Excuse me sir hamare vit vellore me signals and systems me Hilbert transform and processing of bandpass signals bhi dal diya hai aur wo koi bhi topic ya youtu be pe structurised nahi mil Raha, please make a video on these topics too 🙏🙏🥺😭
Impulse has infinity amplitude and it has a unit area. Why you are saying that value is 1? How CT Dirac function converted to the DT Dirac function? If the amplitude is 1, there is no area, so the integral is zero.
Thanks for raising question, Yes, you are absolutely right. the amplitude of impulse function is not 1, rather the are under the pulse if 1. And when we create samples practically they are not discrete time functions but pieces of continuous time function. But if we consider the width of impulse function tending to zero. Approximately (for simplicity so that beginner students can understand the concept) we can explain taking the amplitude as 1. I admit this is not the standard way but i find it helpful for students to understand the concept. NOTE: Students who went deeper side of the topic please consider the point raised by blackseastorm 61 research more on the topic.
@@vinaysingh-xi1sw Thank you for explanations. I am stucked at this point. The problem is, how we obtain a DT function by using this CT impulse function. It has value of infinity. I don't understand how we transform impulse to the discrete-time as its amplitude is 1. How this process/conversion works ? I have problems on converting CT to DT, I am trying to watch several videos about it, but the actual mathematical operation of "converter" is not clear. What I mean is , what is the operator that converts ""impulse(t) >> to impulse[n] with amplitude of 1"" or ""x(t) . p(t) impulse train >> to x[n] as a sequence"" x(t) . p(t) could be represented as = summation of the series of x(nT) . impulse ( t - nT ) But this is still not equal to a sequence of x[n] , because it contains scaled impulses with amplitude of infinity, right? Therefore I am trying to understand what actually this conversion and this impulse are. What is the title of topic/video that covers this point?
@@tıbhendese If i understood your confusion, i think you are confused with the mathematical calculations. x(t) . p(t) could be represented as = summation of the series of x(nT) . impulse ( t - nT ) In above expression dot (.) is convolution operation not simple multiplication. both are different operations. Please go to video th-cam.com/video/1pJ5ie2hX1M/w-d-xo.html for understanding the convolution of a CT function with impulse. The second point is summation of the series of x(nT) . impulse ( t - nT ) , here summation does not mean the addtion of all the samples but samples at time instants like T second, 2T second and so on. To simplify solve the convolution for n=1 first then n=2 following the video i suggested and analyze the results. A lot of things will be clear to you.
@@vinaysingh-xi1sw For the expressions "x(t) . p(t)" and "series of x(nT) . impulse ( t - nT ) " I have almost never seen that is written as convolution instead of multiplication. In the videos I watched, they all write this by multiplication, therefore I noted it like that. Secondly , " x(t) * impulse(t) = x(t) " so it dont satisfies with "" summation of the series of x(nT) . impulse ( t - nT ) = x[n] as a sequence"" I am still confused about how this conversion works " impulse(t) >> to impulse[n] with amplitude of 1" And its getting much more complicated each time :(
I appreciate your efforts sir.
Nice explanation.
thanks dear
Thank you ❣️☺️☺️💞
You’re welcome 😊
nice explanation sir
Thanks
Excuse me sir hamare vit vellore me signals and systems me Hilbert transform and processing of bandpass signals bhi dal diya hai aur wo koi bhi topic ya youtu be pe structurised nahi mil Raha, please make a video on these topics too 🙏🙏🥺😭
ok sure
Impulse has infinity amplitude and it has a unit area. Why you are saying that value is 1? How CT Dirac function converted to the DT Dirac function?
If the amplitude is 1, there is no area, so the integral is zero.
Thanks for raising question, Yes, you are absolutely right. the amplitude of impulse function is not 1, rather the are under the pulse if 1. And when we create samples practically they are not discrete time functions but pieces of continuous time function. But if we consider the width of impulse function tending to zero. Approximately (for simplicity so that beginner students can understand the concept) we can explain taking the amplitude as 1. I admit this is not the standard way but i find it helpful for students to understand the concept. NOTE: Students who went deeper side of the topic please consider the point raised by blackseastorm 61 research more on the topic.
@@vinaysingh-xi1sw Thank you for explanations. I am stucked at this point.
The problem is, how we obtain a DT function by using this CT impulse function. It has value of infinity.
I don't understand how we transform impulse to the discrete-time as its amplitude is 1. How this process/conversion works ?
I have problems on converting CT to DT, I am trying to watch several videos about it, but the actual mathematical operation of "converter" is not clear.
What I mean is , what is the operator that converts ""impulse(t) >> to impulse[n] with amplitude of 1"" or ""x(t) . p(t) impulse train >> to x[n] as a sequence""
x(t) . p(t) could be represented as = summation of the series of x(nT) . impulse ( t - nT )
But this is still not equal to a sequence of x[n] , because it contains scaled impulses with amplitude of infinity, right?
Therefore I am trying to understand what actually this conversion and this impulse are.
What is the title of topic/video that covers this point?
@@tıbhendese If i understood your confusion, i think you are confused with the mathematical calculations.
x(t) . p(t) could be represented as = summation of the series of x(nT) . impulse ( t - nT )
In above expression dot (.) is convolution operation not simple multiplication. both are different operations. Please go to video th-cam.com/video/1pJ5ie2hX1M/w-d-xo.html for understanding the convolution of a CT function with impulse.
The second point is summation of the series of x(nT) . impulse ( t - nT ) , here summation does not mean the addtion of all the samples but samples at time instants like T second, 2T second and so on. To simplify solve the convolution for n=1 first then n=2 following the video i suggested and analyze the results. A lot of things will be clear to you.
@@vinaysingh-xi1sw For the expressions "x(t) . p(t)" and "series of x(nT) . impulse ( t - nT ) " I have almost never seen that is written as convolution instead of multiplication. In the videos I watched, they all write this by multiplication, therefore I noted it like that.
Secondly , " x(t) * impulse(t) = x(t) " so it dont satisfies with
"" summation of the series of x(nT) . impulse ( t - nT ) = x[n] as a sequence""
I am still confused about how this conversion works " impulse(t) >> to impulse[n] with amplitude of 1"
And its getting much more complicated each time :(
ok I will see deeply to your doubt n will come up with a solution.
Statement?
Sorry I didn't understand what is your query.