Newton's 2nd Law (13 of 21) Calculate Acceleration with Friction; Inclined Plane, Pulley, Two Masses
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- เผยแพร่เมื่อ 10 ก.ค. 2024
- Shows you how to calculate the acceleration and tension in the string of a two block system on an inclined plane with friction. The acceleration of an object is directly proportional to the net force applied to the object and inversely proportional to the mass of the object. The second law can also be stated in terms of an object's changing momentum, such that the rate of change of momentum of an object is directly proportional to the net force applied and the change in momentum is in the direction of the net force.
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Congrats, that is amazing, you're very welcome and thanks for letting me know.
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This semester has started off on a rough note. Your video helped see the problems more carefully and in a less complex/hectic manner. Thank you!
My physic's exam is tomorrow! This was exactly the type of problem that will be on the exam. When I first clicked this video I was so frustrated at the fact that I didn't know how to set up the forces applied onto the incline or how to brake it down into its' X and Y components. SO if anybody here is struggling with same issue. I RECOMMEND watching "calculating Acceleration with OUT friction (ONE MASS) then working your way to this video. THNAK-YOU. Simple and easy.
Thank for the great comment. You can see a listing of all my videos a my website, www.stepbystepscience.com
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Glad to help, thanks for your efforts to watch and learn. Best wishes.
Just found this a few hours before my physics test, really helpful ! Thank you !
Hope the test went well. Thanks for the comment.
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+Jacklynn Ong Thank you for the positive comments and the encouragement. You can a listing of all my videos from my website, www.stepbystepscience.com
This helped me out a lot! thank you so much for your clear explanation.
great teaching man, I learn more watching these videos than I really do in class.
Thanks for the great comment. you can also see a listing of all my videos by topic at www.stepbystepscience.com
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+Shaina Ramos Great and thanks for the great comment.
You can see a listing of all my videos at my website, www.stepbystepscience.com
Very happy I found this. Similar question on my 2nd class TSSA operating engineers exam but the first time I had seen it. Glad I was able to satisfy my curiosity!
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I subscribed after watching my very first video.
Glad it helped! And thanks for taking the time to write such a nice comment.
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Hey. The vid is 4 years ago yet it still so helpful. Thank you very much bro! 😊
I can't believe that it has been that long. Thanks for the comment.
Lovely explanation. Well paced and easy to follow with workings shown without repetition. Many thanks from someone who has not studied physics for many years
You are very welcome, thanks for taking the time to write such a nice comment.
Thank you so much for explaining this in an easy to understand way.
btw you explain 1000 times better than my actual physics teacher
That's a bummer. You are very welcome, thanks for commenting.
I like the way you broke each component down.
my physics prof didn't teach me that way. I found this video very helpful. Thanks again.
Great and thanks for letting me know. I just tryto go Step By Step, in
fact you can see a listing of all my videos at my website, www.stepbystepscience.com
You're my savior for my unit test today 🙌
Hope the test went well, thanks for the comment.
You are making acceleration matters clear to me. Thank you!
Great that the videos are helping and thanks for letting me know.
You can see a listing of all my videos from my website, www.stepbystepscience.com
Thanks alots man, u made this thing look so easy, thanks alot, made me see it from another point of view
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Great, hope it goes well.
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Thank you very for watching and commenting.
Thank you so much Sir :) it's a bit complicated but you explain it very well :) two thumbs up for!
+Rae Plaza Thanks for the positive comment. I try to go through it step-by-step, in fact….You can a listing of all my videos from my website, www.stepbystepscience.com
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You are very welcome, thanks for watching and commenting...
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+Sydney Amidon You are very welcome, hope you physics grade continues to do well. You can see a listing of all my videos from my website, www.stepbystepscience.com
Very helpful thanks man
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You have saved my life.😀
Thank you! Gave it a thumbs up :)
Thanks for the comment.
thanks so much u save my life
Bro Your Soo cool 🔥 💯💪🏻 Your method Works in any inclined problem I put it against,Man Your Soo Awesome!!!
So nice of you, thanks!!
Another excellent vid..got to know the importance of the direction of forces in getting final calculation..mix up the plus and minus you will get wrong answer
Ezaddin Harun excellent point, thanks for commenting.
Step-by-Step Science good day
I have the same problem, but the next question, the hanging block is submerged in water, calculate the new tension and acceleration? Please help. I’m not given the density or volume of the second block, only the mass. The block on the incline volume is 8cm^3.
THANK YOU SO MUCH
This saved me, thank you so much
Sorry it .took me so long to respond....but thanks for the positive comment
I'm fucked
Just go step by step and practice with and without the video. Takes a little time.
Ok. Thank you Sir
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+Hatim Hamad Thanks for the great comment. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thank you so much!!
You're welcome!
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amin
You're very welcome.
I am perfoming a lab with this inclined plane with pulley and thanks to you I now know what to do!
+Gian Lumapas Great, glad that the video helped, You can a listing of all my videos from my website, www.stepbystepscience.com
just amazing......content.
excellent explaination
Thanks for the comment.
You can see a listing of all my videos at my website, www.stepbystepscience.com
thank you
Thank you! Great video
+Mechanical Me Thank you very much for commenting.
You can see a listing of all my videos at my website, www.stepbystepscience.com
I will for sure :)
Thank you so much
You're most welcome
Step-by-Step Science good day
I have the same problem, but the next question, the hanging block is submerged in water, calculate the new tension and acceleration? Please help. I’m not given the density or volume of the second block, only the mass. The block on the incline volume is 8cm^3.
Thanks a lot 🙏
Welcome!
Thank you very much🤗
You're welcome !
Isn't the coefficient of friction equal to tangent angle theta?
What if you have two masses on the plane connected by a rope? Do you just add (or subtract) the m3g and Ff3?
Thank you
AMAZING!!!!
Just for you!
What if you're given the coefficient of static and kinetic friction. What would you plug in for the u in the final equation to find out acceleration?
Kinetic since it is moving. You can a listing of all my videos from my website at www.stepbystepscience.com
Masses m1 and m2 are connected to a string passing over a pulley as shown in above diagram . Mass m1 starts from rest an falls through a distance d in time t .. Now by inter changing the masses the time required for m2 to fall through the same distance is 2t , therefore , the ratio of masses m1:m2 is?? angle =30°
Plz answer this problem
Why dont you add the forces in the y direction (m1gy and fN) when taking the sum of forces?
hands down
What if m1 is missing and the direction of acceleration goes through the opposite of the direction on thw video
This was awesome! You've taken the ambiguity out of physics 105. Please come teach at BYU.
is that BYU like Brigham Young Univerisity?
Yup, I'm currently enrolled there and this video really helped solidify concepts that before seemed vague.
Cool, I teach at a school in Berlin, Germany.
This is gonna save my butt in today's test!
Hope the test goes well, you can see a listing of all my videos at my website, www.stepbystepscience.com
what will be reslt if diagrum change to mirror view
May I ask, when you found the Ff, you took the product of 0.12 and m1gy, but are we not supposed to switch the sign. Since fN and m1gy are equal in mag but not signs? I appreciate your help.
I m not 100% sure that I fully understand your question but...When I calculate Ff I am just getting the magnitude of the friction force. I account for the sign of the friction force when I put it in the acceleration equation by making it negative. Since it points in what I have designated as the negative direction. Does that help?
how can I calculate if I want to only find the acceleration of M1 ? Thanks
cool trick for acceleration
Thanks.
hello, what happens if they are asking me for the acceleration of the block m1 only. I believe I need the value of the force tension so I can calculate the acceleration? please help
In this case both blocks have the same acceleration. And you should not need the tension force.
Your answer is wrong . m1 has a greater mass than m2 , so the system will accelerate toward m1... The friction force will act to the right due to the motion of m1(left) and the tension acts to the right. The acceleration is -1.75m/s^2
No it is not, sorry.
Sir,Can we put zero for friction force for a frictionless plane in this equation to calculate the acceleration of the system
yes you can.
I hope I get a perfect score today. thanks lol.
thanks bud
no problem dude
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You are very welcome.
I have a problem where you have to solve for m2 if it is to descend 12.0 m in 3.00 s. Idk what to do ;7;
Is that Acceleration for each object 1 and 2? Because there is a question asking two acceleration of each object
Yes, because they are attached by a chord that does not stretch they have the same acceleration.
If m1 is greater than m2 wasn't friction supposed to be up the incline and m1 block wasn't it supposed to accelerate down the incline,I don't get that free body diagram.
thankyouuuuuu
You are very welcome. You can see a listing of all my videos at my website, www.stepbystepscience.com
So it means tad m2 will always go down no matter how heavy m1 is??
No, I made a series of videos called will it accelerate.
How come the object is moving up when the m1 is greater than m2? am a bit confuse here.
Because object m1 is on the inclined and its "gravitational" force is not vertical but is parallel to the surface of the inclined plane.
When you add up: Ff + m1gx + m1a
You get 56.3 N
Please, that is the same thing, just rounding. you can see a listing of all my videos at my website, www.stepbystepscience.com
thankssssss :D :D:D:D:D:D:D
I need this equation for my Robotics Engineering certification... any advice?
What equation?
If you mean the equation in the video then there you have it or.....?
The whole equation for finding the masses required, when given an angle and a coefficient for friction, for acceleration to remain zero for the most part. Also, props for the lightning response. Is there any really easy way to memorize it?
Try not not think about memorizing the equation. Think about the process for coming up with the acceleration, summing up the relevant forces and masses. Start with the table without friction and add friction to the problem. Without friction it works out to be pretty straight forward. then continue to the ramp. Hope it goes well, a little practice should help you gain your confidence.
Thanks, mate! Next is Dry Friction I guess. Lel
Good video, but I think you calculated the acceleration wrong. It's 0.03 m/s^2 not 0.42
What did I do wrong?
Step-by-Step Science The work itself is right, but every time I calculate the acceleration (based on your calculations) I get 0.03 and not 0.42
I am not sure what you are doing wrong, probably how you entered the values into your calculator but I just checked it and the answer 0.42. The top half of the equation comes out to 6.7, then divide by 16, equals 0.42
Step-by-Step Science ok this is weirding me out. Once I find 6.7, if I immediately divide it by 16 without clearing the calculator it gives me 0.3. If I clear the calculator and write it again I get 0.42. It’s even assigning both answers to the same fraction
dronite001 ??????
every video out there is ignoring the pulley's friction force...Its included in my exam..so frustrating.
RIP
Lets say the mass of m2 was unknown, but you knew m1 was travelling up the incline. How would you find the mass of m2?
isnt mgx= mgCOS(theta) and mgy=mgySIN(theta) ?
Yigah Lhamo I think I got right. The side adjacent to the angle, mgy = mgCOS(theta). Cosine is adjacent over hypotenuse. The opposite opposite the angle, mgx = mgSIN(theta). Sine is opposite over hypotenuse.
your volume is too low
I just check and mine it is OK.
Maybe you need to turn yours up?
This semester has started off on a rough note. Your video helped see the problems more carefully and in a less complex/hectic manner. Thank you!
Thank you so much!!
This semester has started off on a rough note. Your video helped see the problems more carefully and in a less complex/hectic manner. Thank you!
This semester has started off on a rough note. Your video helped see the problems more carefully and in a less complex/hectic manner. Thank you!
Great and thanks for letting me know. I just tryto go Step By Step, in fact you can see a listing of all my videos at my website, www.stepbystepscience.com