Introduction to Superposition
ฝัง
- เผยแพร่เมื่อ 10 ม.ค. 2012
- Introduces the principle of superposition. More instructional engineering videos can be found at www.engineeringvideos.org.
This video is licensed under the Creative Commons BY-SA license creativecommons.org/licenses/b....
watch this video with 1.25 times speed. saves a lot of time.!
Nah man, 1.5 is better
....No!
Screw it! 2 Times!
Try and stop me suckers!
bih im considering 2x
@@NJLStudios1 4x worked well for me
"any voltage or current in a circuit is the sum of the voltage/current due to each individual independent source alone"
in case anyone wanted that written out for them
thank god, there is an english video on the subject!!
These guys talking about you talking so slow are ungrateful and disrespectful..
You have mellow way of teaching which makes the topics much easier
Man, you make it look easy. Thanks a lot.
Cheers man. This is real great! :)
The current 'I' we are solving for can be anywhere in the circuit can the method still applies?
Thank you for the excellent Videos
To calculate I', the current source is replaced. Current sources are replaced by an open circuit (break in the wire), leaving just the two resistors in series with the 6v voltage source.
To calculate I'', the voltage source is replaced. Voltage sources are replaced by a short circuit (wires connected together), leaving the two resistors in parallel with the 3A current source.
It might help you to redraw the circuit after each substitution to see the arrangement more clearly.
could you please explain why I=0A, how does this make sense?
Thanks!!!
Thank You Sir
thank you sir!
PRIME INSTRUCTIONS. Thanx! :D
thank you sensei
effective video....!!!!
For I'' (eye double prime), why is the -3 Amps negative?
Why I' =6*2/(2+4)=2 according to my view and current divider rule not 1 amper .Please explain.
current divider does not work in series resistors. you are mixing the formula
thanks :)
Thanks
I like your raspy voice. nice vid.
I don't understand why superposition needed to be used to solve this circuit. Initially, couldn't you tell that all 6V would be used up by the 2ohm resistor only? No current would flow through the path with the 4 ohm resistor because the path parallel to it (the one with the 3A supply) has 0 ohm resistance, therefore making it a short circuit?
Isnt I prime - I double prime?
It's probably too late but see that in I', the current source BECOMES AN OPEN. in I'', the voltage source BECOMES A SHORT.
Why is I'' negative?
I thought the reciprocal rule was used with resistors in parallel!!
junkdogg1 he didnt use the reciprocal rule, he used current division
Casual Competitors isn't current division in parallel too?
junkdogg1 my bad, i realised the resistors are in parallel. They are only in series when the current source is missing
Only one voltage source, so it should be 1amp for this circuit
You have explained really well but you're to slow which made the explanation kind of poring.
In other word this basic video didn't save my time.
Well i'd rather spend 9 mins with this sir then 20mins trying to decipher my text book!
Abdullah EE watch with 1.25 times speed, saves time, (;
There is only one voltage source so this is not superposition
+junkdogg1 But a current source can also be a voltage source if you use source transformation so yeah this is superposition
you.. eehm.. talk.. uhmm.. sooo.. uhm.. slooow
OMG you talk soooo slow. I should just change my speed from .5 to normal
Oooooh Myyyyyyy Goooooooood,
you talk so slow, video could be half the size
Ok wrong type of superpositions. Should've searched quantum superpositions.
Dude first learn how to talk
Wow, the way you're saying that, it really seems like you can do a better job. Lets see you explain it then...