Mesh Analysis Example-Independent Current Sources
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- เผยแพร่เมื่อ 12 ม.ค. 2012
- Mesh analysis for a circuit with independent current sources. One of the current sources requires a super mesh. More instructional engineering videos can be found at www.engineeringvideos.org.
This video is licensed under the Creative Commons BY-SA license creativecommons.org/licenses/b....
If any new viewer is watching and you got different answers, it's because he mixed up between 2ohm and 3 ohm. If you used 3ohm,
The answers should be the following
I1= -4.17A
I2= 0.833A
I3= -4.0A
what if i got i1 to be 4.17A and i2 to be -0.833A
This man volunteered info and the correct way to do things for free. Much more than you basic circuits professor can say. So show a little respect!
Many thanks for explaining these independent current sources, because I've lost few hours searching for help in my books and you did it in ~10 min.
After ~2 years since I first saw your videos, these are by far one of the best tutorials out here.
Thank you sooo much Darryl! This helped me a lot. Previously i was solving using this method and was applying directly the current of source value in the super mesh during the formulation of supermesh equation and other meshes that were attached to it but now YOU JUST OPENED MY MIND HERE AND JUST SOLVED A QUESTION WITH 2 EQUATIONS AND IT WAS FLAWLESS.. Thank you so much Darryl. This tutorial literarily saved my life. 🙏🙏🙏
you fucked up on the 3 ohm resistor
Your videos are so useful. Thanks for posting a very clear and concise video.
Taking electrical engineer class right now for my ME degree. You make this so much easier understand than my Prof. Thank you for making these videos.
Thank you for all the videos that you post, each video has been helpful.
you taught me the one thing my professor couldnt. thanks a million
Thanks! Helped straighten out the basics!
@xloren Thanks for pointing this out. I have added a few annotations to show where it should be different.
Your videoes are very helpful. Thanks.
Awesome video! super helpful :) :)
Thanks a lot. U save my life!!!
Thank you so much for the video👍👍👍👍
Great explanation, thanks.
Great explanation =)
Wow, thank you so much!
In mesh equation instead of 3 ohms u have taken 2ohms then i1 and i2 are 6.1666A and 1.16666A
great vid!
@HUNT4LlF3Z I agree that nodal analysis is usually easier; I usually use nodal analysis when I need to analyze a complex circuit.
5:45 your phone rang and you didnt answer it!
ohh btw i like your videos, you explain this much better than my lecturer. well done!
Igor Keating maybe it was his mother lol
@@abdelrahmangamalmahdy or his wife
The I3 is drawn clockwise. The current provided from the current source is drawn flowing counter-clockwise in the nr 3 mesh circuit. Thus I3 must be -4 because it flows in the opposite direction.
what will happen to I3 if you reverse it? will it be posive 4A?
thank you sir !
thank you
Professor gave us an exam that had labelled meshes that weren't all in the same direction and 2 dependent current sources.
Kaz Those professors are idiots, in real life, you just do whatever you want .. you can even do a simulation and you're done. The first course in electronics should be just to get to know how analysis works.
perfect. thanks
thanx very helpful
@12:10 the 3.2A changes since the 2 ohm resistor used when it was really 3 ohhms.
Thanks. Your videos help me so much. BTW R.I.P headphone users
+Tayyib “T410” Cankat sssssssssssssso :D ?
+Hussam Y. yeah 😁
Im sorry I got confused in my own equation. Your answers are right. Sir, do you always have to do a super mesh if there are current sources in the circuit?
Awesome bro, try to make circuit complex
sir the above circuit is there is a current if they instead one resistor and other is be given the how we find voltage across 1.1 resistor in the circuit.
@7:03 it should be 3ohms instead of 2ohms
Thanks mahn
I think Darryl forgot i2 passing through 3 ohms resistor. So through 3 ohms you will have I1, I2 and I3. Can you verify if this is correct?
I assume I can apply this even if I was only given an independent current source?
Could you explain how to enter the I2-I1 = 4A into a calculator? I figure I cannot use this in my matrix because it represents a different variable than our KVL expressions
i like it
Hmm.. Shouldn't it be 3 ohms instead of 2 ohms in your calculation ?
yeah ,that's a little mistake i also think
was goin crazy, so i guess i got a right answer xD
love ya
After you did the 2ohm to 3 ohm mistake you fuked up the whole thing. Please add more captions because it made me confused for a while. Add caption on where you put the equation on wolfram please.
The easiest way to handle this is to just change the value of the 3 Ohm resistor to 2 Ohms, and then you all the calculations are correct.
Be respectful. He is doing it for humanity and if he wants to stop this whole thing it his right. Learn how to behave he is not getting paid by you.
and if you check the answers using the original equation(i2-i1=5) and the answers from that wolfram site, i1=16/5 ,i2=9/5
9/5-16/5 is not equal to 5A
Hello, I tried solving the super mesh equation manually and somehow i dont get your answer,
since i3=-4
i2-i1=5 -- equation 1
3i1+2i2-(-4)(3)=6
3i1+2i2+12=6
3i1+2i2=-6 -- equation 2
using substitution --- eq 1 to 2
i2=5+i1
3i1-2(5+i1)=-6
3i1-10-2i1=-6
i1=4A, i2=9A
I thought if your loop direction is the same as your assumed current direction it should be subtract not add?
What if 4A current source is replaced by 5V battery downward
How would this be inserted in a ti-84 plus calculator to solve?
th-cam.com/video/e8mDRCIRbJU/w-d-xo.html
in first equation...why is it I2-I1=5 and not I1-I2=5 ?
PLZZZ ANS ASAP
I don't understand why I3 = -4A, shouldn't it be I3=+4A since I3 goes from high to low. Such as in the case of the 6V power source where I2 goes from a lower potential to a higher potential hence, it is written a negative -6V. I am very confuse in this part? Can you be nice enough to explain this or make a video addressing this since myself and a friend are very confused. Thank You.
Mess Analysis!!! Oh Darryl
Does this work for linear circuits ONLY ?
+Abdulrahman Mahdaly no it works for nonlinear too.
I love cruising around my supermesh. Dont you?
To bad he messed up the 3ohm resistor. Otherwise a good video.
U should also tell that how to solve these equations without internet....I mean we are not allowed to use internet during examinations...So, it could be difficult..
faiza shah you use matrices (: with all of the coefficients ... I should make a video of it 👍🏼
@@clawskitt-3841 ok
Also if your numbers are easy you can use substitution (solve for one variable to plug into another equation)
Man, why is your voice so cranky. It makes it kinda hard to focus considering I'm watching this at night trying to finish a long-ass assignment by morning... Makes me wanna give in to the sleep D:
+prepareuranus I kinda like it. It feels like he's saying "I know the struggle" :p
I1= -4.167A
I2= 0.833A
I3= -4.0A
this is what i got too!
I got:
I2=4.17A
I3--0.833A
Can someone please verify?
yes, correct
yass
Well not exactly, since you already knew that I3 was -4 A.
The answers should be the following
I1= 4.17A
I2= 0.833A
I3= -4.0A
Abulfazel Naser i got these answers as well !
There is a mistake ur calculation. U took up 2ohm instead of 3ohm in supermesh equation....:)
yes I solved the whole question ans didn't match ..
2 is not equal to 3 . lol
There any many mistakes in this video.
At 8:30 "there are two equations and two unknowns" when there is clearly I1 I2 and I3 all unknown
current sources in mesh analysis makes things... MESSHY?
sorry, i have been studying fo a long time
Just go back 2 sleep.......coz you're literally sleeping in this video
Its amazing how a professor can go on about something for an hour and a half explaining how easy something is, but you just don't get it and feel like a moron.... 15 minutes on youtube with someone who knows how to explain something later... everything is fine
are u look nervous
i know it's so slow and annoying
Shit brix when you see it. hahahaha. there is a mistake dude. The the other resistor should be 3 ohms.
Lmao, why would you use an equation solver after getting all the data? SOLVE THE EQUATION, that is half the work.
you fucked up from the start! it is easy calculations! the current in I1 is 4.17A!
Not really but your comment put a whole kindergarten to sleep...
Talk tooooo slooooooooowwwwwwwwwwwww
just set the speed to 2x
this is very bad. he literally makes me sleep.
Totaly wrong why you make videos ??!!!
ergh his voice is horrible to listen to!
thank you
in first equation...why is it I2-I1=5 and not I1-I2=5 ?
PLZZZ ANS ASAP
I2 is going the same direction as the 5A current source whereas I1 is going against.