32. Convolution Theorem | Complete Concept and Problem#2 | Inverse Laplace Transform

[@dinkark98]

2sinAsinB=cos(A-B)-cos(A+B)

[@nikhilraj5343]

Sir Thanks Is Not Enough You Get Blessings of students especially.in this Exam time . I haven't read much trying to watch as much as possible of your videos

[@aayushisingh7587]

2 SinA.SinB= Cos(A-B ) - Cos(A+B)

[@SanMalli]

Thank you so much sir for this kind of amazing video ❤️ lots of love by an engineering student ❤️ from Nepal 🇳🇵🙏

[@jassu..5685]

Ultimate explanation Sir...out of words 🤐🤐

[@SAIKUMAR-wp8zj]

2sinasinb=cos(a-b)-cos(a+b)

[@kalash_kale]

Thankyou Sir🙏🏻

[@kumardigambar1664]

Thankyou so much sir 🙏🙏🙏

[@anujsingh116]

Amazing ♥️🙏

[@abhishekjangid6626]

Nice handwriting sir

[@abcd-gp6is]

Thank you sir 💜✨

[@saloniee2969]

2sinAsinB=cos(a-b)-cos(a+b)

[@ayanavadas6154]

2sinAsinB= -{cos(A+B)-cos(A-B)}

[@AJ-sb5kz]

Thank you sir 🙏

[@luckyraghav8125]

❤thnx sir

[@mohanishshevde3548]

Thank you sir!!!

[@vivekrawat6822]

Thanks sir ur great

[@vanshvansh3484]

Awesome ❤

[@totalgamingshortvideo9919]

Cos(a-b) -cos(a+b)

[@deepakkumarmohanty6182]

2CosA.CosB=Cos(A+B)+Cos(A-B)

[@jayasondhi6906]

2sinA.sinB =sin a+b - sin a-b

[@itishreenaik1147]

Sir plz make videos on linear algebra

[@krishnasharmavairagi8597]

2SinASinB=Cos(A-B)-Cos(A+B)

[@rudreshpareta3894]

2sinAcosB=sin(A+B)+sin(A-B)
2cosAsinB=sin(A+B)-sin(A-B)
2cosAsinB=cos(A+B)+cos(A-B)
2sinAsinB=cos(A-B)-cos(A+B)

[@Tejuh_tej]

*3rd 2cosA cosB =cos(a+b)+cos(a-b)

[@prashantsharma7788]

❤️❤️❤️❤️❤️

[@imu5728]

2SINASINB=COS(A-B)-COS(A+)

[@pankajchoudhary2668]

thank you so much

[@jayjethva814]

Sir what will be the lapcalce inverse of 1/(s^2+w^2) ^2 by convolution theorem

[@trayoudhnpatil3238]

Sin(A+B) - Sin (A-B)

[@rajeshbonala6078]

Nice sir

[@weirdo1114]

Thank you sir

[@jasigupta]

Nice explain sir

[@AjayKumar-yy8xp]

Sir can you plz send me more questions of Laplace transform . In lockdown I have no books and I am not getting questions to solve .sir plz help me 🙏🙏🙏🙏

[@deepakkumarmohanty6182]

Yes Sir🙏🙏🙏

[@ownpreacher]

2sinA.sinB = [Cos(A-B)] - [Cos(A+B)]

[@rajuchitrapu4903]

Sir m2 imp questions chapandi

[@jasigupta]

Sir Fourier series par lacture banaye

[@ManojKumarSahoo]

FOURIER SERIES (Complete Playlist): th-cam.com/play/PLhSp9OSVmeyLke5_cby8i8ZhK8FHpw3qs.html

[@tarunparjapati6185]

Sin(a+b)+sin(a-b)

[@samankhan8066]

can you solve it for me plz
..?
h(t)=1*sin(wt)

[@ajaynarayan_editon_009]

Sir 3p+2/4p2_4p+3 bala solved kijiye

[@vinaychavhan434]

Sin ( A - B ) - Sin ( A + B )

[@subhadranaringika6525]

2 SinA SinB=Cos(A-B)-Cos(A+B)

[@tanvirhossainreza735]

2sinA.SinB=Cos(A-B)-Cos(A+B)

[@monikameena3467]

2SinAsinB=cos(A-B)-cos(A+B)

[@Mumtaz_________3200]

2sinASinB=cos(A-B)-cos(A+B)

[@niralithakur1257]

2sinAsinB= cos(A-B)-cos(A+B)

[@nehalchouhan9476]

2sinAsinB= cos(A-B) - cos (A+B)