Please check my calculations carefully, and you will see I have used (ds/dv)=(dp/dT) which is a right choice of replacement in the calculation of 1tds equation. Also you can verify it form any standard text books like books by zemansky, or by A B Gupta or by garg and bansal
Nice explanation sir😊👌🏻
☺️
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Glad to know that it was helpful.
Really helpful 🤩
Glad to hear that it was helpful.
We use 2nd Maxwell relationship in 1st TdS equation ; Here you make the mistake.
Please check my calculations carefully, and you will see I have used (ds/dv)=(dp/dT) which is a right choice of replacement in the calculation of 1tds equation.
Also you can verify it form any standard text books like books by zemansky, or by A B Gupta or by garg and bansal