Lecture 04: Mesh Analysis - I

[@Shivam-nj9ly]

17:45 Mesh analysis starts👍.

[@pratikchaudhari5371]

35:40 should be (-)

[@tajaramsingar7437]

very very nice concept explain ,dhanayawad sir

[@gmoinpatel]

i wonder to attained this lecture, Super explanation, one of the best teacher ever.

[@yashkaushik9166]

I think that the equation of mesh 3 should be -
+(R1 + R4 + R3)*I3 - (R1*I1) - (R3*I2) = 0

[@subeyrbashir4138]

Yeah.. you are right.

[@akshatsharma5426]

yes

[@chandangupta3731]

Yes

[@funnymoment4543]

Yes

[@AdityaSingh-uj3ko]

3:04 SHORT CIRCUITED*

[@AdityaSingh-uj3ko]

2:52 SHORT CIRCUITED*

[@-EE-AAYUSH]

Shukriya 🙏

[@practiceofbramcharya1053]

great teaching sir

[@nimeshsingh9271]

👌🏻👌🏻

[@-ARBAAZ_58]

Thnku sir

[@aadhithkrishna5682]

How top to bottom will be i1-i2?

[@nimeshsingh9271]

At R2, i1 flows from top to bottom and i2 bottom to top. Hence total current would be i1-i2 top to bottom or i2-i1 bottom to top.

[@thefirstprinciplesguy4371]

@@nimeshsingh9271 i1-i3 flows from top no?