@lizziellama Yes, you can refer to stage 2 of electrophilic addition, where the carbocation is attacked by, for instance, a Br⁻ ion, as nucleophilic attack. In this step, the nucleophile (Br⁻) donates a pair of electrons to the electron-deficient carbocation, completing the addition reaction. While the overall reaction is called electrophilic addition (since it starts with an electrophile attacking the π bond), the specific second step involves a nucleophile (like Br⁻) attacking the carbocation, which fits the definition of a nucleophilic attack. They aren't really a fan of using the term nucleophile when the mechanism isn't nucleophilic substitution or nucleophilic addition though. I would recommend you refer to it more broadly as the Br^1- donates an electron pair or attacks the C+
Could you please explain the concept of nucleophile and carbocation? Actually I'm learning this for the first time and the book isn't very helpful rn. Thanks for your efforts. Appreciate it.😊❤
hi sir, i need some help please, at 4:14 what do u mean by rotate? why do we need to rotate the molecule if the mirror image is the enantiomer? i’m also struggling to understand the importance of the groups now pointing in different directions? at 5:38
@maarr77 the reason we rotate the molecule is to *prove* that the enantiomers are different. When looking at mirror images you could be forgiven for thinking they were the same thing, but when we rotate one of them, we see that the two are different. We can tell they are two different things *because* the groups are pointing in different directions. So people's hands normally look like mirror images when held palm to palm, but rotate them so both of the palms face the same way and the thumbs point in different directions
Hi sir, in the nucleophilic addition relating to racemic mixtures, where does the hydrogen come from to form the hydroxyl group - or is that outlined in another video specifically talking abt nucleophilic Addition later in a2? Thanks
Hi sir. I had a question if you don’t mind. Does it matter which group you choose to put on the wedge and which group you put on the dotted line when drawing shapes of molecules. I mean generally, I’m not talking about optical isomers. Thanks.
hello, as an independent resit student thank you so much for your time in making these videos! They help a lot!
That's great to know, thank you! 😊
Good luck with your studies!
from a medical student, that was matchless sir!, it has really helped a lot in my biochem studies.
Excellent! Thanks for your kind feedback 😀
Thank you cant wait for more A2 videos 😃
Glad you've found it helpful 😀
I was struggling, there are gaps in some concepts for me, but I can say I almost understood everything in the video, so thank you a lot really!!
That's great to know 😊
Well done you!
Thank you❤ I can finally understand this topic now!!
Excellent! I'm really pleased it's useful 😀
Thank you so much u saved my life i have my exam in the morning and its 4am now
Thanks! Comments like yours make this so rewarding 😃
Good luck for your exam 👍
At 14:09, isn't the 2nd mechanism a nucleophilic substitution, because the negative ion attacks the positive carbon?
@lizziellama Yes, you can refer to stage 2 of electrophilic addition, where the carbocation is attacked by, for instance, a Br⁻ ion, as nucleophilic attack. In this step, the nucleophile (Br⁻) donates a pair of electrons to the electron-deficient carbocation, completing the addition reaction.
While the overall reaction is called electrophilic addition (since it starts with an electrophile attacking the π bond), the specific second step involves a nucleophile (like Br⁻) attacking the carbocation, which fits the definition of a nucleophilic attack. They aren't really a fan of using the term nucleophile when the mechanism isn't nucleophilic substitution or nucleophilic addition though. I would recommend you refer to it more broadly as the Br^1- donates an electron pair or attacks the C+
@@chemistrytutor Okay, thank you so much!!
Could you please explain the concept of nucleophile and carbocation? Actually I'm learning this for the first time and the book isn't very helpful rn. Thanks for your efforts. Appreciate it.😊❤
hi sir, i need some help please, at 4:14 what do u mean by rotate? why do we need to rotate the molecule if the mirror image is the enantiomer? i’m also struggling to understand the importance of the groups now pointing in different directions? at 5:38
@maarr77 the reason we rotate the molecule is to *prove* that the enantiomers are different. When looking at mirror images you could be forgiven for thinking they were the same thing, but when we rotate one of them, we see that the two are different. We can tell they are two different things *because* the groups are pointing in different directions. So people's hands normally look like mirror images when held palm to palm, but rotate them so both of the palms face the same way and the thumbs point in different directions
Very nice teaching
You just saved me 😅
Great news! Thanks for the feedback! 😀
Very eazy to understand
Good job sir
Thank you 😊
Glad it's helped you
I too do tutoring, how would you say you prepare?
@@chemistrytutor
13:28 electropihlic addition or substitution ?
Addition!!! Good spot!!
Hi sir, in the nucleophilic addition relating to racemic mixtures, where does the hydrogen come from to form the hydroxyl group - or is that outlined in another video specifically talking abt nucleophilic Addition later in a2?
Thanks
It comes from the water solvent. I go into it in more detail here
th-cam.com/video/dJn0c1rcAxo/w-d-xo.html
@@chemistrytutor thanks for ur help as always
Thanks man literally saved me
@@Sanrio-ut9jr excellent 👌
does this covers all the topics mentioned in a2 chemistry course of optical isomer?
That was my plan... certainly it covers all of aqa. It may depend on your course
Can you make videos like this for year 2 Aqa a level as well please
At the moment I'm prioritising exam question walkthroughs as we get closer to the exams. But I'll do a few over the next weeks
44 sec in and i already know a bit better
Brilliant! Its a tough topic, so stick at it!
@@chemistrytutor thank you
@@Masowe. 😀
you're amazing!
Thank you 😊
Thanks a lot
Most welcome 😃
very good video 👍
Glad you found it useful 😀
Hi sir. I had a question if you don’t mind. Does it matter which group you choose to put on the wedge and which group you put on the dotted line when drawing shapes of molecules. I mean generally, I’m not talking about optical isomers. Thanks.
Good question - no, does not matter at all. They're all equivalent just pointing to different directions
@@chemistrytutor thanks a lot sir!!!
🙏🙏🙏🙏
😁