Let's consider an equilateral triangle ABC with a side length equal to 'a'. If a perpendicular line is drawn from one of the vertices, to the side of the triangle, the perpendicular line divides the 60° angle at the vertex and the side of the triangle into two halves, that is 30° and a\2. the a/2 is the side opposite 30°, and the longest side is opposite the 90° formed by the perpendicular line and the side of the triangle remains a.
Can you clarify how the side of the largest angle is twice the size of the side of the smallest angle?
Let's consider an equilateral triangle ABC with a side length equal to 'a'.
If a perpendicular line is drawn from one of the vertices, to the side of the triangle, the perpendicular line divides the 60° angle at the vertex and the side of the triangle into two halves, that is 30° and a\2.
the a/2 is the side opposite 30°, and the longest side is opposite the 90° formed by the perpendicular line and the side of the triangle remains a.
You can apply trigonometry and can realise it easily 🎉
@@trytolearnsomethingnew7903yes sir