot!! But 1 question... When you project the object above the horizontal at an angle, then the height should be greater than h, shouldn't it?
If you throw at angle above the horizontal the maximum height will be more than the height of the tower. If you throw horizontally or below the horizontal level at some angle, then the maximum height above the ground will remain as the original height from which the body was thrown. I have discussed all the three cases in the video.
Thank you for the kind comment Abhilash Tyagi. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Thank you Keshaw. You can also Download the COACHengg APP from playstore: play.google.com/store/apps/details?id=com.rdnc.coachengg. All our content is organized there subject wise and Chapterwise along with assignments, tests and doubt discussion forum
You are most welcome Priyu Mina. Will post the FBD videos too. In the meantime you can watch NEET and JEE Main FBD related solved numericals in these videos - th-cam.com/video/lFQ1YZiTfUc/w-d-xo.html th-cam.com/video/o5vd279nlog/w-d-xo.html
Hi Nishant. We use +ve and -ve signs in front of vectors to specify their direction. We can choose any convention to do that. You can either choose upwards positive or downwards positive at the beginning of your discussion. Whatever convention you choose, apply it properly to all vectors (displacement, velocity, acceleration). If applied correctly the answers will remain the same. If I take upwards positive in this question, all the terms in the vertical direction will be negative (displacement, velocity, acceleration). So when you make the equation of motion, the -ve signs will cancel out on both sides of the equation and the answer will come out as the same as if you had chosen the opposite convention
You are most welcome Sarad Gupta. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Thank you Nazish Khan. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Thank you so much Manjibhai Bhingaradiya. Really glad that you liked our work. We also have an android app. You can download the COACHengg APP from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Thank you Yash. Really glad that you liked our work.We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
You are most welcome Monika Raghuwanshi. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
hello sir, i am preparing for NEET without any coaching totally depending on internet and as most of students i am poor at physics. but i am so unfortunate that i found you today!!! so, i am asking you if are there other chapters like SEMICONDUCTORS,PROPERTIES OF MATTER, ELECTROSTATICS,THERMODYNAMICS,OPTICS.... etc. most important chapters for NEET in your free videos, or is there any other way for purchase your videos ?
Hello Tapas Ranjan Barik. You can download the COACHengg APP from playstore:play.google.com/store/apps/details?id=com.rdnc.coachengg. All our content is organized there subject wise and Chapterwise along with assignments, tests and doubt discussion forum. As of now, it is completely free and later we will be charging a very nominal monthly fees for it.
Thankyou sir...thnx a lot for making me understand this concept so clearly...I was so tensed coz I was not getting projectile but now I can solve everything...
You are most welcome Chintu Dansana. Really glad that you liked our work. You can get access to more videos like this on our android app "COACHENGG" which you can download from google playstore or from the link given below: play.google.com/store/apps/details?id=com.rdnc.coachengg All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.
Download the COACHengg APP from playstore: play.google.com/store/apps/details?id=com.rdnc.coachengg.
All our content is organised there subject wise and chapterwise along with assignments, tests and doubt discussion forum.
Sir kisi object ko apn height se fekte hai angle ke sath to initial velocity of vertical and horizontal same kiu hoti h
This explaination was great, thank you, truly appreciate it.
sir your channel is very nice....really very nice. if u include jee adv problem chapterwise of all the chapters...it will be best one
Thank you so much Sir. Well explained.......
You are most welcome Manit Singh. For more videos like this, download COACHENGG App from Google Playstore or from the link below:
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i think there is a flow in accounting for the time on Y axis
Can you please highlight the part of the video where you saw the mistake. You can mention the time of the video.
You didnt account for the time it flew upwards
7:35
Excellent video, very convincing video.
Thank you for the kind feedback Kumar Gaurav. Really glad that you liked our work .
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Really amazing!
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Highly thankful to u!!!
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Very Good. Thanks and Regards
You are most welcome Surendra Kumar Verma. For more videos like this, Download COACHENGG App from Google Playstore or from the link below:
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IIT Bombay and a teacher on TH-cam. salute ur passion for teaching.
Thank you Aayush Bisht. Really glad that you liked our work.
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very best method for clearation of concept
Thank you Sameer.
*Sir,All your videos is very helpful to me. You teach brilliantly .Thank you so much!!^_^*
You are most welcome Manshi. Glad that our work is helping you.
Sir can we derive velocity at any instant t if we project the ball along the horizontally making no angle?? If yes then should we write i cap for velocity along x and y cap for velocity along y??? Plzz solve
Yes Samridhi. If you throw the ball horizontally from a height 'h' you can solve it just like a normal projectile. Use i cap for the motion along ground and j cap for the motion along the y-axis
very awesome explanation and the video was very useful.Thank you for devoting your time sir.😊😊
Thank you Sachin. Really glad that you liked our work.
You can also Download the COACHengg APP from playstore:
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really helpful and dedicated explanation. Thank you .
You are most welcome
Why not your all video is download please solve my problem
This was awesome..you cleared all my doubts sir..thank you!!
You are most welcome Bhagyashree Rao
Thanks for Very good explanation
You are most welcome Vineet Vajpai. For more videos like this, you can download COACHENGG App from Google Playstore or from the link below:
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Sir when we throw object at some angle acceleration along y-axis is -g so, how acceleration along y-axis is -g in this condition?
Hi Nikhil. Acceleration does not depend on the magnitude or direction of the initial velocity. Acceleration depends on the net force acting on a body. In the case of projectile motion, only one force is acting, i.e, mg, which acts in the vertical direction. That is why acceleration is in the vertically downward direction.
Sir how is the horizontal acceleration zero? Because when we are throwing it is obvious that we are applying a horizontal force on it . So shouldn"t there be any horizontal acceleration? Plz do clear it . It is my yearlong doubt.
Hi Himangshu. In discussing projectile motion the object is given an initial velocity (due to application of some forces by your hand, or by a gun etc.) . The analysis is done after this action. Once the ball leaves your hand or the bullet leaves the gun, there is no other force acting on it apart from gravity.
COACHengg so the ball moves only by the influence of gravity...Got it. Thank you
Bro because the body is moving with uniform and constant velocity along the horizontal path...
Thanku sir its really very helpful .
Sir why u take displacement along y axis is -h-0. ?
Displacement along y axis = final y coordinate - initial y coordinate = (-h) - (0). I have discussed how and why I chose the co-ordinate system in the first 3 minutes of the video
please upload video on river man & boat man problems.
Sure. Will post conceptual discussion after covering previous year JEE Main and NEET series
Yes sir plz upload this topic...especialllyyyy rain numericals😧
Thanku 😄
You are most welcome Aditi Choudhary. For more videos like this, download COACHENGG App from Google Playstore or from the link below:
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Thanks 😊 sir 🙏
You are most welcome Sushant Porkhrel. For more videos like this, you can also download COACHENGG App from Google Playstore or from the link below:
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Such a nice explaination
Sir how can we prove that the path followed in horizontal projections is parabolic?
the relation between y (vertical position) and x (horizontal position) is a quadratic equation. The graphs of quadratic equations are parabolic in shape.
Equation of trajectory
Equation of tragectory shows that the path is parabolic
thanx sir you have cleared my doubt.👌
You are most welcome Randhir Maurya
Brilliant, just brilliant
Thank you. Really glad that you liked our work
Sir isme ke energy minimum starting point pe hogi na?
Please reply sir
kinetic energy will be minimum at highest point. After that, as the object comes at lower levels, it PE decreases and KE increases
@@COACHengg4u if we talk about horizontal projection in which object is drooped (thrown horizontally straight) from a height then what will happen because starting point is already the highest point and it will continue moving towards the ground.
what is the meaning of height ascended??
Thank you so much for helping us🥰
You are most welcome Joydeep Paul. For more videos like this, download COACHENGG App from Google Playstore or from the link below:
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thank you sir. ..so much for clearing our doughts.....are you studying in iit bombay
You are most welcome Tarang. I graduated from IIT Bombay in 2009
Thanx a lot
Huge thanks to you
You are most welcome Piyush
Great work , very useful for me👍👍
Thank you Raj Saini. Really glad that you liked our work.
You can get access to more vidoes like this on our android app "COACHENGG" which you can download from google playstore or from the link given below:
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All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.
Amazing!!
Thank you Nisha Sharma. For more videos like this, download the COACHengg APP from playstore or from the link given below:
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Awesome
Thank you. Really glad that you liked our work.
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Amazingg!!!!!
Thank you Nisha Sharma. For more videos like this, download COACHENGG App from Google Playstore or from the link below:
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Really helpful😊
Glad that we could help you Captain Sups_Xd. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below:
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Thanks a lot. Really helpful.
You are most welcome.
Thank you! It was very useful.
You are most welcome Vamsi Krishna
Very nice and helpful, kudos god bless you
Sir very nice channel for students thanks sir
You are most welcome cbse education. Really glad that you liked our work.
We also have an android app "COACHENGG" which you can download from google playstore or from the link given below:
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All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.
Very nice sir! Thanks a lot!!
But 1 question...
When you project the object above the horizontal at an angle, then the height should be greater than h, shouldn't it?
If you throw at angle above the horizontal the maximum height will be more than the height of the tower. If you throw horizontally or below the horizontal level at some angle, then the maximum height above the ground will remain as the original height from which the body was thrown. I have discussed all the three cases in the video.
Best explanation...
U r definitely from iit Bombay...god bless u.
Thank you for the kind comment Abhilash Tyagi. Really glad that you liked our work.
We also have an android app "COACHENGG" which you can download from google playstore or from the link given below:
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Sir ek question hai
Velocity and directions at height
Best explaination sir
Thank you Keshaw.
You can also Download the COACHengg APP from playstore:
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Thanks sir good vedio . Please sir make a vedio free body diagram related to problems 😊😊😊☺
You are most welcome Priyu Mina. Will post the FBD videos too. In the meantime you can watch NEET and JEE Main FBD related solved numericals in these videos - th-cam.com/video/lFQ1YZiTfUc/w-d-xo.html
th-cam.com/video/o5vd279nlog/w-d-xo.html
one thing sir...g is acting downwards,the object is also going downwards,so g will be positive,how come u are taking it as negative
Hi Nishant. We use +ve and -ve signs in front of vectors to specify their direction. We can choose any convention to do that. You can either choose upwards positive or downwards positive at the beginning of your discussion. Whatever convention you choose, apply it properly to all vectors (displacement, velocity, acceleration). If applied correctly the answers will remain the same. If I take upwards positive in this question, all the terms in the vertical direction will be negative (displacement, velocity, acceleration). So when you make the equation of motion, the -ve signs will cancel out on both sides of the equation and the answer will come out as the same as if you had chosen the opposite convention
u derived as sx twice and plz solve the quadratic equation
good
thank you
Sir quadratic equations solve please
Thanks sir
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Sir u are the best teacher
Thank you Seema Sharma. Really glad that you liked our work.
Love sir😘😘😘
Thank you Nazish Khan. Really glad that you liked our work.
We also have an android app "COACHENGG" which you can download from google playstore or from the link given below:
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you are really good teacher
l have put 5 star your channel
Thank you so much Manjibhai Bhingaradiya. Really glad that you liked our work. We also have an android app.
You can download the COACHengg APP from google playstore or from the link given below:
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Best explanation
Thank you Soumyashree Priyadarshini
I was unable to attend my jee class in which this topic was taught ,u r video saved me
Really happy that our work helped you.
lot of thanks
sir
Best
Thank you Yash. Really glad that you liked our work.We also have an android app "COACHENGG" which you can download from google playstore or from the link given below:
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All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
Hathanks sir
You are most welcome Monika Raghuwanshi. Really glad that you liked our work. We also have an android app "COACHENGG" which you can download from google playstore or from the link given below:
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All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small monthly subscription fee.
hello sir, i am preparing for NEET without any coaching totally depending on internet and as most of students i am poor at physics. but i am so unfortunate that i found you today!!! so, i am asking you if are there other chapters like SEMICONDUCTORS,PROPERTIES OF MATTER, ELECTROSTATICS,THERMODYNAMICS,OPTICS.... etc. most important chapters for NEET in your free videos, or is there any other way for purchase your videos ?
Hello Tapas Ranjan Barik. You can download the COACHengg APP from playstore:play.google.com/store/apps/details?id=com.rdnc.coachengg. All our content is organized there subject wise and Chapterwise along with assignments, tests and doubt discussion forum.
As of now, it is completely free and later we will be charging a very nominal monthly fees for it.
thank you very much, but as i do not have an android could not i get those facilities to my PC ?
You are 'unfortunate' to find him? Lol!
Bhai plz ek yesi hi video friction pr banado
Sir very nice explaning lekin bahut ad aa gye
Priyanshu Rawat Ads nhi aayenge to unko payment kaise milegi?
why ay is -g?
I have chosen the sign convention as upwards positive. So all vectors in the downward direction will be chosen as negative.
Thankyou sir...thnx a lot for making me understand this concept so clearly...I was so tensed coz I was not getting projectile but now I can solve everything...
You are most welcome Sizzling Martina. Happy to help you.
Use English please
damn. why cant he speak english
Roses are red, Violets are blue, Your title's in english, so why arent you?
Thanks sir
You are most welcome Chintu Dansana. Really glad that you liked our work.
You can get access to more videos like this on our android app "COACHENGG" which you can download from google playstore or from the link given below:
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All our content is organized there subject wise and Chapterwise along with assignments, and doubt discussion forum and you can access it for a small subscription fee.