Be careful how you explain a circuit, or you may just make it more confusing. Read about voltage and polarity in a series circuit: vocademy.net/textbooks/dcelect...
I think it’s important for people to keep in mind these multiple grounding points are not separate ground rods driven into dirt with all the associated ground rod resistance etc. it is one grounded conductor connected to all “grounded points” on the circuit. That’s why we say it’s a short circuit between grounded points. It’s because in electronics the ground is generally a copper path that happens to be bonded to earth. That copper path has near zero resistance point to point.
Further to my other two posts, when a circuit has two ground points, i guess charged particles that enter ground at one point do not feel an attraction to the other ground connection causing those charges to move towards the other connection through the earth, but the other connection just sucks up charges from earth quite independently and quite oblivious to the other ground connection. In a "normal" circuit with only one or no earth connections, an election would leave the anode (positive charge leave the cathode) and eventually arrive at the cathode, but that electron would never reach the cathode if it entered earth first. No electron would complete a circuit.
Very interesting that earth does not appear to have an absolute voltage, but takes on the voltage of whatever node it is connected to. ... as any conductor does I guess.
In the case of two ground points at different nodes of the circuit, how does one ground know there is another ground connection which makes it draw current from the circuit? I guess if ground takes the value of 15 volts then the other ground would too (at the other end of the resistor) and there would be no incentive for current to move through the resistor. Same if ground took on the value of any other voltage, say zero volts. But this still does not quite explain the mechanism to me. Ah! Current takes all paths! It would go through the resistor and via the earth, albeit the earth has much less resistance and nearly all the current would flow via the earth (as indeed Bob says quite clearly). Moreover, i guess when there is only one connection to ground current could/would flow to and from ground but in equal measure so as to cancel each other out.
At 48.56, the voltage is 0V only when the DM is connected to the earth ground wire. That means the voltage at the n side of the diode is -1.5. Now, you removed the DM and placed it at the end of the same negative side of the diode. It is showing 0V. How this conversion from -1.5 to 0v takes place???
Thank you, professor! I was just thinking about this a couple of days ago, and since I've been watching your videos this got recommended. Lucky me!
sir I wish I had you for my teacher when I was at school
Another great video, Bob!
I think it’s important for people to keep in mind these multiple grounding points are not separate ground rods driven into dirt with all the associated ground rod resistance etc. it is one grounded conductor connected to all “grounded points” on the circuit. That’s why we say it’s a short circuit between grounded points. It’s because in electronics the ground is generally a copper path that happens to be bonded to earth. That copper path has near zero resistance point to point.
Excellence
Further to my other two posts, when a circuit has two ground points, i guess charged particles that enter ground at one point do not feel an attraction to the other ground connection causing those charges to move towards the other connection through the earth, but the other connection just sucks up charges from earth quite independently and quite oblivious to the other ground connection.
In a "normal" circuit with only one or no earth connections, an election would leave the anode (positive charge leave the cathode) and eventually arrive at the cathode, but that electron would never reach the cathode if it entered earth first. No electron would complete a circuit.
excellent👍👍👍
Very interesting that earth does not appear to have an absolute voltage, but takes on the voltage of whatever node it is connected to.
... as any conductor does I guess.
In the case of two ground points at different nodes of the circuit, how does one ground know there is another ground connection which makes it draw current from the circuit?
I guess if ground takes the value of 15 volts then the other ground would too (at the other end of the resistor) and there would be no incentive for current to move through the resistor. Same if ground took on the value of any other voltage, say zero volts. But this still does not quite explain the mechanism to me.
Ah! Current takes all paths! It would go through the resistor and via the earth, albeit the earth has much less resistance and nearly all the current would flow via the earth (as indeed Bob says quite clearly).
Moreover, i guess when there is only one connection to ground current could/would flow to and from ground but in equal measure so as to cancel each other out.
At 48.56, the voltage is 0V only when the DM is connected to the earth ground wire. That means the voltage at the n side of the diode is -1.5.
Now, you removed the DM and placed it at the end of the same negative side of the diode. It is showing 0V.
How this conversion from -1.5 to 0v takes place???
Vs = 10v
RL = 10Ω
V1 = 10Vd
10Vs - 10Vd = 0v