E is a point on the side AD produced of a parallelogram ABCD | Q8 Ex 6.3 class 10

Exercise 6.3 Question 8 Class 10
E is a point on the side AD produced of a parallelogram ABCD and BE intersects CD at F. Show that Δ ABE ~ Δ CFB.
HINT of Question 8 of Exercise 6.3 class 10:
Opposite angles of a parallelogram are equal.
Opposite sides of a parallelogram are equal and parallel.
If two angles of one triangle are respectively equal to two angles of another triangle, then the two triangles are similar
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INTRODUCTION
Two figures are said to be congruent, if they have the same shape and the same size.
Two figures having the same shape (and not necessarily the same size) are called similar figures.
All congruent figures are similar but the similar figures need not be congruent.
Two polygons of the same number of sides are similar, if (i) their corresponding angles are equal and (ii) their corresponding sides are in the same ratio (or proportion)
Note📝
The above question is taken from NCERT class 10 chapter Triangles Exercise 6.3 Question 8.
Practice :
In figure, if Δ ABE ≅ Δ ACD, show that Δ ADE ~ Δ ABC.
• In figure, if Δ ABE ≅ ...
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