Inductors and Current - Answers to Questions

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  • เผยแพร่เมื่อ 23 พ.ค. 2023

ความคิดเห็น • 8

  • @SaintAngerFTW
    @SaintAngerFTW 4 หลายเดือนก่อน +1

    This channel deserves a million subs.....

  • @Anilyadav-rb8ft
    @Anilyadav-rb8ft 11 วันที่ผ่านมา

    Excellent lecture. Watching your channel from India

  • @Thoughtflux
    @Thoughtflux 28 วันที่ผ่านมา

    I had the same exact doubt. Thank you for your lectures. I think i will watch all of 'em.

  • @SaintAngerFTW
    @SaintAngerFTW 4 หลายเดือนก่อน

    Thank you..... SIR!

  • @dabay200
    @dabay200 2 หลายเดือนก่อน +1

    Excellent video, but I don't understand how the voltage across the inductor when "charging" it in a DC circuit can ever be higher than the source voltage, as for energy to be "pumped" into an inductor the source voltage must be higher, otherwise the inductor is the one supplying the energy and is thus "discharging".

    • @magical261
      @magical261 29 วันที่ผ่านมา

      When the inductor 'charges', the voltage across it is limited by the source voltage. It cannot, therefore, exceed the source voltage.
      When the switch is opened, the sudden collapse of the magnetic flux induces a voltage 'spike' that can exceed the source voltage. It is only in this 'discharging' state that a high voltage occurs.
      Nb Despite the high voltage, the inductor generates slightly less power than it receives, as there are always losses.

  • @gregorykotoch5045
    @gregorykotoch5045 5 หลายเดือนก่อน

    I know there can be voltage without current, but how can there be current without voltage? Doesn't this contradict ohms law?

    • @jboy6944
      @jboy6944 5 หลายเดือนก่อน

      Voltage is the potential between two point. High voltage means high potential. At 0v there’s still potential. In the real world it’ll be something like 0.12v, but if you probe a battery from negative to positive you’ll have negative voltage. So there’s always potential to do work. The question is at which rate.