Thank you for the very instructive series of videos on this topic. They are all very clear, except in this one, where I can’t see a trick at time 1:50. The entropy is said to be S=f(T,V); and T,V are defined as independent variables. But i can’t have a non-zero result when I apply de/de p|T (I mean de for partial derivative). The only way is to think T and p as functions of (p). So, with the chain rule, i can have the equation: (de S/de p)|T = (de S/de T)(de T/de p)|T + (de S/de V)(de V/de p)|T and then apply the switch of variables, as indicated… Am i wrong? Please, tell me if it turns to be correct. Thank you! Greetings from Italy
Sir what we have to do in this question..........Derive a relation for the change of internal energy when the independent variables T and V of the substance undergo a simultaneous change. Express the result in terms of measurable quantities P, V, T, B, K, Cp and Cv only. Simplify the relation for an ideal gas. ..........plz tell 🙏🙏🙏❤️
th-cam.com/video/hGMYI9HWY6A/w-d-xo.html Watch this video on energy equations, and you will get your answer. Derivation is there as well as calculation for ideal is also there.
Thank u sirrrr........ again a great one😊
Welcome..☺️
3:02 , at that point there 2nd Maxwell equation is used instead of 1st☺
Thank you for the very instructive series of videos on this topic. They are all very clear, except in this one, where I can’t see a trick at time 1:50.
The entropy is said to be S=f(T,V); and T,V are defined as independent variables. But i can’t have a non-zero result when I apply de/de p|T (I mean de for partial derivative). The only way is to think T and p as functions of (p).
So, with the chain rule, i can have the equation:
(de S/de p)|T = (de S/de T)(de T/de p)|T + (de S/de V)(de V/de p)|T
and then apply the switch of variables, as indicated…
Am i wrong?
Please, tell me if it turns to be correct. Thank you! Greetings from Italy
How does the second equation form dS = (delta S/ delta T ) dT + ( delta S / delta V) dV
Do you have any video related ode & pde conversion?
A big thx ❤
💗💗
Sir what we have to do in this question..........Derive a relation for the change of internal energy when the independent variables
T and V of the substance undergo a simultaneous change. Express the result in terms of measurable quantities P, V, T, B, K, Cp and Cv only. Simplify the relation for an ideal gas. ..........plz tell 🙏🙏🙏❤️
th-cam.com/video/hGMYI9HWY6A/w-d-xo.html
Watch this video on energy equations, and you will get your answer. Derivation is there as well as calculation for ideal is also there.
Please sir, give me the proved of CP-CV=alpha ²VT/beta
send me a mail on physicslearning2020@gmail.com
I will reply back the proof.
Thanks
Welcome...🙂
How to get Cp and Cv formula
But i have Cp =dQ/m dt= t ds /m dt .
Where did m go!!!
The value of m was considered 1.
The value of m was considered 1.