As a physics teacher, educated in engineering, I would ask that there be some additional synonyms at the end. "Static equilibrium" being a well understood term for the case of non-moving equilibrium, and "dynamic equilibrium" being another term for "translational equilibrium". Using your flip videos is great! However, either because I'm lazy or just don't like having to explain why my terms are different from yours, it would be nice to have them mentioned :>)
Interesting, I had never heard the term "Dynamic Equilibrium" and I have always used "Static Equilibrium" to refer to an object which has both a net force of zero and a net torque of zero acting on it, and is at rest. Therefore I don't normally talk about Static Equilibrium until after torque is introduced. I still think it is important students understand that a net force of zero acting on an object simply means the object is not accelerating. Also, I don't see "Dynamic Equilibrium" and "Translational Equilibrium" as synonymous. Translational Equilibrium means the net force on the object is zero and therefore the object could be at rest or moving at a constant velocity. Thanks for sharing your knowledge. I love that I get to learn because I make these videos. Please be aware that I can not make changes to videos after uploading them to TH-cam and therefore cannot add any "additional synonyms at the end" of the video. Sorry.
Sadly, I can do a lot of clever things, however I cannot change a video once it has been uploaded to TH-cam. When there is an egregious error, I do change the video and upload an new version. In fact, I did so just yesterday... New: th-cam.com/video/fiT2R88Zt58/w-d-xo.html Old: th-cam.com/video/d4VUVzyd06o/w-d-xo.html
The "New" version has lost quite a bit of resolution. It's almost as if the original video was analog and copied with the unwanted segment cut out. That leaves the "New" as a 2nd generation copy which is quite degraded over the first.
***** Filmed from a car driven by my wife using a GoPro Hero at 2704x1524. Motion tracked/stabilized using the Flipping Physics sign on the Prius. Because this video is 1920x1080, I was able to zoom in and center the Prius.
Sir , l have misconception that according to newtons third law that every action and has an equal and opposite reaction so if a car is moving with a velocity of 5
I'm still struggling with this - how can the car move if there is no resultant force? I understand that it is moving at constant velocity, but doesn't it have to have a force stronger than the frictional force to move? So I don't understand why the x force equals to zero... I hope you can help me with this concept...
+bee choo The net force is zero because all the forces add up to zero. According to Newton's Second Law: The net force acting on any object is equals to the mass of that object times its acceleration (where both force and acceleration are vectors). Therefore, when the net force acting on an object is equal to zero, the acceleration of the object is equal to zero and the velocity of the object isn't changing.
Sabhupa 123 actually, if you apply Newton's first law: Every object will continue in its state of rest or uniform motion in a straight line unless a resultant force acts on it. So in this case, the object is moving at constant velocity; and lets say the forward force is 5N, so applying the third rule, the friction should also be 5N. So why is it not stopping? It is because that, as stated in rule 1, it will continue moving in uniform motion in a straight line unless a resultant force acts on it. To put it simply, the car will continue to move in constant velocity unless it accelerates faster than it should be. Therefore, it will not stop despite of friction because of Newton's first rule.
I have a question about the example of a vehicle being at equilibrium at a constant speed. It seems to me that although the example is interesting, that there are so many real life variables involved that in reality it would be virtually impossible to achieve. For example to maintain speed on a grade would require greater force or the conditions of the road itself could change things entirely (ie...paved road or gravel road). I'm not trying to argue for the sake of the argument but am rather interested to know if I am looking at this correctly or if all of that is irrelevant.
Also, I have considered the possibility of creating a machine that is in a perpetual state of unequillibrium (which is a word yet coined). If my thought process on this is correct that is the goal trying to be achieved by perpetual motion machines but so far been elusive to those that have attempted it. Without completely giving away the idea that I am working on it involves the use of a perpetual "fuel" that powers the machine and creates the unequillibrium. So, heh heh heh...have you ever contemplated such seeming nonsense yourself or am I off on my own here pondering the ideas of Einstein.
@@timc6149 Cars do have cruise control, which is a control system that uses a feedback loop to constantly tune the position of the accelerator pedal so that the work done by the engine is equal to the rate of heat lost to the air drag and friction. Try seeing what a car with cruise control feels like, when driving along a straight and flat road. If you are in a car that uses cruise control on a flat and straight road, the only way you would feel the motion is when you feel the car's vibrations from the imperfections in the road. You can also experience this in an airplane, as airplanes aren't subject to the imperfections in a manmade roadway. If you've ever woken up in an airplane that is at a cruising speed and altitude with no turbulence, you don't feel its motion. You have to wait for your brain to wake up to put together several other facts to realize that you are moving.
Sir force applied by the engine rotates the wheels of the car. Then what exactly causes the the force toward the forward direction on the car. Also friction acts to the opposite direction of motion resisting the motion and on absence of the friction the wheels will keep rotating at a fixed place. These two facts seem contradictory to me. I feel friction is pushing the car forward. Sir clarify my misconception please. Hope like before you will make a quick reply. Sir learning is ecstatic but confusion is tormenting. Love you sir.
You are correct that the force of static is what actually moves the car forward. Typically in a basic approach to solving this type of problem we treat it as a force applied pushing the car forward, however, that is not actually correct. I’ve tried teaching it with force of static friction instead and it confused students more. So I teach it this way instead; it confuses students less, however, is not quite correct. 😬
@@learningisecstatic9348 Think of the road/ground/Earth as a "work mirror". You push backwards on the road, you attempt to do work on the road in the reverse direction. The road is ultimately attached to Earth, which has significantly more mass than you. The Earth's movement due to this force is barely noticeable, and because you can't do any significant work on the road/ground/Earth, the road reflects this work back onto you, with its Newton's third law force pair to the force you apply to it.
@@FlippingPhysicsI think that you have not realised the problem here. A force that slows the car down must do a certain work. No work is done at the ground contact as the tires are not slipping. The braking work transferred to heat occurs in the interior of the car and makes the wheels rotate slower. And those forces working are not directed backwards. The static friction force on the the tires only make the wheels still rotate without slipping. Sorry, but you show a big misunderstanding here regarding forces.
+Kenneth Greer If you stop pedaling a bike on level ground, your bike will not be in equilibrium. The forces of friction will cause an acceleration and slow the bike down, therefore, not equilibrium. The car in this video is in equilibrium because it has a force pushing it forward which is equal in magnitude to the friction forces. If the bike was going down an incline, you could find an angle at which the force of gravity parallel would balance out the forces of friction acting on the bike.
In the absence of a force applied to the right, the leftward force of friction will cause a net force in the x-direction which will acceleratedthe car to the left and the car will no longer be in equilibrium.
+Nihal Jalaluddin The net force is zero because all the forces add up to zero. According to Newton's Second Law: The net force acting on any object is equals to the mass of that object times its acceleration (where both force and acceleration are vectors). Therefore, when the net force acting on an object is equal to zero, the acceleration of the object is equal to zero and the velocity of the object isn't changing.
+Nihal Jalaluddin Your question isn't very clear. I will answer the question, "Why is it easier to push an object down than to pull it up?" Because the force of gravity is always down. The force of gravity assists when you push the object down and resists when you pull the object up.
+Zubaer Ahmed If you are standing on a floor on the Earth, you will experience a force of gravity pulling you straight down toward the middle of the Earth. This Force of Gravity is also called "Weight" and is caused by the mass of the planet and the mass of your body pulling toward one another. There will also be a Force Normal upward preventing your body from accelerating toward the center of the planet. The net force in the y-direction is zero and the magnitude of the net force is zero. I suggest you watch these two videos: www.flippingphysics.com/free-body-diagrams.html and www.flippingphysics.com/second-law.html
Just wanted to say this video is still helping people in 2020 :)
The physics does not change, so I am hopeful my videos will continue to help people learn physics for decades...
Flipping Physics I thank you for that! I subscribed!
Also in 20201
Thank you. I really appreciate your time and dedication to this content. You helped me really understand physics calculations.
I like your tie-dye shirt! Thanks for sharing some info!
hey man u explain better than many teachers. thank you for every thing
u mke physics so intersting!
+ibrahim amanullah that's great!
Thanks have an exam tomorrow you are better than my teacher
Hope i pass
Massive thanks from france
I hope you passed!
I am sure you passed, my friend!
Thanks! We used this in our science class to learn more about Equilibrium.
Great. Glad I can help!
As a physics teacher, educated in engineering, I would ask that there be some additional synonyms at the end. "Static equilibrium" being a well understood term for the case of non-moving equilibrium, and "dynamic equilibrium" being another term for "translational equilibrium". Using your flip videos is great! However, either because I'm lazy or just don't like having to explain why my terms are different from yours, it would be nice to have them mentioned :>)
Interesting, I had never heard the term "Dynamic Equilibrium" and I have always used "Static Equilibrium" to refer to an object which has both a net force of zero and a net torque of zero acting on it, and is at rest. Therefore I don't normally talk about Static Equilibrium until after torque is introduced. I still think it is important students understand that a net force of zero acting on an object simply means the object is not accelerating. Also, I don't see "Dynamic Equilibrium" and "Translational Equilibrium" as synonymous. Translational Equilibrium means the net force on the object is zero and therefore the object could be at rest or moving at a constant velocity.
Thanks for sharing your knowledge. I love that I get to learn because I make these videos. Please be aware that I can not make changes to videos after uploading them to TH-cam and therefore cannot add any "additional synonyms at the end" of the video. Sorry.
Oh (referring to last sentence), sorry then. :
Sadly, I can do a lot of clever things, however I cannot change a video once it has been uploaded to TH-cam. When there is an egregious error, I do change the video and upload an new version. In fact, I did so just yesterday...
New: th-cam.com/video/fiT2R88Zt58/w-d-xo.html
Old: th-cam.com/video/d4VUVzyd06o/w-d-xo.html
The "New" version has lost quite a bit of resolution. It's almost as if the original video was analog and copied with the unwanted segment cut out. That leaves the "New" as a 2nd generation copy which is quite degraded over the first.
I'm guessing it's an issue with your internet connection. The "new" version uses the same original files as the "old".
The introduction is everything 😂
Thanks for not making physics boring like every other video 😊
Great explanation helped me a lot !
+norayik karakashian You are welcome!
Thanks sirr watching from Philippines
Very clear and simple. Thanks!
Thankyou so much...I understood ,it is crystal clear explanation 🔥... something I watched worthy today , thankyou bro
Glad it helped
Just keep making videos guys i bet you r gonna get to a million subscribers
Someday...
I like your teaching system thanks.
This video is still helping in 2021 🙂
Best explanation ever!!
nice video😘
Introduction to Equilibrium #PhysicsED #APPhysics1
What a glorious way of teaching
Thanks. I am quite proud of it.
Fun and helpful video, thanks a lot
You are welcome!
Really great explanation with interesting view and funny too.
Glad you enjoyed it!
Thanks a lot
So helpful...Thanks man!
Very good
thank you so much for these vids!
You are welcome!
Thank for explains 😘😘
You are welcome.
Ty so much
awesome, man!! Love your videos!!
Thanks!
How'd you keep the camera on the moving car?
***** Filmed from a car driven by my wife using a GoPro Hero at 2704x1524. Motion tracked/stabilized using the Flipping Physics sign on the Prius. Because this video is 1920x1080, I was able to zoom in and center the Prius.
this video helped me a lot!
Glad you help you out!
Sir , l have misconception that according to newtons third law that every action and has an equal and opposite reaction so if a car is moving with a velocity of 5
yes
I'm still struggling with this - how can the car move if there is no resultant force? I understand that it is moving at constant velocity, but doesn't it have to have a force stronger than the frictional force to move? So I don't understand why the x force equals to zero... I hope you can help me with this concept...
+bee choo The net force is zero because all the forces add up to zero. According to Newton's Second Law: The net force acting on any object is equals to the mass of that object times its acceleration (where both force and acceleration are vectors). Therefore, when the net force acting on an object is equal to zero, the acceleration of the object is equal to zero and the velocity of the object isn't changing.
bee choo yah i also had the same confusion ! Isnt there a frictional force ??
Sabhupa 123 actually, if you apply Newton's first law: Every object will continue in its state of rest or uniform motion in a straight line unless a resultant force acts on it. So in this case, the object is moving at constant velocity; and lets say the forward force is 5N, so applying the third rule, the friction should also be 5N. So why is it not stopping? It is because that, as stated in rule 1, it will continue moving in uniform motion in a straight line unless a resultant force acts on it. To put it simply, the car will continue to move in constant velocity unless it accelerates faster than it should be. Therefore, it will not stop despite of friction because of Newton's first rule.
Excellent superb explaintion
Thanks. Glad you found it helpful and hopefully learned something.
good
This is still helping people in 2022
Wonderful!
I have a question about the example of a vehicle being at equilibrium at a constant speed. It seems to me that although the example is interesting, that there are so many real life variables involved that in reality it would be virtually impossible to achieve. For example to maintain speed on a grade would require greater force or the conditions of the road itself could change things entirely (ie...paved road or gravel road). I'm not trying to argue for the sake of the argument but am rather interested to know if I am looking at this correctly or if all of that is irrelevant.
Also, I have considered the possibility of creating a machine that is in a perpetual state of unequillibrium (which is a word yet coined). If my thought process on this is correct that is the goal trying to be achieved by perpetual motion machines but so far been elusive to those that have attempted it. Without completely giving away the idea that I am working on it involves the use of a perpetual "fuel" that powers the machine and creates the unequillibrium. So, heh heh heh...have you ever contemplated such seeming nonsense yourself or am I off on my own here pondering the ideas of Einstein.
@@timc6149 Cars do have cruise control, which is a control system that uses a feedback loop to constantly tune the position of the accelerator pedal so that the work done by the engine is equal to the rate of heat lost to the air drag and friction. Try seeing what a car with cruise control feels like, when driving along a straight and flat road.
If you are in a car that uses cruise control on a flat and straight road, the only way you would feel the motion is when you feel the car's vibrations from the imperfections in the road.
You can also experience this in an airplane, as airplanes aren't subject to the imperfections in a manmade roadway. If you've ever woken up in an airplane that is at a cruising speed and altitude with no turbulence, you don't feel its motion. You have to wait for your brain to wake up to put together several other facts to realize that you are moving.
This video is still helping us in 2030
Wow. Thanks for coming back and letting me know!
Sir force applied by the engine rotates the wheels of the car. Then what exactly causes the the force toward the forward direction on the car. Also friction acts to the opposite direction of motion resisting the motion and on absence of the friction the wheels will keep rotating at a fixed place. These two facts seem contradictory to me. I feel friction is pushing the car forward. Sir clarify my misconception please. Hope like before you will make a quick reply. Sir learning is ecstatic but confusion is tormenting. Love you sir.
You are correct that the force of static is what actually moves the car forward. Typically in a basic approach to solving this type of problem we treat it as a force applied pushing the car forward, however, that is not actually correct. I’ve tried teaching it with force of static friction instead and it confused students more. So I teach it this way instead; it confuses students less, however, is not quite correct. 😬
@@FlippingPhysics thank you sir for your reply. This is due to your videos that my basics are getting cleared.
@@learningisecstatic9348 Think of the road/ground/Earth as a "work mirror". You push backwards on the road, you attempt to do work on the road in the reverse direction. The road is ultimately attached to Earth, which has significantly more mass than you. The Earth's movement due to this force is barely noticeable, and because you can't do any significant work on the road/ground/Earth, the road reflects this work back onto you, with its Newton's third law force pair to the force you apply to it.
Thanks
Welcome
"the force of friction backward", what force is that? Please explain.
Perhaps this will help: www.flippingphysics.com/tire-friction.html
@@FlippingPhysicsI think that you have not realised the problem here. A force that slows the car down must do a certain work. No work is done at the ground contact as the tires are not slipping. The braking work transferred to heat occurs in the interior of the car and makes the wheels rotate slower. And those forces working are not directed backwards. The static friction force on the the tires only make the wheels still rotate without slipping. Sorry, but you show a big misunderstanding here regarding forces.
As a kid we'd say a moving object in equilibrium was "coasting." Like when you stop pedaling on a bike.
+Kenneth Greer If you stop pedaling a bike on level ground, your bike will not be in equilibrium. The forces of friction will cause an acceleration and slow the bike down, therefore, not equilibrium. The car in this video is in equilibrium because it has a force pushing it forward which is equal in magnitude to the friction forces. If the bike was going down an incline, you could find an angle at which the force of gravity parallel would balance out the forces of friction acting on the bike.
Perfect. I like to spatialize these concepts. I can almost feel the experience of equilibrium while moving.
#Firstyearphysicsnumericalproblems
#BestExampleOfTheAboveTopic
I think there should be no horizontal force towards the right 'cause the car is moving because of inertia.
In the absence of a force applied to the right, the leftward force of friction will cause a net force in the x-direction which will acceleratedthe car to the left and the car will no longer be in equilibrium.
Great
Thanks. That's better then good.
Wow
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If the net force is 0 then how is the car moving?
Net force causes _acceleration_ not velocity.
How can it be possible that net force acting on a moving car is zero?
+Nihal Jalaluddin The net force is zero because all the forces add up to zero. According to Newton's Second Law: The net force acting on any object is equals to the mass of that object times its acceleration (where both force and acceleration are vectors). Therefore, when the net force acting on an object is equal to zero, the acceleration of the object is equal to zero and the velocity of the object isn't changing.
+Flipping Physics tnx,but why is it easy to push down an object then to pull it up?
+Nihal Jalaluddin Your question isn't very clear. I will answer the question, "Why is it easier to push an object down than to pull it up?"
Because the force of gravity is always down. The force of gravity assists when you push the object down and resists when you pull the object up.
+Flipping Physics okay this is what I wanted
maybe the acceleration on a moving car is unequal to zero because the car is moving
an object moving at a constant velocity has zero acceleration.
since acceleration is basically change in velocity and if there is zero net velocity movement - a = 0
when I am standing on a floor total force on me is 0.so in that situation will i feel a weight please help me
+Zubaer Ahmed If you are standing on a floor on the Earth, you will experience a force of gravity pulling you straight down toward the middle of the Earth. This Force of Gravity is also called "Weight" and is caused by the mass of the planet and the mass of your body pulling toward one another. There will also be a Force Normal upward preventing your body from accelerating toward the center of the planet. The net force in the y-direction is zero and the magnitude of the net force is zero. I suggest you watch these two videos: www.flippingphysics.com/free-body-diagrams.html and www.flippingphysics.com/second-law.html
Sorry, I meant :thanks
You are welcome!
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thanks?
Haha nicd
2025
For me one doubt that u r boy or girl??🤣