Thanks. In order to get the beta hydride 'syn elimination' to form the palladium hydride (and eta 2 pi-complex), the palladium (II) species locks itself so that aryl group is further away from the carbonyl (this just relieves steric hindrance and torsional strain). If you can access Heck's papers then the syn elimination is mentioned in JACS (1974), 96, pg1133. Hope this helps.
it makes beta hydrogen elimination, so You are saying this a little bit incorrect and addition of palladium after pi complex formation should be called insertion of alkene
Thanks. In order to get the beta hydride 'syn elimination' to form the palladium hydride (and eta 2 pi-complex), the palladium (II) species locks itself so that aryl group is further away from the carbonyl (this just relieves steric hindrance and torsional strain). If you can access Heck's papers then the syn elimination is mentioned in JACS (1974), 96, pg1133. Hope this helps.
Thanks for adding this! You are the only one with a tutorial on this! Would you be able to elaborate on what happens between step 3 and 4?
it makes beta hydrogen elimination, so You are saying this a little bit incorrect
and addition of palladium after pi complex formation should be called insertion of alkene
Please improve u r writing skills after allit's the 1st expression of ur video
arabic please
😂😂😂 no