Newton's 2nd Law (11 of 21) Calculating Acceleration with Friction; Table, Pulley, Two Masses
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- เผยแพร่เมื่อ 4 ต.ค. 2014
- Shows how to calculate the acceleration of a two block system with friction using Newton's Second Law. One of the blocks is on a table with friction and the other hangs off the end of the table over a pulley. The acceleration of an object is directly proportional to the net force applied to the object and inversely proportional to the mass of the object. The second law can also be stated in terms of an object's changing momentum, such that the rate of change of momentum of an object is directly proportional to the net force applied and the change in momentum is in the direction of the net force.
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I got the concept in just 9 minutes..after wasting 1 hour on my textbooks..Great explaination👍👍
Awesome, videos can be god that way.
Same!
I have a dynamics unit test tmr and I could never figure out Force of Tension until I saw this video as well.
same
What type of legend are you. Cheers for the video man.
this video is so awesome. completely helped me to understand a concept that I had so many issues with.
This saved me so much time. I spent almost 4 days trying to understand the concept of Newton's second law and this cleared it up in a matter of minutes.
So glad that it was helpful. Best wishes.
@@stepbystepscience CLEARLY, gravity AND ELECTROMAGNETISM/energy are linked AND BALANCED opposites (ON BALANCE); as the stars AND PLANETS are POINTS in the night sky. Consider TIME (AND time dilation) ON BALANCE.
The tides are CLEARLY related to E=mc2 AND F=ma. These equations represent a balanced two dimensional surface OR SPACE ON BALANCE (as what is the MIDDLE DISTANCE in/of SPACE). The stars AND PLANETS are POINTS in the night sky. The rotation of WHAT IS THE MOON matches it's revolution. Get a good LOOK at what is the fully illuminated AND setting Moon. Great. Compare this with what is the orange AND setting Sun on balance, as they are both the SAME SIZE as what is THE EYE (ON BALANCE) !!! Great. c squared represents a dimension of SPACE ON BALANCE. This explains the fourth dimension AND the term c4 from Einstein's field equations. Consider what is THE SUN ON BALANCE. Excellent. Notice the black “space” in relation to what is THE EYE ON BALANCE, AS outer “space” involves full inertia; AND it is fully invisible AND black. The tides are CLEARLY, fundamentally, and necessarily related to F=ma AND E=mc2 (ON/IN BALANCE) !!!
Define “mass”. You can't. BALANCED inertia/INERTIAL RESISTANCE is fundamental.
WHY THE TIDES ARE NECESSARILY ELECTROMAGNETIC/gravitational IN BALANCE, AS THE ROTATION OF WHAT IS THE MOON MATCHES IT'S REVOLUTION; AS ELECTROMAGNETISM/energy is gravity ON BALANCE:
Gravity AND ELECTROMAGNETISM/energy are linked AND BALANCED opposites ON BALANCE, AS ELECTROMAGNETISM/energy is gravity ON BALANCE. This NECESSARILY represents, INVOLVES, AND DESCRIBES what is possible/potential AND actual IN BALANCE, as TIME dilation ULTIMATELY proves ON BALANCE that ELECTROMAGNETISM/energy is gravity ON BALANCE. “Mass”/ENERGY involves BALANCED inertia/INERTIAL RESISTANCE consistent with/as what is BALANCED ELECTROMAGNETIC/GRAVITATIONAL force/ENERGY, as ELECTROMAGNETISM/energy is gravity ON BALANCE. This explains F=ma AND E=mc2. TIME is NECESSARILY possible/potential AND actual IN BALANCE, AS ELECTROMAGNETISM/energy is gravity ON BALANCE.
BALANCE AND completeness go hand in hand. TIME is NECESSARILY possible/potential AND actual IN BALANCE, as ELECTROMAGNETISM/energy is gravity ON BALANCE. Consider BALANCED BODILY/VISUAL EXPERIENCE !! It has to be this way in order for INVISIBLE bodily experience to be understood ON BALANCE. It's called QUANTUM GRAVITY. Consider what is THE MAN (AND THE EYE) who IS standing on what is THE EARTH/ground. Touch AND feeling BLEND, as ELECTROMAGNETISM/energy is gravity ON BALANCE. So, ON BALANCE, what is BALANCED inertia/INERTIAL RESISTANCE is fundamental. Energy has/involves GRAVITY, AND ENERGY has/involves inertia/INERTIAL RESISTANCE. Gravity is (CLEARLY AND NECESSARILY) proven to be ELECTROMAGNETISM/gravity ON BALANCE.
If we understand E=mc2 and F=ma to be in balance, then gravity/acceleration involves BALANCED inertia/INERTIAL RESISTANCE. So, this then explains why the rotation of the Moon matches it's revolution. (The perpetual motion of the Moon is also CLEARLY accounted for.) The stars AND PLANETS are POINTS in the night sky. Gravity and ELECTROMAGNETISM/energy are linked AND BALANCED opposites, as gravity is ELECTROMAGNETISM/energy. Accordingly, the planets will move away very, very, very slightly in relation to what is the Sun on balance. Consider the fully illuminated (and setting) Moon AND the orange (and setting) Sun when manifest at EYE LEVEL/body height. They are the same size as the eye AS WELL. NOW, the sky is blue; AND the Earth is also blue. The Moon is about one quarter (27 percent) the size of the Earth. The surface LAND area of the Earth is 29 percent, and this is precisely between one quarter and one third. The connection with lava is CLEAR. (Consider the role or relation of WHAT IS THE EYE ON BALANCE !!!) The stars AND PLANETS are POINTS in the night sky. Lava even manifests as blood red. Indeed, it is a very great truth that THE SELF represents, FORMS, and experiences a COMPREHENSIVE approximation of experience in general by combining conscious and unconscious experience. I have a preponderance of evidence that CLEARLY proves that the sizes of the fully illuminated (AND setting) Moon AND orange (AND setting) Sun are not meaningless, random, or insignificant. Indeed, this is CLEARLY CONNECTED with the fact that the rotation of WHAT IS the Moon matches it's revolution. GREAT. TIME dilation ULTIMATELY proves ON BALANCE that ELECTROMAGNETISM/energy is gravity ON BALANCE. This NECESSARILY represents, INVOLVES, AND DESCRIBES what is possible/potential AND actual IN BALANCE, as ELECTROMAGNETISM/energy is gravity ON BALANCE. Indeed, TIME is NECESSARILY possible/potential AND actual IN BALANCE; as ELECTROMAGNETISM/energy is CLEARLY and necessarily proven to be gravity ON BALANCE.
Finally, consider said WHITE Moon (on balance) in relation to what is the blue sky AND the tides.
By Frank DiMeglio
Thank you, this video was really helpful!! You did an excellent job explaining each step👍🏻
Thanks for the comment...you can see a listing of all my videos at my website.....www.stepbystepscience.com
Thanks That was very helpful , keep it up . you are doing a great work
I didn't know Vince Vaughn taught physics... Thanks for the help Vince!
this was the only video i could find that helps with the acceleration with friction and pulleys thanks lol
Wow, you are very welcome, thanks for commenting.
Amazing. You've made it so lucid and clear.
+nishant gurrapadi Thanks for the positive comment, I try to go over everything step-by-step, in fact….You can a listing of all my videos from my website, www.stepbystepscience.com
Wow thank you so much.... this video really helped me on my assignment and cleared any confusion I had in this topic. Awesome video!!
Great and thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com
Great video,i have an upcoming test and i will definitely be able to get this done now, kudos :)
Great hope that the test goes well. You can see a listing of all my videos at my website, www.stepbystepscience.com
Thanks so much Brian. You saved me from a lot of headaches. Cheers. I got an exam in the next 12 hrs.
Best of luck on the exam and thanks for the nice comment!
itz a really helpful video! have you done a problem where the block is kept on an inclined plane and a force is given to the inclined plane? Plz share the link if you have,.... thank you
Thanks! After hours of reading my textbook until I have a headache and filling a recycling bin with crumpled up papers, I got the concept in 5 minutes thanks to this video! I wish I could like this video once for each incorrect answer in those hours.....
You're very welcome, glad that you found the video helpful and thank you very much for commenting.
At 6:50 in the video, isn't the force of friction actually 17.15 N rather than 17.5 N? Multiplication error which causes a chain of errors. The actual acceleration then would be 2.00 m/s^2 for the system. I think you just read it too fast and missed the 3rd digit on your calculator. Thanks though for the review practice! Really helpful for test tomorrow.
maybe he used g=10 like i do to simplify stuff when practicing.
this has little impact on the Tension calculation, T=31.2 N
yes i agree . he made a mistake
Not quite a mistake. Probably taking the problem from a textbook where they used g=10m/s instead of 9.8 If you use 9.8 you get 17.15, but if you use 10 you get 17.5.
@@michaelcross6269 if he was using g=10 then he would have found Ft=m2g-m2a to be 32.1, but no he used 9.8
Thank you so much for making this video! It was very easy to comprehend; have a good day! :)
And thanks to you for the nice comment!
@@stepbystepscience no problem and thanks again! :D
You sound like Tom Hanks!!!! Very Helpful!!
Thanks so much, this really helped me on my computational physics assignment. We had to write a python script to calculate this problem with any variables.
Glad it helped sounds like an interesting assignment.
Thank you for explaining why the tensions cancel out
what if there's also a friction in the belt? how to do it pls reply
i have the same kind of question but it says the maximum tension for the string is 40N and i need to find the max mass the string can hold and the m1 is 2kg so should i just go backwards? and he gave me static and kinetic friction so which one should i pick to use
THANK YOU so much. I was struggling with this because our physics teacher never teaches anything. This helped me A LOT!! (:
You are very welcome and thanks for commenting. What does your physics teacher do if he/she never teaches anything?
He basically just talks about all this useless stuff we don't need to know and random calculus facts. Then he gives us tests on stuff we never learned. I am trying not to die in this class this year
iPanda Bummer, a teacher should never test on something he or she has not taught.
Sir just wanted to ask
Aren't you supposed to multiplie the kgs by 9.8, I'm asking coz sir added them directly
Super helpful and was exactly what I needed to understand my hw!
Great, and thanks for commenting.
How am i suppose to calculate the same question when i have another object placed above the object below?
Hey, you saved me life. Really. Thank you.
Glad I could help! You're very welcome.
Thank you so much Sir, you really helped me with my assignment!
Most welcome! Are you having school at home because of the virus.
@@stepbystepscience Yea, I'm having online classes now, sorry for the late reply.. didn't check my email
I'm confused, why doesn't the friction force act on mass two, partially counteracting the tension force pulling it upwards?
What will be if the string is elastic and what will be the graph Between displacement vs time for m1 object??
6 years later and this vid is very helpful
Yes, it doesn't get outdated. Glad it was helpful.
whats up with 9:27
i need answers
@@tinyeung3468 It says Ft=m2g-m2a
Ft=31.3 N
If you still need to know...
@@sunnythind8574 2 years ago wow
@@sunnythind8574 hes talking about the blood curling screams
Thank you my man!
You bet, thanks for watching!
Thank you so much sir for this helpful video
Thank you for commenting.
Sir iam very pleased with your calculations...can you do for kc calculations at equilibrium concentration
Thanks, I mainly just make physics videos.
Thank you so much!
You're welcome!
Sir pls tell me value of Ff in that equation
at 4:22 why did you swap over Ff and m2g? is that a rule?
very greatful, thanks!
You are welcome!
Can I ask, what if the m2 is missing and the rest is given. How will I able to solve it?
What would be the accel if the 2 masses were the same? No friction
Rlly...thx alot...i skipped lot of classes and i lost...thx for your free tutor...im havin exam next week:3
hope the exam goes well!
Good video very helpful! The only thing is that when I multiply 0.25 x 7 x 9.8 I get 17.15 not 17.5. Very minor, but I kept getting a slightly different end answer.
multiply by 10
@@adityapopuri8796 I think you might be a bit too late lol
@@filipkapera5659 yeah lol
exactly what i needed!
Wonderful!
I tried solving this using a different (but equivalent) method that I learned in my textbook. When I solved for a, I got 2.00 m/s^2 instead of 1.97 m/s^2. I looked for what was different and found that you put the force of friction as 17.5 N, but 0.25 * 7 kg * 9.8 m/s^2 = 17.15 N. So, there was a minor mistake in the video, but otherwise, it did help me to understand these types of problems better.
OK, thank you
What if there was another pulley on the left side with another mass hanging down?
How would I calculate acceleration of the system using both the static and kinetic friction?
+kyle courtney Gets a little complicated, but it is like an Atwood machine. You can see a listing of all my videos at my website, www.stepbystepscience.com
You make physics fun!
That is a great comment.
Thank you thank you that’s all I have to say, thank you sir.
Very welcome and that is more than enough.
Do you have any videos on pulley systems where the pulley has mass and friction. We have to calculate the acceleration of two hanging masses by a given pulley with a given radius, mass and coefficient of friction for the pulley.
Sorry but I do not. You can see a listing of all my videos at www.stepbystepscience.com
Step-by-Step Science either way, thanks for the video and for the reply.
i have a similar question, but it includes the mass of the pulley's solid disk aswell as the radius. how would i go about this?
+R0ARMC rotational kinematics or rotational inertia…a bit more complicated…
You can see a listing of all my videos at my website, www.stepbystepscience.com
7:20 - how to find Ft
Superb !
Thanks for the comment.
I feel like I'm learning physics from Vince Vaughn and I really enjoy it.
Since I've stopped crashing weddings I had to find something else to do......
what it that tool you are using for that drawing? amzing!!
I am very low budget, MacBook Pro, internal camera and mic, recorded with QuickTime and Keynote for the presentations. Thanks for the comment. You can see a listing of all my videos at www.stepbystepscience.com
dammit!! this is soooo helpful!!! Thank uuuu
Great you found it so helpful.
u r the best teacher
Very nice of you to say...You can see a listing of all my videos at my website, www.stepbystepscience.com
THANK YOU!
You are welcome
Thanks a lot sir🙂🙂🙂
You are most welcome, thanks for the comment.
I tried doing going through your steps for a problem but for the tension i ended up getting 0.910 when the answer was supposed to be 9.105. What exactly did I do wrong?
'The video has 31.3 N as the tension not 9 or 0.9???
what it that tool you are using for that drawing? amzing
It is just Apple Keynote, but it works pretty well.
Great!
Thanks.
thanks... I really thought I was gonna fail
Hope it goes well.
Wait... are both tension forces equal? If so, that makes what I'm doing a whole lot easier...
Yup, Equal in magnitude but opposite in direction. For example, +10N + (-10N) = 0N.
.25(7kg x 9.8m/s^2) =17.15N not 17.5N. Just pointing this out because this will change the overall answer to 2.0m/s^2. Instead of 1.97m/s^2.
Rebecca Krych Thanks for letting me know, I'll try to make an annotation on the video.
2018 yess
Why do we choose positive direction to be down for m2?
Because that is the direction that the object will be moving.
why do we do m1 + m2 instead of just m1 as the hanging weight isn't being dragged
+Will Harding That is a great question. We are calculating the acceleration of the whole system which includes m1 and m2. Also they have the same acceleration and therefore we must consider their combined mass.
why do you have m2g as + but not -. isn't gravity pulling down so thats -?
You can choose any direction to be positive or negative. I choose the direction that the objects are moving as the positive direction. They are two objects but they do have the same acceleration. You can see a listing of all my videos at www.stepbystepscience.com
love it
+Hutster1229 Excellent, thanks for commenting!
You can see a listing of all my videos at my website, www.stepbystepscience.com
How do I find acceleration if I'm given tension, mass and the angle
you're not given angles in these type of questions.
do you mean one with two masses, a pulley and one mass is on an inclined plane?
th-cam.com/video/OrG8vbh8ZRo/w-d-xo.html
You are the besssssssssssssttttttttttttttttttttt ever😭😭😭😭💜💜💜💜💜💜💜you made my life muuccchh easier 😭😭💜💜💜💜💜💜💔
Saaya Noor Glad to be of help. Thanks for the comment.
why do u add two equations
what if i cut the rope.how far block b will go after 3 seconds.?
this is me is it at rest (not moving) when you cut the rope? if yes then distance = 1/2at^2. The acceleration (a) in this case would be the acceleration due to gravity (g) = -9.81 m/s^2. Does that help?
What about when the direction of friction is reverse?
I am not sure that the friction can be reversed??? The force of friction is always opposite the direction of motion.
at 8:09, where does the 31.3 come from? m1*a is 13.79, the friction is 17.51?
Ft = m1a x Ff = (7kg x 1.97 m/s2) + 17N = 31.29 N....Does that help?
You can see a listing of all my videos at www.stepbystepscience.com
Ff = Mu(k)*m1*g =(0.25*7kg*9.8m/s2) = 17.15N
Ft = m1a + Ff = (7kg*1.97m/s2) + (0.25*7kg*9.8) = 30.94N
Since the number is greater than zero, this will serve as my positive comment :)
Look at me , M1 has a greater mass than M2 so normally and rationally it should accelerate to the left ..whereas M2 will accelerate upward since it has a smaller mass...that's how I think , any ideas ?
Not possible, m2 pulls down and m1 will simply slide to the right with the same acceleration. the force of gravity acts on m2 and m1 has no force to oppose that motion. Does that help????
@@stepbystepscience yea I got it clearly now ! Thank you
@@stepbystepscience But what if they were in an inclined plane where the mass that rests in the incline is greater ? Where would be the acceleration???
If you have an inclined with one mass on the incline and one mass hanging off the other side then I would say it depends on a couple of things; the mass of the masses, the angle of the inclined plane and the coefficient of friction between the mass and the inclined plane. I made some videos about this topic, here is the link to one of them:
th-cam.com/video/Bos9b6IomUk/w-d-xo.html
how did you assume FT are equal?
Newtons 3rd law, for every action there is an opposite but equal reaction.
Would (mu) be static or kinetic?
kinetic
Is the coefficient of friction static or kinetic
Since its accelerating I would say kinetic.
yes, I realized that soon after
17.15 not 17.5. Acceleration should equal 2.004 m/s^2
is it kinetic or static friction?
Before it starts moving it's static friction and after it starts moving it's kinetic friction.
In this case it would be kinetic friction.
Niceeeeeeeeeeeee !
+David Romero Thank you and Happy New Year….You can a listing of all my videos from my website, www.stepbystepscience.com
Did someone get murdered at the end?
No murders in the videos, I think that was my teenage son harassing his little brother.
god bless your soul
Very kind of you, You can see a complete listing of my videos at www.stepbystepscience.com
scream at the end tho
funny
Here’s a positive comment. Negativeness is a bliss
Acceleration for India tectonic plates is what ??so we found energy accumulated per second ??
So simple?🕉🕉🕉
What the fuck was that screaming at the end?!
I am not sure....but I can assure you that no was harmed in the making of this video...it was probably my son acting like a wild animal.
what the fuck happened at 09:28 ?? :D
I think my kids were goofing off in the kitchen....
his process is way to long ... theres much more easier quicker ways
Use this equation for next date of earthquake???🕉🕉🕉
count your maths right pls.... 0.25*7*9.8=17.15 lol== did u even use calculator to check before posting out?