36:56 we can solve these combustion equation more easily First write the equation for examole C76H154 + O2 Now we can solve this with a trick the carbon number reamains same on both side due to 1:1 ratio so it will be 76CO2 + now the hydrogen number on the right hand side is always divided by 2 because of 1:2 ratio so the hydrogen becomes 77H2O and final equation will be C76H154+114.5O2--->76CO2 + 77H20
@ASHAR240 absolutely yes 👌. For the complete combustion of alkanes the number in front of the O2 is always 1.5n + 0.5 where n is the number of carbon atoms. 😃 I explained it in the way that I did at that time because I wanted to make sure everyone was comfortable balancing any equation. This is important because sometimes combustion is incomplete, sometimes you burn alkenes and sometimes alcohols. So you've got to be flexible
For skeletal formulae of alkenes you would show the double bond as a second line. So the shape would be the same, but one of the bonds would end up looking more like a = sign
In terms of physical properties of alkanes, where does that appear on the spec and is it necessary to know them? I haven't come across any questions on solubility or polarity for example
The big one is boiling point. Not specific to alkanes but you need to know about larger Molecules having more van der Waals forces. This fits into the Bonding topic and to Fractional Distillation. Solubility can come up in a few places. Most commonly in chemical analysis and spectroscopy, put simply from the point of view of alkanes being non-polar and therefore dissolving non Polar things and being insoluble in water. It can come in more indirectly with ideas about why they are not susceptible to attack by nucleophiles or electrophiles as well
You're right. The temperature for catalytic cracking that I wrote should have been in kelvin! Great spot! It's about 500 degrees Celsius (it's fine to generalise to an approximate temp as different refineries vary slightly)
Hi, yes, this video will be suitable for any exam board. I teach AQA so I always make sure it covers everything needed for AQA. All exam boards are at least 95% the same though. The main differences between them is not the content they include, but rather how they structure the course, what topics are on each exam and the question style
Sorry but you have catalytic cracking and thermal at the same temp because one is in kelvin and the other Celsius. But otherwise your videos are amazing!!!
I'm really glad you found the video useful, thanks for the feedback. Good spot with the mistake... I said the right thing, but then wrote it in celsius- oops!
Correct... and not just alkanes. For any molecule at all the Covalent bonds are always much stronger than the intermolecular forces. Typically at least 10 x stronger
It does get tricky with cylic Compounds. Good news is you are more likely to be asked to draw them as functional group Isomers of alkenes than you are to name them
Perhaps the best part of this channel is that you reply to every comment. That shows you actually do care for your audience. Great video as always
Thank you! I do really appreciate all the feedback and the encouragement. It helps keep me going!
Noticed the same , and that is kind of him . And commendable if I may add ❤.
Bro these videos are amazing, you explain everything so well. Im going to make sure to share your videos to the rest of my class ! thank you !!!!
Your kind words are much appreciated, thank-you!
36:56 we can solve these combustion equation more easily
First write the equation for examole C76H154 + O2
Now we can solve this with a trick the carbon number reamains same on both side due to 1:1 ratio so it will be 76CO2 + now the hydrogen number on the right hand side is always divided by 2 because of 1:2 ratio so the hydrogen becomes 77H2O and final equation will be
C76H154+114.5O2--->76CO2 + 77H20
@ASHAR240 absolutely yes 👌. For the complete combustion of alkanes the number in front of the O2 is always 1.5n + 0.5 where n is the number of carbon atoms. 😃
I explained it in the way that I did at that time because I wanted to make sure everyone was comfortable balancing any equation. This is important because sometimes combustion is incomplete, sometimes you burn alkenes and sometimes alcohols. So you've got to be flexible
Sir you are amazing, thank you so much for your videos. I have an exam tomorrow and this video sums it up beautifully!!!
That's lovely to hear! I'm glad it's useful 😊
Good luck!
Is there a difference in skeletal formula of alkanes and alkenes?
For skeletal formulae of alkenes you would show the double bond as a second line. So the shape would be the same, but one of the bonds would end up looking more like a = sign
I see, thanks!
These videos are the best I’m so grateful thank you so much
In terms of physical properties of alkanes, where does that appear on the spec and is it necessary to know them? I haven't come across any questions on solubility or polarity for example
The big one is boiling point. Not specific to alkanes but you need to know about larger Molecules having more van der Waals forces. This fits into the Bonding topic and to Fractional Distillation.
Solubility can come up in a few places. Most commonly in chemical analysis and spectroscopy, put simply from the point of view of alkanes being non-polar and therefore dissolving non Polar things and being insoluble in water. It can come in more indirectly with ideas about why they are not susceptible to attack by nucleophiles or electrophiles as well
Best teacher on the whole TH-cam..Thnkuu❤
@@YamnaIjaz-z5w that's really kind of you, thanks 😊
Do we need to know about vacuum distillation for AQA?
Good question, no you do not
Great Video!!
Just got confused by temperature conditions such as At 29:45 is the unit used degree celcius or Kelvin ?
Thank You
You're right. The temperature for catalytic cracking that I wrote should have been in kelvin! Great spot!
It's about 500 degrees Celsius (it's fine to generalise to an approximate temp as different refineries vary slightly)
@@chemistrytutor Thank You !! Absolutely goated videos !!
@@zhar9177 😀👍
Hi Sir. Just a bit confused on the equation at 44:26, whether it is fully balanced. Great video. Thank you.
You're right, the green equation isn't balanced! It needs a 2 in front of the H2O and a 1/2 in front of the O2
@@chemistrytutor Thank you for the reply and thanks again for all the excellent videos Sir.
Is this also for CAIEs As level??
Hi, yes, this video will be suitable for any exam board.
I teach AQA so I always make sure it covers everything needed for AQA.
All exam boards are at least 95% the same though. The main differences between them is not the content they include, but rather how they structure the course, what topics are on each exam and the question style
Thank you so much for saving my life
I'm really glad you found it useful!
Very helpful thank you ❤🎉
I'm really glad you've found it useful 👍
So good
Thank you 😊
Hi Sir, thanks for the video, do you have any videos on chlorination and free radical equation solving?
You're very welcome!
Yes, here is an explanation videos
th-cam.com/video/-P-YWVK-v4w/w-d-xo.html
And here is an exam question walkthrough th-cam.com/video/hHIcm1QlqA0/w-d-xo.html
So helpful ❤️ thank you
Brilliant! I'm really glad it's useful 😊
Thank you very much
It was really helpful
Glad to hear that! Thanks for the kind words!
Thank you Mr be blessed
You're very welcome! I'm really pleased they're useful
Sorry but you have catalytic cracking and thermal at the same temp because one is in kelvin and the other Celsius. But otherwise your videos are amazing!!!
I'm really glad you found the video useful, thanks for the feedback.
Good spot with the mistake... I said the right thing, but then wrote it in celsius- oops!
So alkanes have weak intermolecular forces and strong intramolecular forces?
Correct... and not just alkanes. For any molecule at all the Covalent bonds are always much stronger than the intermolecular forces. Typically at least 10 x stronger
Thank you so much for this video. Very helpful indeed.
I really appreciate your kind feedback 😀
Subscribed! Thanks.
😊👍
aaa these videos are so helpful! i can't thank you enough !!❤
Thanks for your kind feedback! 😊
Thank you
You're welcome 😊
That aside, I'm sharing this
Many thanks 😊
Glad it's useful
The cyclo nomenclature was a little bit buzzy for me
It does get tricky with cylic Compounds. Good news is you are more likely to be asked to draw them as functional group Isomers of alkenes than you are to name them
@@chemistrytutor oh okay. Thanks
Thank you so much for this!
You're very welcome! I'm pleased it's useful 😀
Thank you so much😀
You're very welcome! Glad these videos are useful 😃
bye bye!
😃