Thevenin's Theorem-One Independent Source

Shows how to find the Thevenin equivalent of a circuit with an independent source. More instructional engineering videos can be found at www.engineeringvideos.org.
This video is licensed under the Creative Commons BY-SA license creativecommons.org/licenses/b....

[@kathrnrorr]

You're so much easier to follow than my grumpy old circuits instructor, who is tenured and therefore too important to bother with any actual educating. In a few minutes you managed to clarify concepts that I have struggled with for weeks. Thank you so much for your knowledge!

[@aelita909]

what i find the most helpful is your commentary! the breakdown and clarification of each step cleared up a lot of confusion i had from reading the textbook

[@eaglebaize]

It feels like I've gone through so many different tutorials on this topic. Finally, this is the one that has helped the most. Thank you!

[@user-yx6mq2km3m]

Another clear and concise video. Thank you

[@soumilyade1057]

Thank You. That was a real help. This subject is daunting really. You made this simple task simpler xD

[@takk2536]

you said thanks for watching . . .
no !!!
thanks for teaching me !!!!
i love that

[@GrindOne69]

well, I understood this video on Thevenin's Theorem very welll !!!
Thanks Darryl Morrel .....

[@kara96raza]

thanks very very much Mr. Darry morrell that helped me alot we appreciate what you doing

[@zawette]

Thank you a lot !

[@AngeloGi]

Parallel resistors means that both their ends are common.

[@karennakye]

Thank you so much

[@DarrylMorrell]

@Omdrwsh The 500 ohm resistor is the equivalent resistance of the two 1k Ohm resistors in parallel. My video "Equivalent Resistance of Parallel Resistors" explains how you can find this equivalent resistance.

[@i8tweak]

Thanks!

[@r3vmixman]

Why is it that the 1k and 1k ohm resistors are parallel for the short circuit on the right but then the 1k and 2k ohm resistors are parallel for the short circuit on the left (Vs=0)?

[@Marsc0met]

Hey Darryl, so you can only use the shortcut method to find the Rthev right? You would still have to do what you did in the beginning to calculate the Voc, right? So essentially, the shortcut allows you to skip calculating the current across a short circuit.

[@4thKyuubi]

Hmmm, I keep getting .0016 for the Isc.
I used KCL with the current from the 8V source as coming in, and set it equal to (Isc + the current across the 1 kilo ohms). Shouldnt this lead you to the same result?

[@aarongoodson2293]

Hi, I was just wondering when you solved for the voltage across the 500 ohm resistor, does that imply that the same voltage will put across both the 1K ohm resistors because 500 ohms is the equivalent of both the resistors?

[@tjaistt]

How did you get the two 1KOhms to be parallel to each other?

[@Omdrwsh]

Hi, I'm still new to electronics and I was hoping you could explain how at 6:03, you came up with 500 ohms?

[@peter_castle]

I have a very basic course in circuits (i'm physics, not in engineering) so i didn't understand the "Voltage divider" thing. Can you illustrate me to what is?

[@i8tweak]

Also, what program are you using to teach this? I'd like to get it.

[@saiyaspring]

why can't you use a loop and mesh analysis to find the short circuit current?

[@powboy01]

saiyaspring +1 somebody answer plz

[@femiairboy94]

+Kirolos Saad You can use mesh analysis to do this. Just make a loop on the first enclosed circuit do a kvl and solve for the current, the current will be the same in the 1k Ohm resistor. Multiply and you’ll get the same V_oc. People like to do voltage divider most times as it requires less effort but more technique.

[@powboy01]

femiairboy94 thx for the respond but it's a bit too late i passed electronics in finals already xD

[@femiairboy94]

***** lol sweet, that’s good.

[@ElecTech_Innovations]

🐐🐐

[@HeyZeus096]

Do you follow the same procedure with a current source?

[@aelita909]

mostly. you replace a VS with a wire (no change in voltage). you replace an IS with open terminals (no current flowing through)

[@maturijaahnavi8274]

y independent sources must be set to zero

[@aelita909]

Because a circuit with an independent source has the R-th equivalent to the output resistance. the source itself has no affect on that resistance.

[@hemarajkumar3851]

teaching like snail

[@ScoobyGSXR750]

Why are you here?

[@aelita909]

i tend to find that most tutorial videos have people talking really slowly.
just replay at 1.25 speed

[@hemarajkumar3851]

almost i did