Let a+b+c+d=s, The given expression will become a²/(s-a)+b²/(s-a)+c²/(s-a)+d²/(s-a) Now add and subtract a+b+c+d and pair each term, a²/(s-a)+a=sa/(s-a) Take s common and the rest will become 1 you will get s-s=0
Ez method here Multiply both sides with a+b+c+d , now multiply like this A²+A(b+c+d), for b multiply like this B²+B(a+c+d) and so on. If u look carefully ull see that if u divide every individuals of the nominator with the denominator ull get A²/b+c+d +A and so on Now just cancel out the lhs's a+b+c+d with the RHS's a+b+c+d and u will have an answer 0. This seemed ez for me so I shared this method 😅
Let a+b+c+d=s,
The given expression will become a²/(s-a)+b²/(s-a)+c²/(s-a)+d²/(s-a)
Now add and subtract a+b+c+d and pair each term,
a²/(s-a)+a=sa/(s-a)
Take s common and the rest will become 1
you will get s-s=0
Brilliant 👌👌
Ez method here
Multiply both sides with a+b+c+d , now multiply like this
A²+A(b+c+d), for b multiply like this
B²+B(a+c+d) and so on.
If u look carefully ull see that if u divide every individuals of the nominator with the denominator ull get A²/b+c+d +A and so on
Now just cancel out the lhs's a+b+c+d with the RHS's a+b+c+d and u will have an answer 0. This seemed ez for me so I shared this method 😅
@@souvik7752 Outstanding Solution 👌👌👌Awesome 👌👌👌