Thank you so much sir, but pls do video on oxidation and reduction on how to know oxidizing agent and reducing agent,I know it will be 100% helpful....
I have been waiting for this video to drop, and finally, the great OBO has done another wonders, The great OBO of chemistry just know we ur fans love and look up to u, God bless you for the help u have rendered to some people and I, Thanks for the video🙏🙏🙏🤭
the second question....chlorine gas is the limiting agent
theoretical mass=15.91g
actual mass=12.3g
%age yield=77.36%
Thank you so much sir, but pls do video on oxidation and reduction on how to know oxidizing agent and reducing agent,I know it will be 100% helpful....
God bless you 🎉🎉🎉🎉
Q1
Theoretical yield is 24.765g
% yield= 20.5 ×100/24.8 =82.7%
Honestly speaking sir am so thankful for this lesson , I am hundred percent sure that I can solve any stoichiometry questions given I appreciate sir❤
A masterpiece indeed❤❤
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You're really a great help, you help me alot sir especially in chemistry thank you May God bless ❤❤
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I will try my best sir
Thank you
God bless you🙏🏾
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I've been waiting for this video since like forever thanks nurse bright ♥️
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Theoretical yield 40.99
Percentage yield 50.01%
Thank you so much sir you really don a great help sir please do a video on oxidation and reduction reaction it will be helpful sir. Thank you sir
I have been waiting for this video to drop, and finally, the great OBO has done another wonders,
The great OBO of chemistry just know we ur fans love and look up to u,
God bless you for the help u have rendered to some people and I,
Thanks for the video🙏🙏🙏🤭
I am glad my videos have impacted you greatly Christopher ✨
@@NurseBright yes it has Nurse, u re really the best trust me
God bless you
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Q2
% yield of CCl4=77.4%
Tysm❤️
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Pls do another vid in theoretical yield and percentage yield
Alright
Q1: moles of HI=0.195 moles
8HI= 4I2
8mol = 4moles
0.195 = x
X= 0.0975 moles of I2
Mass of I2= 0.0975×254= 24.8g
% yield= 20.5/24.8= 82.6%
Dont let the excess h2so4 confuse you.
Q2: no of moles for cl2 = 0.31
No of moles for CS2 = 0.237
3Cl2 = CS2
3mol= 1 mol
Xmol = 0.237
Xmol= 0.71
3CL2 = CS2
3MOL = 1MOL
0.31= XMOL
XMOL= 0.103.
Cl2 is the L.A
3CL2 = CCL4
3MOL= 1MOL
0.31= XMOL
XMOL= 0.103MOL
MASS OF CCL4 =
0.103×154= 15.9
12.3/15.9× 100= 77.35.
Very correct ✨
❤
Pls solve the second practice question
I think I'm confused
Question 1: theoretical yield: 12g while percentage yield: 165%
Question 2: percentage yield:27.9%
Please explain how you got the answer especially the no of moles for h2so4
Wow
Theoritical yield for question one is 1122, while percentage yield is 1.827
Question 2
% yield is 2.09898
So it's correct
Good afternoon everyone, please can someone help me write out the question no.2 is not clear in my phone
Thank you .
Question 1: theoretical yield is 50.8
Percentage yield is 40.35%
Sir is the answer correct
No
Hi
Explicit
Q1 Theoretical yield =107.115g and Percentage yield = 19.14%
Q2 Percentage yield= 25.8%
This method is too long sir
Question 2: theoretical yield is 15.9
Percentage yield is 77.36%