Mechanical Engineering: Particle Equilibrium (7 of 19) Tension of Cables Attached to Hanging Object
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- เผยแพร่เมื่อ 19 มิ.ย. 2015
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In this video I will calculate T1=?, T2=?, T3=? of a 500kg mass hanging from a ceiling.
Next video in the Particle Equilibrium series can be seen at:
• Mechanical Engineering...
Bless your soul you amazing man! I have a test tomorrow and i get everything you are doing, keep going.
you passed?
This is amazing. Thank you SO much. I could understand in 10 minutes what I couldn't for months in other physics classes. Teaching is a skill on its own.
You're very welcome!
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Keep it going! Glad you found our videos.
I swear to my teacher’s explanation was so complicated and I didn’t understand anything until I saw this vid and I have a test tomorrow thank u so much
I was the whiz when we did this at school (in the 60s) but I moved in to chemistry and not gone near since. Too many years later and m son needs help with his homework. French school as well so it's in French God help me.
You might just have saved my life with this. Very well explained. Thank you.
So you had your kid when you were around 50?
@@thefridge5844 I'm 66 now, he is 18.
This guy is always saving my physics grades, because my teacher fails to explain anything. 👍
Glad you find our videos helpful.
Wanted to say I came here to say looking for help to solve a challenge problem for my physics class only until I realized half way through that it was a trick answer. Still stayed for the excellent lesson, you’ve definitely helped me on my path Mr. van Biezen. Many thanks.
Thank you. Glad you found our videos. We have thousands of videos on physisc and engineering.
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More people have mentioned that. That you.
Thank you so much , i find all your videos very helpful since I’m taking AP physics and the teacher in school tries to explain things fast since we have a lot of material to cover and I often find myself lost in her lesson and it’s hard for me to keep up with her , one day i found your videos and ever since that day i depend on them whenever i need help . :) thank you very much 💕✨
Michel Biezen, i enjoyed watching and learning from your tutorials. Your Engineering tutorials are very good, and i like them. You did an excellent jobs of explaining concepts in a very entertaining , clear and understandable way . Many thanks for your tutorials.
I missed this on my physics 1 exam. Looking back on it I have no idea how I didn't understand it. Its so easy now
Some days ago i was ill and I couldn't come to school. I tried to study but didn't understand until I watched this video. Thank you so much for explaining. You saved my life
thank you ever so much for this video. even 7 years later, people like me still find this useful! May Allah bless your soul.
Thank you. Glad you found our videos! 🙂
thank you so much. From South Africa. This sure will help for tomorrow's physics exam
fellow south african! i also have an exam tomorrow!!! ugh!
I haven't been able to understand this problems earlier but now everything is clear. It is only because of u. U r amazing. I also liked your bow
Sir, you might hear this a lot of times or probably none but you're awesome sir. You have saved my life lol I hope you're doing well! And thanks a lot for this video!
We remember that when we were students we were at times very desperate to find anything that could help us understand the material. That is a big part of the reason why we are making these videos to help students today that are in the same position. Comments like yours tell us it is working. We are very glad they are of help to students. Thank you for your comment.
I hope i found this earlier this is a great help you are amazing.....
If my prof is good as you i wont struggle understanding our lessons
Simply..u can use lami's theorem...
4900/sin(130)= T1/sin(110)=T2/sin(120)...
Solve this equation u can get T1& T2 value
it did not work. how?
Yes here you can use Lami's theorem, but you can't use it when you have an unknown force and angle that's why it is better to know how to resolve forces.
great vid! im currently in my final year of highschool, and due to the coronavirus im very bored so im practising for physics in college. watching this makes me feel dumb and clever at the same time😂
I had such a big problem understanding this typical physics exam question. thanks to you i can now solve most of these questions in less than 4 mins. Hip hip hurra for you Professor.your explanations is so easy to follow.
Never studied mechanical engineering. But after watching your lessons, I feel that I missed a lot! So interesting! Tank you.
You are The Boss , I am glad to watch your video ,you are amazing and i understood everything, even though My English is not good enough , thank you very much , made my day .
YESS!! Thank you verymuch!! I couldn't understand this from my sir but u easily explainedit !!!!! THANKS ALOT!
best teacher i had i swear to jerry's future kids
You sir are a genius. May god bless you!
Been watching your vids for a while, but just subscribed. I like the straightforward style you have. My only input would be based on how I like to do problems like this and that is to wait and obtain the final forms of the variables and equations and then do all the trig functions and other numbers and arithmetic. Great video however, I enjoy watching and seeing another style and explanation. :)
That is indeed the typical way in which one should solve physics problems (solve the equations first before substituting numbers), but there are a number of types of problems, where plugging in numbers earlier is advisable.
@@MichelvanBiezen :)
@@MichelvanBiezen I like the videos you've done where you take the moment of inertia of a pulley into account. I'd like to see one where you take the mass of the rope into account too.
You are truly brilliant...
The lesson is pretty amazing I appreciate, For further knowledge, I'd like to know what's contributes to the large tensions in T1 and T2, whereas in normal situations, we would expect that summation of tensions in T1 and T2 will be equal to the tension in T3.
When the angles appoach zero degrees, the tensions will approach infinity. 🙂
Merci beaucoup !!! Vous m'avez vraiment aidé même si ce n'est pas ma langue ! C'est tout dire :) vous êtes très bon pour expliquer monsieur !
Merci bien
Thank you for this great example! I only encountered tension problems that only has t1 and t2 and are attached to the object, but this one has t1 and t2 and its connected to another string which is t3 that is attached to the object. 😊 Also subscribed and will be exploring your other physics videos. ❤️
Glad to have you as a new subscriber! We have over 9000 videos. Enjoy!
Excellent tutorial. You make it so simple Sir.
I love u thanks :) you are a great teacher
At 3:54, he meant to say T1x in the x-direction, not y. Just a happy little accident. :]
"Happy little acident..." Do you watch Bob Ross from "Joy of painting"? LOL. I (Mike van Biezen's wife) used to watch him on TV 25 years ago. Long before Bob Ross TH-cam days.
@@MichelvanBiezen Heh. I wish. Bob Ross was before my time.
A very helpful video, i was just reviewing my class lecture and this video explained a lot. Thank you so much.
Thank you for your video! They are very useful first, and second you explain very well!
Thank you. Glad you find these helpful.
Oh thank you so much now I solved all my problems really thank you, keep going
Happy to help
woww we need faculty like you
Thank you.
This came in very useful!
Glad it was helpful!
Professer Biezen, Thank you so much for doing these static videos I am a Mechatronic Engineering student and I have been enjoying many of your videos to help me along. I just so happen to be taking statics this summer and this playlist is what i have needed. I am also taking Ordinary Differential equations I hope you get a chance to do this as well. Again thanks for the content.
Johnny Canazon
Johnny,
You are welcome. I started differential equations as well as statics. Now I just need time (still working more than full time besides doing these videos) Good luck with your studies this summer.
thanks Prof! love the way u easify the question.. and we know giving knowledge I's just doubling your knowledge
sonic boom are you American ?
You just summarized my entire semester in 10 minutes. Thank you, Sir🥲.
Glad you found our videos,
God bless you and all your relative
This is an old video but since the results showed there are inbalance between the force, does that mean its not in equilibrium? Since it supposed to be at 0 however in the end we got like 6,012N T1 and 5,540N on T2? Plus the 4900N below
There is no net force on the object. (Otherwise there would be an acceleration --> F = ma) Therefore all the forces in the x-direction add up to zero and all the forces in the y-direction add up to zero.
I'm just wondering about ty1 sin 30. Are we assuming that a right angle gets formed by the angle between t1 and tx2 above it so that we can imagine a 30/60/90 triangle with ty1 opposite?
May God bless you, Sir. Your tutorial was really helpful.
what a god. I am passing my exam bc of this
No god around here. But glad you found our videos and you found them helpful. 🙂
I hope I know this channel when I'm still an undergraduate student. 😌😌😌.
Your the goat michael
Glad you found our videos 🙂
thank you!!!! you saved my life
Glad it helped!
Thank you Sir
I tried to solve a problem in my high school text which was like this i tried to use Lami theoram for equilibrium but i failed to find the angles it helped alot Sir
May God bless you
Great! Thank you. 🙂
Why do T3 and FG not cancel out? When you say that T3 is acting downwards when you are solving for T1 and T3, why is that? Why would that not nullify the tension upwards?
Pick the point where all 3 strings meet as the reference point. Since that point is stationary, all the forces acting on it in the x-direction and in the y-direction must add up to zero. (that is how the problem is solved as shown int the video). Your question can best be answered by drawing a free body diagram around the mass, which would then indicated that the net force on that block is indeed zero (T3 = mg) But that is not relevant to solving the problem.
Why is there a tension force equal to the the gravity force. Wouldn't that net in twice the force downward?
thank you so much your videos are really appreciated
Thank you Professor, I would like to ask about a part of a question I saw in an IG textbook, the question starts as "A smooth bead is threaded on a light inextensible string, the ends of the string are attached to the ceilling, the bead is acted on by a horizontal force F and the bead is in equilibrium..... ", the point is that the answer assumes that the tension on both sides of the string are equal, why is this true?
Thanks
If the tension on the string was not the same on both ends, then there would be a net force acting on the string and the string would accelerate in the direction of the net force.
thankyouuu!!! im now understand how to solve this type question!! Really worth to watch
Glad it helped
Best tutorial ever thanks 🙏
Great video, thanks man.
Best explanation sir
Thanks and welcome
Sir can you explain equation relating to rope drum and load. Our project had faced issue since we supplied crane where it function on top of hill due to gravity parameters we couldn't find the exact load we carry out by crane. It runs on 25hp motor, which could lift 10ton , but at 5 ton itself the gears rotated opposite direction since the load seems heavier due gravity pull near Nepal hydro power generation project. It suppose to drill and lift deep to 78mts into mountain but at 9mts itself issue faced
THIS EXACT QUESTION CAME OUT IN MY EXAM AND I AM ONLY FINDING OUT HOW TO DO THIS TODAY????? Y'ALL ARE TRIPPIN
Now you know where to find physics help.
A 100 lb weight is suspended from 2 cables. The tensions T1 and T2 satisfy the following
equations:
0.6T1+0.8T2=100 (1)
0.8T1−0.6T2=0 (2)
Solve for T1 and T2.
You can work this problem in 2 ways. Simply solve it algebraically (2 equations and 2 unknowns). Multiply the bottom equation by (-6/8) and then add the result to the top equation to eliminate T1 so you can solve for T2.
Interesting thing is that we have only one force pulling down, i.e. a cause of all tensions and this force is 4900N while all tensions caused by that force are bigger - both above 5000N
That is correct. If those angles approach zero degrees, the tension will approach infinity. That is why with hanging cables they don't try to stretch them too much or they will break.
8:22 - 10:00 I get confused Someone please explain! How does he get 6011 if he is just dividing .815/4900
6011 = 4900 / 0.815
It is 4900/0.8152
How did u get .8152 sir?
THANK U SO MUCH MAY GOD BLESS U
Thank you. God bless you as well. 🙂
How do we calculate the tension and wire diameter required to fix a vertical wobble of a bunk bed? Assuming load is 400kg and cross bracing.
wires (or cables) made of metal will be rated with a maximum tensile strength expressed in force / cross secional area. Which means that your cable diameter must be sufficiently large to hold the load with margin. (The margin is usually a minimum of 300% meaning the you want a cable large enough to hold 3 times the inteded weight.)
@@MichelvanBiezen Thank you vry much!
Thank you very much! Helped me out a lot.
Thank you very much professor. Really amazing lesson.
Excellent better than the people lecuring and tutoring me
hello sir
can you explain me why when we add the results of T1 and T2 back to 0.9397T2 - 0.8660T1=0
and we can not get zero??????
Since T1, T2, and T3 are vectors, they must be added like vectors (add all the x components together and all the y components together) If you do this correctly they will add up to zero.
@@MichelvanBiezen thank you very much teacher
Really helpful advice
Glad it was helpful!
good work it was hard but you made it very simple
Glad it helped
Good🎉❤ Physics Dr..
Glad you found our videos. 🙂
Thank you so much! After I saw some of your videos I got an A in Physic on the exam.
Excellent. Good job!
Thanks so much sir, this stuff actually jumped in😁
Glad it helped!
Dear respected sir, we can solve this problem conveniently by using Lami,s law as well
Yes, you can. Lami's Law is very interesting. We should create a video on it.
you are a good man, i love you
Thanks!
Thank you so much for this explanation
Welcome 😊
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Thank you so much for the person in this video.Im getting to know something new about Force hanging case.Hope for more such a great video in the future.
Thanks it's so amazing i like it
Thank you. 🙂
Nice video, clears my confusion.
Thanks that was so helpful
Other method
If all the forces are coplanar and concurrent and all angles are less than 180°, then Lami's theorem is applicable and its very simple.
it is so helpful thanks
You're welcome! Glad you found our videos. 🙂
Please help me
Calculate this problem
A car traveling 20m/s passes a street corner. the car maintains its speed even though the speed limit is 10m/s. The police car sitting at the corner begins to chase the car by accelerating at 2m/s/s.
How long will it take for the police car to chase the speeder?
How far from the corner is the catch-up point?
How fast would the police care be traveled at that time?
Assuming that the police begins the chase as soon as the car passes the police car. When the police car catches the speeding car, they will have traveled the same distance. ( d = v t) (20) t = (1/2) (2) (t^2) solve for t. Once you find t, d = (20) (t) then you find the velocity v = a t = (2) (t)
@@MichelvanBiezen thanks
Thank you so much for this video!! It helped a lot.
THANK YOU SO SO SO SO SO MUUUCH!!!!
YOU'RE WELCOME SO SO SO SO SO MUUUCH!!!!
Thank you !! Saved me a ton
You're welcome!
Can't thank you Enough!!!
Glad you found it helpful ! 🙂
Excellent professor
So nice of you
how you get 6011N? what do you mean by ''Plus point 5' and inverse?????
4900 N / 0.8152 = 6011 N
woah, very helpful i must say. Definitely subscribing
Thanks. You’re a life saver
Why not use Lami's theorum
Thanks for your videos!!!! 🎉🎉🎉👍
Very comprehensive instructions
Dear sir I have been watching your videos and they have been very helpful.
I just have one question. What if the rope is not weightless(Like reality)? How can we incorporate the weight of rope into this equation if we know the weight/m?
Then you need to look at this playlist: MECHANICAL ENGINEERING 10: FORCES ON CABLES
I have been watching all of your physics problems, very well done videos at a good pase. Much appreciated, thanks for your hard work and dedication.
Many thanks for your nice comment. We appreciate it.
Proof that I need more brain cells
thanks for this amazing lecture!