ฝัง
- เผยแพร่เมื่อ 15 ก.ค. 2019
- An ancient, abandoned alien space station has been discovered. Can you beat everyone in the galaxy and reach it first?
--
It’s an incredible discovery: an abandoned alien space station filled with precursor technology. Now every species in the galaxy is in a mad dash to get there first, but you’ve got a problem. Your ship can’t hold enough fuel to get you there unless you vent caches of it into space at precise points and then come back for the fuel later. Can you reach the alien space station? Dan Finkel shows how.
Lesson by Daniel Finkel, directed by Artrake Studio.
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Ted Ed: Can you sol-
Me: No, I can’t.
We believe in you!
Loool
@@TEDEd i don't
@@TEDEd : l
TED-Ed you have too much faith in all of us
This guy who narrates riddles should do audiobooks, I swear he has the most calming voice in the world
His voice is good but you cannot ignore the soothing voice kurzgesagt narrator.
Kurzgesagt narrator is the best
.
Go see jerryrigeverything
Uhm no he doesn't
Addison Anderson is my religion
And now you're stuck on that planet without dark matter... RIP
Exactly!! That's why I couldn't solve it because it was not a good option
Wait, so what? You only need the dark matter so that you can get to the planet faster than the other aliens. You can use your regular fuel to fly off after you collect the stuff.
@@blankname6657 rewatched it i guess they don't but i feel it's implied.
Or... Or you could hitch a ride with the other ships in exchange for probably information
But now you have yarn
Step 1: Confirm dark matter has green eyes
Step 2: Ask all the aliens to leave
Step 3 : Make bigger fuel tanks
Step 4: Find a way to get off the planet now that you have a larger fuel tank but no fuel
Step 7:Sell the Minecraft and make money and buy a antimatter girlfriend and make babies with her.
AMEER ROCKZZ Step 8: ozo
This joke never gets old
This may come in handy when raiding area 51
So where we droppin,bois?
Just pretend you're a lost farmer.
Tedd M
Invite skinny medic to the raid
Dress as an Alien that guard will capture u.
What is wrong with you
Whenever I click on these videos, I know I'm not going to be able to solve the riddle. I just want to know the answer
Same
I as well
Same
@Manuel yeah, this one's insultingly simple being told you've got three full tanks worth of fuel means three trips, which means two dropoffs and one real journey, then it's just about deciding how many parsecs away you'd need what quantity of fuel, and as mentioned there's multiple options there.
honestly i'm just angrily typing because i forgot these weren't worth clicking on.
I’m just here cuz they make me feel smart
Me: Use one thing of fuel. There's no friction in space.
Genius😂
Yeah, and they specifically mentioned it's completely empty space lol
You need fuel to go faster than light though. Assuming you can go >90% of the speed of light without fuel it would take you a little over 25 years to coast the last 8 parsecs.
@@lordofthecats6397 that's not the way it works, you won't slow down in outer space. Period. Well unless you hit a planet or a an asteroid or whatever. 1 unit of fuel sends you flying at a speed higher than that of light, but due to the fact you don't slow down you can just cut the engine.
No because these are JUMPS. So basically with 1 unit, you jump to 1 parsec, but you have 0 momentum so you're actually stuck
There’s a solution to this, and it’s really easy:
Get a better ship
But you're on a government funding, and broke.
Ozo
But where's the fun in that?
Don’t care
Fun doesn’t equal efficiency
ulu
How about just build a ship with a goddamn bigger tank
Bigger tank means more mass and that will decrease the fuel-distance efficiency.
Are you the real elon musk
@@atulkumarashish584 It's not rocket science!
_wait_
Or have a fuel storage on board so you can refuel without leaving the ship
perfect that your profile name is Elon Musk hahah
There’s a problem with this:
How will you leave the space station without any fuel?
Well, once you get there first, you can wait for someone to come and give you a lift.
There might be fuel on the space station.
That's what I was thinking, you'll just be a sitting duck waiting for the aliens from other species to arrive, take the artifact from you, and leave you stranded.
@@MrEel-dc4kh Exactly. It's a space station, what else would it do?
The story says: as you go in you find some upgrades for the maximum dark matter fuel and 70 dark matter fuel
I Understood Nothing, Except..
“Universe’s Biggest Ball Of Yarn”
Ted Ed: Can you solve it??
Me: Yeah I'm trying hard..!!
(Meanwhile other species from galaxy reached there and took all the precursor technology..)
Many days past.......
Me:----- Still trying to figure out the solution....!!!!!
This comment is just LEGEND 😂😂 lol
Clarence Viñalon
But really I m yet thinking for solution....
@@sanketpatil6711 lol
...Sometime later
Precursors wake up from their hidden hibernation chambers
Track down all the civilizations that took their stuff, wipe them out
Humans slip beneath the radar
Win!!
I was waiting for long for a riddle .
Thank you
ditto
Probably not
More like a 100% not
Ay ur here
Impossible
One of you least liked comments
Where are the likes?
TedEd: “Can you solve the riddle?”
Me at 3am, with 3 Braincells left “‘(crying) nO i cANt”
@Protoxicalbedwarsguy he lost some along the way, apparently.
You actually have 3 braincells left? Wow, lucky
Interesting. I did it in 3 separate trips.
The start was the same: at the 3 parsec mark, drop off 9 units, then return.
However, I deposited no more in that cache.
I went to that cache, picked up 3 units, went forwards 5 units, deposited 5 units, then returned to the cache, where I got the 3 units to get back to the station.
Then I went to each caches and refueled, leaving me with 15 units at the 8 parsec mark, like you did.
I did that as well
That was my solution as well, after deciding I liked it more than what I came up with first: leaving 2 at 6 parsecs and 3 at 8 parsecs instead of all 5 at 8 parsecs.
me too. both is similar
Mhm, got that too
Nerds
Wait...so while we were doing this, a bunch of other species were headed for this planet. Even if we managed to get there first, we’d be stuck there without fuel, waiting for the other species to arrive. And then when the other species DID arrive, we’d be at their mercy with no means of escape
Human: "Finders keep..."
(Aliens laser gun to death.)
I literally see the word riddle in a ted-ed video and smile :)
Who doesn't?
I think that these riddles are the best thing about the channel(and how it's executed plays a major role too, so thanks😊).
Other educational youtube channels: makes viewers feel smarter.
Ted ed: makes viewers feel like morons
The premium quality we subscribed for!
When it comes to riddles, yes.😂
But TedEd is a very good channel.👍👍
Come on dude this one was easy
Agree to disagree. 😑
Yes..
Quote at the beginning of this video: by Dan Brown
My ad before this video: Dan Brown's Masterclass
Me: I see you universe.
Am I gonna solve this? No.
Will I continue watching these riddles? Heck yeah!
Spaceship girl : I wasted 60 units
Of jump fuel only for creating biggest ball of yarn in universe
Me: wait what??!!!
Not 60, but forty-five.
My solution was a bit different. Still works though. My approach was to carry everything to the next parsec one step at a time. You carry everything to parsec 1, losing 5 units on the way. Repeat from 1 to 2, 2 to 3. From now on you only need 3 units for transferring all left units. Repeat until you're at parsec 8 and you have exactly 15 units left.
Takes waaaay more trips than the solution here tho haha
I did the same thing
Concur. I thought the cost-per-distance was non-linear, paying -d to advance (15-2d) fuel by d positions, so we minimize cost by minimizing d. But it turns out that the granularity is actually full-tanks, not individual fuel.
Graphically, we can quickly see that the two solutions are equivalent, and furthermore generalize to other configurations of waystations. Consider a single full tank of 15 fuel. Think of it as 9 cargo + 6 self-fuel to move itself. Then you can pay 3+3 round-trip to advance the 9 cargo to position #3 in one jump-pair, as in the video, or (1+1)*3 to advance to position 3 in 3 jump-pairs.
It follows that we could do it in two jump-pairs, of distance 1 and 2 or vice versa. It also follows that this generalizes to the isomorphic problems of carrying groceries up a staircase in 1 trip or several trips, or mowing a lawn in horizontal or vertical stripes. In every case, you're covering the same total area, and all partitions of an area sum to the same area.
the problem is that the total distance traveled in order to get 23 parsecs away would be so much more under that method.
Yeah but you are saving units too. I solved by your method and saw that when you reach 8 parsec you actually have 18 units left which is 3 more than required to reach 23 parsec. There is one problem though which is you take more time and by the story that they told you need to reach their as soon as possible.
@@feartheghus That's not true. If you don't have any unused fuel from the 45 units anywhere by the end of the trip, then you've still travelled 45 parsecs no matter what way you do it.
By gods mercy it took me 15 min to solve the problem the points are same at 3 and 5 but the process is different
The idea if.anybody conciders.is
Place 9 fuels at the 3 point marks and now go back. And place 5 at 8 marks by taking 3 from the 3rd mark.of the 9 placed and use the 3 while returning also so at point 3 we have 3 and at 8 we have 5 now we at point 0 fill and move on
Well thought!
Same solution as in the video just a different order, but yeah... also took me way too long to find x / the 3 point mark ^^
how I worked it out, took me a little longer before it occurred to me that on my second trip I could refuel twice from cache a.
I had the same idea! It is actually better because it is a shorter process I think...
I did the same
I actually got this one, I came at it slightly different than they did. I figured the trip would take 2 fuel dumps and 1 full trip. So for the first trip I wanted to dump enough fuel to refuel at the first dump site 3 times. A dump site at 3 lets you use 15 fuel to dump 9 units of fuel at point 3 and return. Next I wanted to dump enough fuel at the second point to refuel at the second site once. You can take 15 units of fuels, drive to the first dump site, take 3 units from the first dump site, drive out to 8(now the second dump site), leave 5 units, return to the first dump site, pick up 3 units, and then return home. Next, you have 3 left over at the first dump site, 5 at the second dump site, and 15 in your base. Refuel at each dump site and you can make it to the end with no problem.
*makes it to space station with no fuel and only finds yarn inside*
WELP
*uses yarn to make a noose*
Try moving as much dark matter forward one unit at a time:
distance from original base: 0->1->2->3->4->5->6->7->8->23
fuel stored after depleting previous location: 45->40->35->30->27->24->21->18->15->0
I feel like the examinations paper questions should be like this and we're all will excited to study and everything lol😂
I admit that Ted ed riddles are difficult... But this one is an exception...
This one was *IMPOSSIBLE* !!!
first riddle I actually solved on my own :P
Congrats The Seperator!
Well done!
Lies
@@stunnerkumah what
Cats of Wisdom he’s lying
It also works with cashes at each of the first 8 parsec marks. Drop off 3 units at stops 1-3 on the first run and drop off 1 unit at stops 4-8 on the second run. Then you'll have 1 unit of fuel at each of the first 8 parsecs for your final journey from the start to the alien base
I did a different (and IMO easier) approach:
You need 23 fuel to go all the way to the space station. That means you have 45-23=22 fuel to go back and forth for storing fuel. If you go back, you also have to cover that area again so in you whole journey, you can only go back up to 22/2=11 parsecs. Your tank has 15 slots so you need to reach parsec 23-15=8 with a full tank. That also means you have to store fuel at that point which already uses 8 of your 11 parsecs you're allowed to go back. That means that parsec 3 is the most far spot you can reach as a second storage point without running out of fuel.
And from that point it's just traveling and seeing if it works.
Heeeeeey I ant reading that
@@Fluffers355 ok
1:15
solution
Use a unit of fuel
then wait
the ship will continue moving because of inertia, says newton
Step 1: load 15 units
Step 2: grab all that’s left and dump it on the floor of ur ship
Step 3: replace when u run out
I love your riddles so much!! Keep up the good work
I love this!it helps me so much with science and problem solving in school!I LOVE THIS CHANNEL!!!!
I really love this animation style!
Wow the first hit sounds like a very popular meme
hmmmm
I wonder which meme is that
Melody Thieme it’s a bit like Area 51, everyone it rushing to get alien things
I read that in Dr Phil’s voice
3rd riddle (I think) that I’ve gotten right from here. I feel so accomplished finishing these, thanks for making them!
I love these not only because I’m a puzzle nerd and I *love* them, but also because my teaches love to play them, and I seem interesting when I tell them I watch them in my spare time.
Problem is, unless you found dark matter or an alternative propulsion system, how do you get back?
Yeah sure you can wait and get rescued reasonable guy now shush /s
You wanna know how I did it? This is how I did it Anton.
I never saved anything for the jump back.
Alien help, duh.
Use the precursor technology
Can you save enough fuel to get back? Well, definitely not... but here's another riddle: How much fuel is initially needed to make a round trip? And, what is your strategy? Hint: you need more than 46 units. I could say even more than 60, but what's the actual amount needed?
You can also do it with the same points in a different way. Put 9 cells at 3 parsecs and go back so base. Refuel fully in base, then go to 3 parsecs, refuell the with 3 cells, go to 8 parsecs and deposit 5 cells there. Use the last 5 cells you have left to return to 3 parsecs and use three more of the cells stashed there to return home. Now you can refuel fully to 15 there, pickup the last 3 cells at 3 parsecs and the 5 cells at 8 parsecs to be fully fueled up at 8 parsecs
Always excited for a riddle
Your finaly pumping out riddles again
Universes biggest ball of yarn lmao I’m dying🤣 4:10
I subscribed your channel because your riddles are good for brain exercise.
Even, if I can't solve it I atleast try.
And that gives me pleasure 😇
This animation makes the video so easy to understand
0:22
Of course I’ve got a problem!
Hi ted-ed
Another interesting episode..
Thanks for educating us...🙏👍😊
Why would I need extra fuel if there is nothing to slow me down in space...
that’s such a satisfyingly methodical approach to the riddle that I’m sure I wouldn’t have figured out if I was stuck in space
Very elegant solution. Love it.
The answer to all of these titles?
No, I can't
But I'll still watch
*Ted-Ed:* Can you solve this riddle?
*Me:* _o_O_
We need more of these riddles 😭
Except now you can't get back.
Wow...distances in parsecs are being travelled....
I hope one day, such space travels would come to reality...
Huh. I got something different.
1st trip: we go to parsec 5, drop off 5 off, and return with 0 (45 remaining at the spot)
2nd trip: repeat step 1 (30 left at location)
3rd trip: repeat again (15 left at location)
There is now 15 fuel at parsec 5
Now we return to the location and refuel fully. We travel to parsec 5 (10 fuel left) and take 5 out of our cashe (fully fueled now).
We then travel to parsec 8 using 3 fuel (12 left) and drop 9 off at parsec 8
With the remaining 3 fuel, we travel back to parsec 5 and take all of the remaining fuel at parsec 5. With 10 fuel, we use 3 to go to parsec 8 (now with 7 remaining) and get out all of our fuel (9 btw) and manage to get to the destination with 1 extra fuel.
Your solution uses 59 fuel (45 at base + 15 in tank assuming tank is full at start -1 fuel remaining getting to goal), while the solution on the video only uses 45 fuel. Your assumption that the tank is full at the start is incorrect.
Ahhhh. I see what I did wrong. Thanks for the tip
"But now, every species in the galaxy is in a mad dash to get there first and claim it for themselves."
Snails: *cries in subground speed*
Finally!! This is the first ted ed riddles I can solve 😭😭
Just add an additional tank.
Bruh I was watching Hamilton animatics how tf did I end up here...
**confused speech**
I first read this comment and thought it said Hamilton animaniacs and was wondering when that show rebooted to have a reference to the Hamilton play
Love the art here
Ted Ed I just love your videos
Yay problem solved
now she is stuck in an ancient abandoned alien space station with no fuel to go back
Congratulations, you're now stuck on an alien planet with no fuel to get home!
lol
What if that was the plan? What if they didn't want to go home? They planned on a one way trip for colonization purposes. Terraforming they say.
I praise the people that can actually figure out these riddles
DO MORE RIDDLES!!!
Ted Ed: can you solve the -
Me: no
In specifying the problem, it left out the very important fact that you apparently didn't need to find a solution which left you with enough fuel to return home... You only needed to make a one way trip. And everything about "getting there first" is pure fluff, the problem only involves getting there at all.
Very nice, but a pity that you have no way to go back now. kkkkkkkkkk love this riddle!
Plot twist: all the others already got there as you solved the riddle
Ofcourse, what's next, The Einstein field and Topology of Hyperspace riddle?
Is it just me or was that orange costume similar to Gordon Freeman's from *Half-Life,*
ONLY on St3roids.
Just you man!
Nope. Just you
In interstellar space, there would be almost nothing to slow you down. Once you leave a particular solar system, you should be able to plot a course that should leave you very free of anything to slow down for, and ergo, you need no fuel to keep going. You will keep going at the same speed until something slows you down. Actually, the fuel in question would be most necessary when slowing you back down, especially in combination with a gravitational assist.
I came up with a similar solution. It used the same cache points, but left less fuel in the vacuum of space, so I’d consider it a more elegant solution. Jump to 3, cache 9, return 3. Pickup 15, jump 3, pickup 3 (leaving point 3 with 6 fuel left on it), jump 5, cache 5 (at point 8), return 5 (to point 3, which has 6 fuel cached), pickup 3, return 3. Pickup 15, jump 3, pickup the 3 fuel left at 3 to return to full, jump 5, pickup the 5 cached at 8 to return to full. Jump 15 to goal.
Ted ed: can you solve it
Me : no but my friends can't solve this too😂💪
I wear my Dan Brown Origins shirt to school!
Btw TedEd: Antimatter is not Dark Matter ~ Yours Truly, Convicted Science Geek
@Adam Filinovich Haha, though they used the quote on Anti instead of the actual Dark
There's something oddly calming about all of these videos.
Hey Presh, my solution used the same cache points as yours but I did the trips in a different order. I first stopped at 3 deposited 9. Then I stopped 3, refueled, stopped at 8, deposited 5, went back to 3 refueled to get back to start. Then I stopped at both 3 and 8 to refuel when making the final trip.
We: How many unsolvable riddles do need for u to stop?
TEDed: YES!
I Solved it
Damn
The very first riddle from this channel I was able to solve
Feels So GOOD 😌
Ahh I love TED ED riddles!
You can cache at every single parsec and end up with the same amount of fuel being used. Carrying 31-45 fuel one parsec forward takes 5 fuel (2 round trips and 1 one way). Carrying 16-30 fuel one parsec takes 3 fuel (1 round trip and 1 one way). You can go 3 parsecs in and have 30 fuel cached (5*3=15) and go a further 5 parsecs and have 15 fuel (3*5=15). Now that you are 8 parsecs in with 15 fuel, you can complete the total trip (8+15=23). Where you cache doesn't matter as long as you have enough fuel to make the trip, since it's a linear problem.
Load in 15, fly one step, drop 13, go back. Repeat. Load in Rest fly to point 1. Now you sit here with 40 units.
Do the same again for point 2, you end up in point 2 with 35 units.
Do the same again for point 3, you end up in point 3 with 30 units.
On your way to point 4, you only have to load up your ship twice (2*15). So you only use up 3 units to carry everything to point 4. You end up in point 4 with 27 untis.
Do the same again for point 5, you end up in point 5 with 24 units.
Do the same again for point 6, you end up in point 6 with 21 units.
Do the same again for point 7, you end up in point 7 with 18 units.
Do the same again for point 8, you end up in point 8 with 15 units.
Use up the remaining 15 units to fly to point 23, the alien base.
Voila!
Yeah since there's no cost to dump fuel, this one can be brute forced and just constantly move the stash up one at a time until reaching 8.
Or you can just blast off, then shut off the engine because space is frictionless. 😏
You are traveling parsec's, many, many, many light years, you would hit the planet, and be in a universe, trillion's of year in the future,
Karthikeya 5638 *BECAUSE SPACE IS FRICTIONLESS.*
All that big brain riddle solving just to get stuck on a different planet
I love the riddles.
They alos good animated, like the most videos on this channel.
I SOLVED IT!!!! THIS WAS MY FIRST TIME BEING ABLE TOO!!! YYYYYAAAAAYYYYY!!!!! IM SO HAPPY;!!!!!
Extension: What's the minimum fuel needed for 25 parsecs? How about 30?
My guess is 59 units for 25 parsecs and around 115.1 for 30 parsecs
@@enderyu
Correct on 25. 30 parsecs requires 118.
I love these videos and it reminds me of Star Trek
Im so happy I actually got this one
I'm just happy that we're finally admitting that the speed of light is not a limit.
Um...
Star Wars already did that 😁😁😁
“Alien facility filled with Precursor technology” Is this subnatica?
Finally someone said it. +1 point Xd
Just transfer the DMs one parsec at a time going back and forth until you collected 15 at the 8pc mark and fly to the target.
Although more smaller trips are needed this solution works too and is IMO less complicated. Also the total distance traveled is the same
:
My fav solution is using every point as cache, which yields the same state as the proposed solution at critical points 3 (30u left) and 8 (15u left): that's a very nice invariant
3:45
XO?
This has become un-advertisement friendly...
Wdym?
*Dark matter matters!*
See what I did there💪😏
I can't support you on Patreon so i watch a full 1:32 ad, please keep making amazing content.
I can never solve these but I love the little stories that they come with