iit madras is the biggest university in india. So the question isn't jee mains level, it's prolly above jee advanced level. The acceptance rate is like 0.01% there, every student has passed jee advanced exam with really good score to be there. Ofc it would be crazy
This question is actually at the mains level. The key is not to solve the entire integral; instead, you should focus on finding the ratio through minimal simplification. Questions of this type are commonly asked in the numerical section of the JEE Mains, and I admit that it is on the more challenging side of the paper.
Man I would have instantly use the cos2x formula to convert it in sin inside the root and also e powers derivatives is cosins argument dk if that would be good but just an intuition 😊
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Ayeee! You solved it quicker than I expected. GGs
@MayankXOR Thank you!!
When you did the triangel equation , I had laughed !! Hahaha
Complex substitution may greatly simplify
00:00 I just woke up bruh
LMAO
Me too
iit madras is the biggest university in india. So the question isn't jee mains level, it's prolly above jee advanced level. The acceptance rate is like 0.01% there, every student has passed jee advanced exam with really good score to be there. Ofc it would be crazy
This question is actually at the mains level. The key is not to solve the entire integral; instead, you should focus on finding the ratio through minimal simplification. Questions of this type are commonly asked in the numerical section of the JEE Mains, and I admit that it is on the more challenging side of the paper.
@@srivatsav9817 bahut pata hai mains level aur advance level...khuud toh syad LPU me betha hoga abhi😂😂😂
you dont have to yap abt JEE everywhere dude get over JEE its over
What ? Tu wahi hena jiska jee clear nahi huya ?@@Aditya-xp7tb
Cant we use expansion of e^x ? 2:05
Yes.............but itll be nasty
@@Silver-cu5up damn sounds nasty
Let me try lmao
@whyandhowdaushitenande oh no lol
Man I would have instantly use the cos2x formula to convert it in sin inside the root and also e powers derivatives is cosins argument dk if that would be good but just an intuition 😊
00:00 me at work
@@codyriceandothers LMFAO
Anyone get √2e^(3/2) as answer?
What event is this
@@potrjtfvjrfvbr Semifinals Integration Bee from IIT Madras
So unlucky ;_;
hi
@@vamshitarun4399 Wasabi!!
Rip
Hey what is your discord link?
Right here: discord.gg/U8Nknh5e
@@Silver-cu5up thanks!! Is it possible that this link has expired?
@@alexanderjerschow7504 oh crap, thanks for letting me know
@@alexanderjerschow7504 Here u go! discord.gg/PJSjwWPfcq
@@Silver-cu5up thanks!!
a=int[0,1](xe^((x^2-1)/2)•cos(x))dx
u=cos(x)
dv=xe^((x^2-1)/2)•dx
du=-sin(x)dx
v=e^((x^2-1)/2)
a=cos(1)-e^(-1/2)+e^(-1/2)•int[0,1](sin(x)e^(x^2/2))dx
B=int[1,3/2](e^2(x^2-2x)•sqrt(1-cos(4x-4)))dx
t=x-1
dt=dx
B=int[0,1/2](e^2(t^2-1)•sqrt(1-cos(4t)))dt
1-cos(4t)=2sin^2(2t)
B=sqrt(2)e^-2•int[0,1/2](e^2t^2•sin(2t))dt
u=2t
du=2dt
B=1/sqrt(2e^4)•int[0,1](e^(u^2/2)•sin(u))du
(a-cos(1)+e^(-1/2))/B=sqrt(2e^4)/sqrt(e)
=sqrt(2e^3)