Wait how did u find the initial sin and cosign angles for the magnitude equations. I understood how u got it for the first one, but you did the second one completely different
The idea is just adding together the x-component of B with x-component of C and y-component of B with y-component of C. In this case add the 30 and -3.5(which are the x components of B and C) to get the x-component of R. Then add 0 and 6.06 to get the y-component of R. is then the x and y components of the resultant
Amp, you only use “SOH CAH TOA” as a reminder of what trigonometric functions to use when solving a right triangle. In this case the video shows a problem involving the box and we are given the angle 21 degrees and the hypotenuse. We are trying to find the opposite side, so with “SOH CAH TOA” you can use Sine of Cos since they both have “H” or the hypotenuse in their functions. Yet, we use Sin specifically because with algebraic manipulation we can find the opposite side.
In example 2, isn't the bearing angle the clockwise angle made from the north? So with the reference angle in this case 24.4 degree, the bearing should be 90-24.4=65.6 degree?
When using Vector components we always use the angle in reference to the positive X-axis or “polar axis” since it was N60E we just figured out the remaining space and use that as our vector. Same with S45E we have subtracted 360 from it to find 315
Our teacher said that if you have notation like this 9m, 45° N of W is that, the west is your origin not the North. So if you plot that notation your 45 degree is in the west not in the North? Please tell me is it wrong or correct, I'm confused
Great question! N30W means you start at due north (which would be 90 degrees for us) and head 30 degrees west (or left) from there, which would lead us into quadrant II. 90 + 30 = 120. This way of describing bearing is more for navigational purposes, so it may be a bit confusing when you see it the first time... Hope that makes sense! Let me know if you have other questions!
in the first question why aren't there any negative components all the work is in the second quadrent so the x components should be negative or is this différents someone pls explain.
3:50 - Components of Vectors and Resultants
9:45 - Force
12:53 - Multiple forces on a stationary object
22:10 - Work
This video was so much better than any of the ones my teacher gave me. Thank you so much!!
Thank you so much for your help! I have a huge exam tomorrow and this was quite helpful!!!!
So happy you found it useful! Good luck on your exam, and thank you for watching!
Me too wish me good
thank you so much love from argentina
Thank you Ms. Rudy
You're a life saver !!
Wait how did u find the initial sin and cosign angles for the magnitude equations. I understood how u got it for the first one, but you did the second one completely different
what dont you have to aline the vectors with tip to tail im so confused
Same here
Thanks, made the whole process easy to follow
Thanks so much for your kind words! Glad it was helpful!
@@MathWithMsRuddy thank you mam
Why were you not my physics teacher :c this made vectors so much easier. Thank you!!!!!!!
Excellent video….thank you
i don't get how you got the r what is the process for adding B & C together? this is my first time taking physics so im tying to understand
The idea is just adding together the x-component of B with x-component of C and y-component of B with y-component of C. In this case add the 30 and -3.5(which are the x components of B and C) to get the x-component of R. Then add 0 and 6.06 to get the y-component of R. is then the x and y components of the resultant
amazing. thank you so much for this video, it helped A LOT
I’m confused, when do we use soh cah toa?
Amp, you only use “SOH CAH TOA” as a reminder of what trigonometric functions to use when solving a right triangle. In this case the video shows a problem involving the box and we are given the angle 21 degrees and the hypotenuse. We are trying to find the opposite side, so with “SOH CAH TOA” you can use Sine of Cos since they both have “H” or the hypotenuse in their functions. Yet, we use Sin specifically because with algebraic manipulation we can find the opposite side.
In example 2, isn't the bearing angle the clockwise angle made from the north? So with the reference angle in this case 24.4 degree, the bearing should be 90-24.4=65.6 degree?
Why is the angle of plane is 30 degrees? Isn't it 90? Thanks :)
When using Vector components we always use the angle in reference to the positive X-axis or “polar axis” since it was N60E we just figured out the remaining space and use that as our vector. Same with S45E we have subtracted 360 from it to find 315
AND IM FINALLY STARTING TO UNDERSTAND IT HAHAHA
Our teacher said that if you have notation like this 9m, 45° N of W is that, the west is your origin not the North. So if you plot that notation your 45 degree is in the west not in the North?
Please tell me is it wrong or correct, I'm confused
wow this absolutely amazing, thankyou
Why did you subtract from 180 to find direction instead if 90?
Mercy Fatolu she's looking for the reference angle from the X axis, 90 degrees would give you the reference angle from the y-axis.
@@md-engineering thanks
My question exactly
Why direction angle is 120 ?
Great question! N30W means you start at due north (which would be 90 degrees for us) and head 30 degrees west (or left) from there, which would lead us into quadrant II. 90 + 30 = 120. This way of describing bearing is more for navigational purposes, so it may be a bit confusing when you see it the first time... Hope that makes sense! Let me know if you have other questions!
Thank you for this video 😄😄 anyways correction 7cos120° = -3.5
that very helpful! keep going
Bravo, keep up your good work. Thank you, really appreciate your help..
Why is the w 270?
in the first question why aren't there any negative components all the work is in the second quadrent so the x components should be negative or is this différents someone pls explain.
The x components are negative?
things this really helped me
estoy viendo esto para mi examen de ingles
Where is the 180 degrees coming from
Thank you
Glad it was helpful! I have more videos and resources on my class website if you need more help! www.mathwithmsruddy.weebly.com
Lol it still ain’t easy sis
Maddie Waksmunski easier than it was before
Sis 😂
send help
Thank you!
What if I want to find the angle for the force ?
Thank you🙂😢
i feel so powerful
THANK YOU
ITS 4AM AND I HAVE A MATH FNAL TMMR
Tullex legend says she’s still watching this vid
Thx bro
is this CIE
Thanks MMMMMMMMMMMMmmm!!
You should have put the directions (i,j,k) to make it easier for people to understand.
lolo
hahaha how come it become the answer without exact formula and solutions .. you are less in teaching you seems copying only
I dont like her, she is manufacturing,, to someone