Well done sir,i have learned alot from your lesson .i wish u were my chemistry teacher in from ss2,chemistry was my best subject from ss1 cause i had a very good chemistry teacher like you then .After the change of that chemistry teacher, i find it difficult to understand chemistry again .thank god I found you, my lack of interest in chemistry will change .god bless you ❤
When given “two” different temperatures and masses in a solubility question how do you go about it aside situations like these where it’s just one temperature
Sir what about question like this 25.0g of potassium chloride were dissolved in 80g of distilled water at 300⁰C, calculate the solubility of the solute in mole dm-³. (K=39, Cl=35.5). We were given two grams and volume was not given. How do we go about it Sir
According to the formula for calculating solubility in (g/mol), molar mass is not in the formula but some questions use to come with molar mass. What do I do in such cases? Is it just for confusion or what?
The formula from for solubility is mole/volume in dm³..but I your given mass and not mole,you use molar mass to find the mole fpr you to find the solubility....am I right?
Please sir how is 4 the answer. I have been trying to make Mass the subject formula. So I did M= solubility*1000/molar mass* volume Please am I correct. My answer was 0.04
Sir help me on how to solve this type of question in solubility. Below is the question. The solubility in mol dm-³ of 20g of CuSO4 dissolved in 100g of water at 180° is? [Cu = 64, S = 32, O =16]
Please when I tried to calculate example 2 on my own I got 0.648 as my answer and then the answer for the question you gave is 0.196 did I miss a step?
I think that is not possible, because if there are asking us to find the solubility that means the parameters for mass, molar mass and volume will be given
Sir you have just made me to understand this topic, thank you sir.
I love ur teaching sir.. easily understood
Glad to hear that
My son is really findings ur classes very helpful......thank you sir ❤❤❤
Thank you so much sir, your teaching is well understood, the answer is 4g
Well done sir,i have learned alot from your lesson .i wish u were my chemistry teacher in from ss2,chemistry was my best subject from ss1 cause i had a very good chemistry teacher like you then .After the change of that chemistry teacher, i find it difficult to understand chemistry again .thank god I found you, my lack of interest in chemistry will change .god bless you ❤
Sir my answer was 2.72g.please let me know if am right thanks
You are God sent.
Thank you sir
Now I understand this topic 🎉
Thank u so much sir... The teaching is well understood...
The answer is 4g
Thanks nurse bright..... God will surely bless u
Wonderful teachig
Thanks so much for this tutorial,you don't know how much you've helped me
Thank you so much. You made me understand better
Thank you sir, God bless you 🙏🙏
really good teaching
Very sharp and clear. Thank you very much Sir. The answer is 4g
very Correct
I like the way u teach God bless u sir
The final answer is 4g , thank you very much sir may Almighty God bless you in return
Very clear and concise, thank you.
The answer is 4g.
very Correct
@Nurse Bright I can't thank you enough sir
How do I contact you directly please
You are welcome❤️
You can contact me on WhatsApp via my Number
08128927392
Thank you for this comprehensive video nurse bright🥰
Clearly understood sir❤️
The answer is 4g
very Correct
When given “two” different temperatures and masses in a solubility question how do you go about it aside situations like these where it’s just one temperature
Ok.. I will Soon provide a Video on that Aspect anticipate ❤️
Thanks for the lesson sir🙏
The answer is 4g
Thank you so much sir for this tutorial
4g sir. I so much love your teaching. Thank you sir and God bless you. Amen. ❤🙏
The answer is 4g
Very correct
Yeah that's what I got too
Pls how did you get it?
4g sir. Sir your the best I totally understood 🎉I really appreciate 🙏
The mass in grams of the compound is 4g
Sir pls what if u were given a question on solubility and Na2CO3 was present in 500cm3 of 0.01mol/dm3,how will you solve for it?
You're a great teacher
You are welcome
Keep sharing with friends
Thank u very much sir
God bless u
Thank you very much, the answer is 4g
Very Correct
The answer to the question you asked is
Mass = 4g
Am learning a lot my brain is open now
Thank you sir
Pls solve problems on electrolysis
Intelligent
Well understood sir
Mass=4g
Very correct
Keep sharing with friends
Plsss explain
Pls explain
Superb
I love ur teaching. It very understandable. Thanks 😍
Happy to hear that! Keep sharing with friends
Thanks sir i got 0.4g
It's 4g
Sir please is there any video on how to solve Graham's law of diffusion of gases
th-cam.com/video/YAxnrawuXLQ/w-d-xo.html
I already have a Video lesson on the Class Lesson
Here it is
Go watch and Master the aspect
@@NurseBright thank you sir
thank you sir
God bless you sir
The ans is 4g
Amen❤️
You are welcome 💥
Thank you so much sir... I got 4g
Thank you sir
My answer is 4g
Sorry plz rate of chemical reaction
Very Correct
Sir what about question like this
25.0g of potassium chloride were dissolved in 80g of distilled water at 300⁰C, calculate the solubility of the solute in mole dm-³. (K=39, Cl=35.5).
We were given two grams and volume was not given. How do we go about it Sir
You have nothing to do with the second mass
Answer is 0.336mol
4g sir, thanks for your teaching
I love your lecture
Thanks❤️
Keep sharing to others
Sir my answer is 4g. Thank you sir.
Thanks so much sir
The answer is 4g
Very good
Thank you very much Sir
So nice of you
0.04g is it correct
Sir please i need to be clearified
Thanks OBO 🙌
I got 4g
Great 👍
Thanks for the leason
The answer is 4g
Very correct
Thanks for your tutorial
Sir the answer is 4g
Thank you
Very good
You can decide to devide the volume by 1000 and use it in the first formula as well
Yeah
Thank you sir 🙏
Please I have a question? So we don't even need the temperature
According to the formula for calculating solubility in (g/mol), molar mass is not in the formula but some questions use to come with molar mass. What do I do in such cases? Is it just for confusion or what?
The formula from for solubility is mole/volume in dm³..but I your given mass and not mole,you use molar mass to find the mole fpr you to find the solubility....am I right?
Thank you sir
The answer is 4g
Very correct
I am so glad my video lessons have impacted you greatly. Keep sharing with friends
I'm confused is it 0.4g or just 4g
What if we weren't given volume but only the temperature and the mass of a liquid?
Please sir how is 4 the answer. I have been trying to make Mass the subject formula.
So I did
M= solubility*1000/molar mass* volume
Please am I correct.
My answer was 0.04
Solubility = Mass*1000/molar mass*volume
Mass = solubility*volume*molar mass/1000
Molar mass= 100
Volume= 100
Mass = 0.4*100*100/1000
Mass = 4g
No, it is actually, solubility*molar mass*volume*1000😁
Like even me self
0.4=mass*1000
100★100
Omo Na 0.04
Thanks allot
Sir the answer is 4g
Sir help me on how to solve this type of question in solubility. Below is the question. The solubility in mol dm-³ of 20g of CuSO4 dissolved in 100g of water at 180° is?
[Cu = 64, S = 32, O =16]
Okay it's Very Easy
If the volume is in cm^3 the answer is 1.25 but if it is in dm^3 then the answer is 0.00125
Cm or dm?
understood 😊
Thank you 😊 4g
Very Correct ❤️💥❤️
Keep sharing with Your Friends
Please when I tried to calculate example 2 on my own I got 0.648 as my answer and then the answer for the question you gave is 0.196 did I miss a step?
Actually it's 4g sir nice is so easy
Sir what if we are give two masses or no volume and uet we're still looking for solubility
Or we're given volume but no mass and solubility
I think that is not possible, because if there are asking us to find the solubility that means the parameters for mass, molar mass and volume will be given
@@Victorgeorgeanimations yes dear you are right
Thanks sir
You are welcome
Sir pls hlp me out I didn’t get the Answer 😢
How will you know when to solve in mol/dm³ or g/dm³ if you aren't given the instruction
They right it in question
Sir am getting 0.18 am confused
I make M subject of the formula
0.4×204×100=x×1000
181.6/1000=1000x/1000
X=0.18
Mass=0.18
0.4g
My answer is 4g
Very correct
What if we are to look for the mass
4g,Thanks
the answer i got for the mass was 4
Very Correct
4.64g
Thanks you so much sir ☺️
You are welcome ❤️
The answer is 31.25
M=4
Big Thanks
Sir Thanks so much 🥺
The answer is 4g🤔😅🎉
My answer is 4g👌
The mass is 4g
Very Correct ❤️
Mass= 4.64g
the answer is. 960g
Mass =4g
very Correct Braimah
@@NurseBright am blessed from WhatsApp am using my dad's phone
My phone got bad
@@aminubraimah6355 Ohk
Accurate
0.04g
0.04
4g
The answer is 40.4g
Then why you did not solve it . For us so we can know it
I got 0.04 ??
4.6g
The answer to the question on mol/dm3 is 3.52g
Very correct
Keep sharing with friends
Answer is 3.76grams