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Thanks for the great video! I have a question, if I may. Helmoltz free energy is usually applied at constant temperature, but in many books the relation "W ≤ T∙ΔS - ΔU" is proved just assuming that the system will start and end the trasformation at the temperature T of the bath, without worrying about "what happens to the system". Does it mean that "W ≤ T∙ΔS - ΔU" holds also when the system changes temperature? And what's the meaning of the Helmoltz free energy when the system changes temperature in the middle of the process (assuming it goes back to the temperature of the bath at the end of the process)?
You can't derive the relation W ≤ T∙ΔS - ΔU when the system is not in the isothermal condition. To derive the above relation, the temperature has to be constant throughout the process not just at the start and end of the transformation. From the Clausius theorem, You will get this T∙ΔS = ΔQ only for the isothermal case. Mathematically you will find "T" within the integration. If the system changes its temperature in the middle of the process, then still we can calculate the Helmholtz free energy, However, it will lose its importance as thermodynamics potential.
*For Explanation in Hindi:*
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Thanks professor really ..IAM from algeria and I tell us that u r agreat sir. .thank I alot
You are welcome. Thank you
@@PhysicsLearningwithDrShaw ❤️
Sir thank you really helpful ❤️🙏🙏
Most welcome
@@PhysicsLearningwithDrShaw sir plz upload more videos.....
Thanks for the great video! I have a question, if I may. Helmoltz free energy is usually applied at constant temperature, but in many books the relation "W ≤ T∙ΔS - ΔU" is proved just assuming that the system will start and end the trasformation at the temperature T of the bath, without worrying about "what happens to the system". Does it mean that "W ≤ T∙ΔS - ΔU" holds also when the system changes temperature? And what's the meaning of the Helmoltz free energy when the system changes temperature in the middle of the process (assuming it goes back to the temperature of the bath at the end of the process)?
You can't derive the relation W ≤ T∙ΔS - ΔU when the system is not in the isothermal condition. To derive the above relation, the temperature has to be constant throughout the process not just at the start and end of the transformation. From the Clausius theorem, You will get this T∙ΔS = ΔQ only for the isothermal case. Mathematically you will find "T" within the integration. If the system changes its temperature in the middle of the process, then still we can calculate the Helmholtz free energy, However, it will lose its importance as thermodynamics potential.
@@PhysicsLearningwithDrShaw Thanks a lot, sir! Very kind and professional!
@@saggezza-artificiale thank you.☺️
Great sir
Thank you.
Which book ??
Mainly i follow three book
1) garg and bansal (as text book)
2) Rakshit and chattopadhyya (as text book)
3) Zemansky and dittman (as reference book)
@@PhysicsLearningwithDrShaw Thanks Sir.
👍👍👍 thanks
Welcome 👍