Extractions | Chemical processes | MCAT | Khan Academy
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- เผยแพร่เมื่อ 16 ก.ย. 2013
- Learn about how chemicals can be separated through acid-base extraction. By Angela Guerrero. . Created by Angela Guerrero.
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Clear explanation and clear writing!! Thank you so much!
Wow!! Very helpful!! Thank you so much
Great explanations. Much better than the other Khan Academy teachers, no offense to the others, of course. You're all better than the many horrible professors college kids pay thousands for!
You literally made so much sense that I finally understand the MCAT question in regards to extractions. Just to clarify I would use a weak base to tackle one of the acids if I have 2 acids?
Yes
extremely helpful!
thank you so much !!!
Thank you so much now I understand
Nice explanation thank you
I'm incredibly impressed by how easy you write using a cursor, in cursive, no less! I expect you're using a tablet. Still, it's impressive!
Nice video. Thanks.
Probably uses a pen on a tablet device like Sal.
Omg thank u so much !! 😍😍
super helpful :)
Good explaination ........
I never understood this in college, and all it took was one video on studying for the MCAT and now I feel like I'm a master! Thank you
thank you . You just helped me ♡-♡
In your 1st example, are you starting out with a known mixture of two compounds you must separate, or do you take each individually, then mix them, and then separate - in which case, that would make little sense, right?
Mild bases can't deprotonate weak acids but in this example (7:05) it can deprotonate acetic acid? Why?
Although both have resonance structures in their conjugate bases, O bears the negative charge on acetate ion whereas C bears the negative charge on phenolate anion. Since O is more EN atom than C, acetate ion is more stable. More stable conjugate base means stronger acid.
Lmao just imagine recovering 1 substance from the waste container 😂
I rather just redo the original extraction
Good video tho
Thanks 💕
ty even helping me a year later
Too good
So, basically, NH2 is neutral, and we want to make it polar so it goes to the aqueous phase. It can do this by stealing hydrogen and reacting with H-Cl. The phenol's OH was neutral, and we want to make it polar, too. To do this, it needs to get deprotonated so it can enter the aqueous phase.
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Isn't aqueous phase at the top while organic phase at the bottom? Anything organic is denser than water. Particularly, DCM (dichloromethane) is organic solvent which is denser than water and obviously takes lower position in sep funnel.
Oil floats on water
Hi, there are two audios overlapping at around 01:05. I think you might have edited it. It's impossible to make out what you say in that like 2-3 second window
Why couldn’t phenol be in the Aqueous layer without being deprotonated? Isn’t it polar?
Why can't sodium acetate deprotonate phenol??
Bruh recovering from the waste container via extraction