31. Convolution Theorem | Complete Concept and Problem#1 | Inverse Laplace Transform

[@anushkakrishna2829]

2sinAcosA=sin(A+B)+sin(A-B)
2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)+cos(A-B)
2sinAsinB=cos(B-A)-cos(A+B)

[@hafizmuhammadosamahasssan1330]

*2sinAcosB = sin(A+B)+sin(A-B)
*2 sinAsinB = cos(A-B)-cos(A+B)

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[@subhashreesahu692]

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[@fanfsty.]

I have followed each and every video of yours regarding this chapter since the beginning and the results are quite good so far. Bunch of thanks 🙏🏻 sir

[@eternalknight2958]

2 cos(a) sin(b) = sin(a+b) - sin(a-b) , thank you sir for your work

[@pratyush2331raj]

2.SinA.CosB = Sin(A+B) + Sin(A-B)
2.CosA.SinB = Sin(A+B) - Sin(A-B)
2.CosA.CosB = Cos(A+B) + Cos(A-B)
-2.SinA.SinB = Cos(A+B) - Cos(A-B)

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[@gamerznetic]

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[@priyanshuchaturvedi3706]

2sin(a)cos(b)=sin(a+b)+sin(a-b)
2cos(a)sin(b)=sin(a+b)-sin(a-b)
2cos(a)cos(b)=cos(a+b)+cos(a-b)
2sin(a)sin(b)=cos(a-b)-cos(a+b)

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[@NITSRINAGAR786]

Thanks so much teacher

[@rakhipikopiko1467]

Thanks to the right place

[@NITSRINAGAR786]

2cosAsinB=sin(A+B)-sin(A-B)

[@mukundhanthanigaimurugan9253]

Good experience

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[@somansoman8162]

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[@karthikdiploma1946]

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[@abcd-gp6is]

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[@deepakkumarmohanty6182]

2CosA.SinB=Sin(A+B)-Sin(A-B)

[@kapilkhankure4685]

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[@dr.rahulgupta7573]

सर,Laplace transform सीखने के लिए कौन सी किताब पढ़ें ?

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Yes

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[@arjunsuthar3641]

2sincos=sin+sin

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[@umeshsilk9500]

2.SinA.CosB = Sin(A+B) + Sin(A-B)
2.CosA.SinB = Sin(A+B) - Sin(A-B)
2.CosA.CosB = Cos(A+B) + Cos(A-B)
-2.SinA.SinB = Cos(A+B) - Cos(A-B)

[@abhinandanjain2399]

Thank you so much sir ji 🙏

[@dinkark98]

2sinAcosB =sin(A+B)+sin(A-B)
2cosAsinB =sin(A+B)-sin(A-B)
2cosAcosB =cos(A+B)+cos(A-B)
2sinAsinB =cos(A-B)-cos(A+B)

[@rashikaverma5261]

Thank u sir

[@Rajanandz]

2cosA.sinB = sin(A+B) - sin(A-B)

[@Sunilkumar22341]

Thanks sir

[@letsdestroy8624]

Yes

[@vdo9372]

2sinAcosA=sin(A+B)+sin(A-B)
2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)+cos(A-B)
2sinAsinB=cos(B-A)-cos(A+B)

[@nissahgkvideos2112]

Thank you sir

[@fallacyfallacy1634]

2cosAsinB=sin(A+B) + sin(A-B)
2cosAcosB=cos(A+B) + cos(A-B)
2sinAcosB=sin(A+B) + sin(A-B)
2sinAsinB=cos(A-B) - cos(A+B)