TdS equations in thermodynamics | Derivation | Thermodynamic | Lecture 5

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  • เผยแพร่เมื่อ 8 ม.ค. 2025

ความคิดเห็น • 8

  • @santashreesahu5831
    @santashreesahu5831 4 ปีที่แล้ว +1

    Nice explanation sir😊👌🏻

  • @jayasrirana7442
    @jayasrirana7442 ปีที่แล้ว +2

    Nice explanation sir , thank 🙏🙏you sir, it is very helpful ☺😊😊sir🙏🙏🙏🙏

  • @chaudharyzaadi5502
    @chaudharyzaadi5502 3 ปีที่แล้ว +1

    Really helpful 🤩

  • @bscphysics3640
    @bscphysics3640 4 ปีที่แล้ว

    We use 2nd Maxwell relationship in 1st TdS equation ; Here you make the mistake.

    • @PhysicsLearningwithDrShaw
      @PhysicsLearningwithDrShaw  4 ปีที่แล้ว +1

      Please check my calculations carefully, and you will see I have used (ds/dv)=(dp/dT) which is a right choice of replacement in the calculation of 1tds equation.
      Also you can verify it form any standard text books like books by zemansky, or by A B Gupta or by garg and bansal