Mesh Analysis Example-Everything Part 2

Mesh analysis with independent and dependent current and voltage sources. Part 2. More instructional engineering videos can be found at www.engineeringvideos.org.
This video is licensed under the Creative Commons BY-SA license creativecommons.org/licenses/b....

[@playuhh]

i1 = 0.473A
i2 = -0.827A
i3 = -1.722A
i4 = 2.709A
Source: RREF Matrix on Ti-84

[@vienlacrose]

Correct.
Source: Multisim

[@user-co6pi1nj5q]

Same me

[@eipiplusone3791]

Thanks a lot for these videos!

[@naturefo2]

a~~0.47257 and b~~-0.82700 and c~~-1.7215 and d~~2.7089

[@MrDlbonano]

I1 = .47, i2 = -0.826, i3 = -1.7215, i4 = 2.708. Great video u just made a mistake by making the last equation to be 20i1 instead of -60i1

[@DarrylMorrell]

@acer57, @stephenxluo
Actually, I believe stephenxluo is correct that the voltage should be negative. The polarity of VB is defined so that I1-I4 flows from positive to negative, and I1-I4 is negative, so the voltage is negative. (This is what I have written, but I reversed it when doing the computation.) I will add an annotation to the video correcting this. Thanks for finding it.

[@kishorek9410]

mesh 4 current is wrong instead of -60i u solved as 20i

[@vxmshikrishnx]

Yeah he's wrong

[@johnnolen8338]

Mr. Morrell:
There is a mistake in your equation for Mesh 4. Should be: -60*I1 + 40*I4 = 80.

[@mnada72]

Thank you

[@acer57]

@stephenxluo because you take your leading current wich is the higher in magnitude and then you substract (BIGGER - smaller) which in this case is (1.9-.19)(40) = 68

[@DarrylMorrell]

You are correct. I have updated the annotations to show this. This is why I really don't like mesh analysis...

[@aashalash40]

i know this is old but im using my ti84plus to solve the systems of equations and im getting a different answer, this works with 3 equations up to I3 for me but wont work for this, please help.

[@johnwang3293]

Where did he get 0.559 from from the equation Vb = 40(0.559-2.709)?? did he make another mistake?

[@shaonjunior8894]

how can i calculate this linear equation without wolframalpha? i want to calculate myself and with fx991MS calculator plz help

[@TheChristopherVEVO]

Linear algebra, thats why its necessary in engineering
there are various ways, you can search for cramers formula, and Gauss Jordan

[@musicismyfuel4085]

well not exactly everything...you could have thrown in dependent current sources as well.

[@jesusalvarezfebres6592]

the last equation should be I1(-40+20)+I4 (40)=80.

[@atmsc4nd4l]

your answers are wrong. i solved it in manual calculations. the correct answers are:
I1 = 0.473A
I2 = -0.827A
I3 = -1.722A
I4 = 2.709A
simulate first before making video so you can verify if your answers are correct. well anyways, great video. just need some editing to make it right.

[@MrDlbonano]

Bro you made a mistake