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How many marks (if any) would I have gotten cos what I did was find the area for the whole of the shaded circle and got 16 pi and then I split one of those sectors/segments (a-b) as though it were a semi circle and got a total area of that section 4 pi and then doubled it as there is 2 of them and got 8 pi and then I did 16 pi - 8 pi to get 8 pi (which is obviously wrong) as my final answer
Yes i had it on my gcse couldn't solve it in the exam but did it in about 5 min after the exam had to explain it to my head of maths was a good question The way I answeeot was different I saw it as 4 identical segments in between the intersections of the circles if that doesn't make sense the circle be where its not shaded you can cut in half and get a segment there are four of them I then worked out the area of the sector using the equalatral triangles and then took the area of the triangle in the sector to leave the segment I then multiplied this by four as there are four segments and took this off 16 pi I can't remember my answer tho as I put the paper in the bin after and haven't looked back since
My uncle has a degree in maths and physics. I showed this question to him and it took him a good 20 minutes to solve it, he said that's one of the most challenging gcse questions he's seen in a long time.
the kids that pass this in their gcse will defo have some basic geometry knowledge and/or even take notice in their geometry studies so well done to them :)
That question left me dazed for 5 minutes. I literally ran out of time so I just found the area of 1 circle as 16π and left it 😥 But thank you so much for making me understand it now! It's always after the exam when I realise what the right answer was and kick myself for not thinking of it. (that's me lol) 😅
This exam paper for soooo messed up! Especially the last few questions ofccc! Let's hope they'll actually more more generous with paper 2 and 3 after striking us with such monstrosity... Good luck everyone for the upcoming exams :)
they won't be so generous in p2 and 3 as if p1 is anything to go by, the next one's will be exactly the same, hit us with unreasonable questions at the very end
Got right to the end of this paper, stared at this question, figured out how to do it, and sadly enough, ran out of time part way through. Shame, watching this video now it seems i would've got it right. RIP those 5 marks.
@@bria4776 to be honest i probably took too much time trying to figure out how to do it, which left me with no time to actually do the maths and answer
I got the same answer with a different method. I split the the two intersecting shapes into two identical segments, then found the area of one of those segments and multiplied by 4. This was a very fun and challenging question, and one of the hardest GCSE questions I've seen.
This question was great; I managed to do it in about 10 minutes because of a method I have for geometry questions. Advice people: If you ever can see a method for a geometry question within 2-3 minutes, just draw lines. Where ever you want. Just draw them. It will really help, trust me. - Anonymous Internet Person. Thanks GCSE Maths Tutor for finding this question on the latest GCSE paper :D
i got the answer to be 64-16π... if you draw a square over the middle circle...!Which will be tangent to three of the circles..and join tge diameter of two of the circles vertically! and a line drawn from tge centre of the circle to the tangent is perpendicular...so the figure was a square..and since diameter was 4+4 cm = 8cm....so the square was of area 64cm^2.. and then inside that we got two identical semi circles...i have subtracted the area of semi circle from the square and then got the shaded regionn...There are many ways to solve a question!
I found it much easier to simply work out the small lens-shaped bits by subtracting the hexagon from the circle dividing by six and then subtracting four of these lenses from one-third of the area of the circle. Just use Pythagoras for the triangles. Doesn't need any trigonometry at all. Hope this helps, shows that it is good to look for shapes in these questions.
Then why tf is Edexcel slapping us questions beyond Seconday school education. The GCSE -> General Certificate of Secondary school is only meant to measure secondary education. :(
@@H8ssan Because it is possible to do at GCSE level as you learn about areas of sectors in circles. It just becomes easier in A level when you learn what a radian is
This was indeed a challenging question and i did it by subtracting 4 equal segments from one circle and convinced it is a lot quicker, although i do like your approach. It’s always nice and refreshing to see a different approach. Thank you.
@@TheGCSEMathsTutor Some people are saying this question got first leaked in this channel gcse maths tutor I saw somewhere there was a comment like “first the last question got leaked in Gcse maths tutor” just wanted to tell you because I don’t think it is true that you can do something like this you helped me a lot so I thought I should tell you
Looks like the whole country did badly here (and also with some of the other ones at the end of the paper), so maybe the exam board will make an exception?
@@Georgeg15 not in a year when after 2 yrs of lockdown and chaos we have exams. And not in a yr when they said it'll be easier but then hit us with a question I haven't even since in past papers PRE PANDEMIC
The paper genuinely wasn’t too hard, it’s just I made the silly mistake of crossing out the right answer for the tangent of a circle question and adding the values of y and x and the algebraic fraction question caught me off guard too
I got a 9 in GCSE Maths and an A* in A Level Maths and Further Maths. Almost shamefully, this question took me 20 minutes to work out. If you couldn’t work this out in the exam, please don’t beat yourself up about it!
Area of an equilateral triangle can easily be calculated by dividing into two right angled triangles and using pythagoras - no need to remember any trigonometry.
Hi, thanks for this great video explaining how you solved it. I attempted it (but failed miserably) before watching your video about a month ago. I tried to solve it again today after 2 cups of strong coffee and managed to get the correct answer....after 30 minutes, which is way too long to spend on just one question. The solution, broadly speaking is "Area of two segments minus area of four sectors." The sectors in question are the fractional area (60/360th) of full circle minus the area of the equilateral triangle formed by AB (or BC) and the circle intersects.
waffle waffle, till the very next day bop bop bop bopity bop, he went to the exam and saw the question and thought "wait is that an elipse?" no its a circle, can you go away, ok, but he waffle waffled till the very next day bop bop bop bopity bop he gave up the question and saw another question and said "got anymore" yes yes yes you dummy dumb dumb this is an exam, your gcse don't think its going to be easy basically what I'm tryna say "e e why are you waffaklin for in de examdey ask you a question and you go say , ehe is this an elipse?" well boohoo u got it wrong nigga
I got this right in the exam The way I did it was at 2:09 the area of that half oval section is two overlapping circle sectors with an equilateral Trinangle ( and each circle sector had 60 degree angles cuz of the equilateral) So find the area then multiply by 4 and subtract that from 16(pi)
I am in second year at uni and it still took me about 10-15 mins or so answering this question. Got the answer right in the end, but definitely a question that targets the grade 8 and 9 students.
I used pythagorus on the equilateral triangle to get the area. Then took that away from a sixth of the circle area to get the segment bit, then to that away from the triangle. A bit quicker than the above.
@@estherereyemi9309 If you split the equilateral triangle in half, you have 2 right-angled triangles. You know the hypotenuse (in this case 4cm), and you know the short leg (2cm), so you can use Pythagoras to calculate the long leg, and thus you have the height of the equilateral triangle. You already know the base, so just use the standard formula to calculate the area. It's basically the way that the formula for the area of an equilateral triangle [ = (√3/4)a² ] is derived.
It's more of an old-fashioned problem from something like Durell's book "New Geometry for Schools" (published in 1956) that was used extensively in secondary schools into the early 1980s for the O-level. More recently, they turn up as Math Olympiad questions from time to time. It used only GCSE techniques (construction of equilateral triangle, area of sector and segment, sin 60° = √3 / 2) but presented in an unfamiliar form as a challenge for grade 9 students.
I didn’t do this test but I got it slightly differently. If you split the shape into the equilateral triangles, instead of working out the sector, I just worked out that 3*(area of one triangle) + 3*(outer semi-circle looking shapes) = 8pi, and then I worked out the area of one small semi-circle thing by dividing this by 3, and then the area of the shaded region is 2(area of equilateral triangle - area of one semi-circle thing). Rip to ppl who got this question but extra rip to further maths students
I'm actually a predicted 6 student but had the exact same methodology in my head, if only I trusted my gut I could've surprised my whole year 10 group XD
I wanted to cry in that usually get grade 9 and managed to zoom through paper and then spent half an hour slamming my head against the table in this question 😭😭
I find it beneficial for questions like this to break it down into a 'shape equation'. Half of shaded area (split vertically) = semicircle - lens. Half of lens = sector + (sector - equilateral triangle) = 2 x sector - equilateral triangle. Areas of sectors (60°, r = 4), equilateral triangles (side = 4) and semicircles (r = 4) are all pretty straightforward to calculate.
grade boundaries are different each year and it doesn't matter from previous years. they are created after all the papers are marked each year to tailor it to the year 11 that did the exams that year. Hope this helps
I'm an A Level student who solved this problem in like 5 minutes, but even then, this is by no means an easy problem. I bet you that 80% of my further math class dont know how to solve it. I really have 0 idea how edexcel could have put a question like this.
I was just flipping through the paper almost having fun at some points and then… then I was faced with the ultimate boss… I couldn’t believe my eyes… the dreaded last questions of the paper 💀🪦 rip, my final brain cell
My first impulse was to use polar integration. Then I realised this question is for 16 year olds. The key to this question is knowing that the circles intersect like hexagons, without that your stumped. I think it’s unfair to expect any gcse students to know this and apply it in an exam in such an obscure way
@@karhukivi the method and working out was light work, but ACTUALLY noticing the triangle at the very beginning under EXAM PRESSURE is nearly impossible
@@kardoxcenna260 I know what you mean, but you have to try to break down the problem by drawing lines, noticing that the three circles have the same radius length etc. Perhaps teachers are not teaching methods of problem-solving and just concentrating on memorising things.
@@karhukivi I got it right, at first I had no idea what to do but I started annotating the drawing and broke one of the semi-oval shapes into circle sectors and an equilateral triangle
This solution is WAY over-complex, simply it is the area of a parellelogram minus area of sector (1//6 of a circle) this gives 1/2 . r . sqr(12) - pi.r^2 / 6 then double it !
ooops! ... that should be ..... r.sqr(12) - pi . r^2 / 6 then double it (where r=4 and Sqr(12) is height of //ogram using pythagorus on the equilateral triangle))
Using a parallelogram you would have to subtract the area of a sector and a segment before doubling it, which is the same method I used except you also have to incorporate Pythagoras to find the area of a parallelogram rather than the area of a triangle. A really nice method but I wouldn’t say it’s easier, nor would I say it’s more or less complex! But definitely another interesting way of looking at it that I had considered! All in all I used 5 different methods - this one included! And the method presented here was the preferred method by my students 😁 Of course we are all different and I would always encourage using the method that you prefer! Thanks for sharing this one!
@@TheGCSEMathsTutor Tut tut tut ... look again , not so ... the equivalent of the exterior segement is incorporated in the //ogram so it is simply area of //ogram minus area of sector ... then double it ... elegant !
I spent over 10 minutes on the ratios one and still couldn't solve it!!! The vector one was easier tho, you had to show they are multiples of ach other :)
@@shanz0663 Tysm... and ur right~ stressing over this would just affect my upcoming exams' guess I really needed to hear dis :) Good luck for ur exams toooo ❤
The exam board are so mean for putting this as a question on the exam I haven’t had that question on an exam before so there’s a high chance of it appearing
didnt get this in the exam, but i had a go at it afterwards to see if i could do it without the time limit and it made me really happy to see that i got the answer right shame i couldnt do it in the exam though :(
Damn this took me a whole lot more steps than it took him. I didn't clock that the 3 segments mentioned are all equal. I did a different method I correctly reacehd the same solution. Goes to say that there are many routes to the right answer.
So my way of getting the 5 marks was actually way easier, I first worked out the area of the 3 circles added them together then skipped the rest of the question to get back the 5 marks through not wasting my time on this dumb question and doing an easier question instead
Could you make 2 triangles with base AB and BC Then work out those tiny segments Add them together Then work out the area of a semi circle Then subtract the area of the semi circle from that?
After the exam, I worked out a general formula for any 3 circles laid out in the way that it was laid out in the question, with a radius of r. The formula was: (r^2)sqrt(3)-(r^2)/3 pi Don't ask why- the question was plaguing my mind
@Ciara Williams nice bit of basic primary school maths there lol good for you 🤣 here basically your formula is this 1x8x2/3-1x8x2/3(pi) lmao nice bit of nursery style maths for ya whoohoo go you 👍
I ended up wasting my time trying to do this, which made me lose dumb marks on other areas. If I had just ignored this I would of got like 70 but now it's like 60-65 :/
My maths teacher showed me how to do this, I usually have like 40 mins by the time I finish the paper but I doubt I would've worked it out myself in that time.
Thanks to your videos and the way u explain these type of difficult question I think I was able to to grab at least one or two marks for this questions as I too also drew a triangle attempting to find out the segment,but ran out of time as most the time I was just stuck! Also wanted to tanks u for ur videos which made most of this paper a breeze.
Just had this question in my paper 1 for my GCSE, took me 20 minutes of checking to make sure there were no mistakes. Shame to learn that this question was leaked so who knows whether ill get the marks for it but it was fun walking out of the exam hall learning I was the only person who even answered it. Sadly that 20 mins spent meant that i couldn't check my paper for stupid mistakes and i learned that i have made like simple addition mistakes in the 3 other final questions soooooooooooooooo rip me. Edit: info about bad additions
Well done for completing it. Several of our students did too, but we enter a cadre into the Math Olympiad to give them a wider experience of questions than those in the text book. Don't worry about the marks, that's up to the exam board to sort out. Given the surprise over the question, my thinking is that the leak was not widespread and the board will look for clusters of anomalous correct answers above an ability indicated in the rest of the papers; if that's the case, most students will gain marks for answering it.
It was a really hard exam that a lot of people struggled with so the grade boundaries would probably be low, try not to stress over it too much or it may effect ur upcoming exams~ Just hope for the best and try hard. GOOD LUCK :)
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What's this
@@intoworld71 the last question of the higher maths edexcel paper we had this morning, it was 💀
How many marks (if any) would I have gotten cos what I did was find the area for the whole of the shaded circle and got 16 pi and then I split one of those sectors/segments (a-b) as though it were a semi circle and got a total area of that section 4 pi and then doubled it as there is 2 of them and got 8 pi and then I did 16 pi - 8 pi to get 8 pi (which is obviously wrong) as my final answer
Thankyou for assuring me that i got the wrong answer.
Yes i had it on my gcse couldn't solve it in the exam but did it in about 5 min after the exam had to explain it to my head of maths was a good question
The way I answeeot was different I saw it as 4 identical segments in between the intersections of the circles if that doesn't make sense the circle be where its not shaded you can cut in half and get a segment there are four of them I then worked out the area of the sector using the equalatral triangles and then took the area of the triangle in the sector to leave the segment I then multiplied this by four as there are four segments and took this off 16 pi
I can't remember my answer tho as I put the paper in the bin after and haven't looked back since
My uncle has a degree in maths and physics. I showed this question to him and it took him a good 20 minutes to solve it, he said that's one of the most challenging gcse questions he's seen in a long time.
And they were meant to be more generous dis year 🙄
@@Osamu_Dazaiii ur forgetting that this Q was hard for mostly everyone, so it kinda cancels out in the grade boundaries
Good to know I’m not the only person who thinks this is stupidly hard
bruh it's an EZ question LOL XD you don't need a PHD just some basic geometry/math knowledge :)
the kids that pass this in their gcse will defo have some basic geometry knowledge and/or even take notice in their geometry studies so well done to them :)
im wholey convinced this question is impossible and it was only there to lower the grade boundries by making people lose marks
TOTALLLY! They just like to see u suffer 😞
Sometimes in exams they put high level questions to identify prodigies and the small% but it could also be for that reason lol
Exactly
literally
@@Osamu_Dazaiii how many marks were for this question?
I worked out 16 Pie and called it a day
Bruh same
I got 16pie -32 ffs
I got 12 pie
I got 8 🥧
Basically everyone, hope we get 1 mark for working
It takes him ( a maths teacher) 12 minutes to do this and they think I can do it in less than 5?!?!???
Ikrrr! At this point... I think they just like to see us suffer and fail 😤
He could do this in around 2 minutes if he wasn’t explaining slowly
@@martinhempston872 true
@@martinhempston872 the method was easy tbh, the hard part was noticing those two triangles..
@@kardoxcenna260that was near impossible
That question left me dazed for 5 minutes. I literally ran out of time so I just found the area of 1 circle as 16π and left it 😥
But thank you so much for making me understand it now!
It's always after the exam when I realise what the right answer was and kick myself for not thinking of it. (that's me lol) 😅
That's exactly what I did too 😂
I had 35 minutes at the end and still had no idea how to do it
That is exactly what I did😂😂
Would 16 pie get a mark
@@saifali1167Yes.
maybe 2 depending on steps question takes
Please make some videos on ridiculously hard unreasonable questions for papers 2 and 3 so we can actually prepare ourselves 😭
fr😮💨
Was really shocked when I saw this, an interesting mix of different topics. Shame I couldn't answer it
Ur not alone ✊🏻😔
same :(( i was feeling so confident for that paper aswell
lol my brain died when i saw it
@@darn. Sameee! I just sat there, staring at it for a while~
it's an atrocious mix, not interesting
oh no that question traumatised me in my paper
Same
i looked at that question and just laughed and continued with life
What a question to give in the year where they said they would be "more generous"
Ikrrr!!!!
They might have done this so the grade boundaries will probably be lower so then they'll be like we lowered the grade boundaries to make it easier
@@khalidmustafa1341 literally, scheming
This exam paper for soooo messed up! Especially the last few questions ofccc! Let's hope they'll actually more more generous with paper 2 and 3 after striking us with such monstrosity... Good luck everyone for the upcoming exams :)
gl
they won't be so generous in p2 and 3 as if p1 is anything to go by, the next one's will be exactly the same, hit us with unreasonable questions at the very end
@@YaSeenAli-bs4wq u mong nothing on earth is the same
Ww1 and ww2 were different weren’t they
@@watchmojofan253 ww1 and ww2 were still both devastating wars which killed millions War is War
@@watchmojofan253 millions died in both, and both wars germany was considered the main threat. Really shitty analogy mong
Got right to the end of this paper, stared at this question, figured out how to do it, and sadly enough, ran out of time part way through. Shame, watching this video now it seems i would've got it right. RIP those 5 marks.
Same. This is exactly what happened to me too.
how did ur mind even gather what to do
@@bria4776 to be honest i probably took too much time trying to figure out how to do it, which left me with no time to actually do the maths and answer
It was a hard paper you guys should just be proud that they thought you were smart enough to do higher
Omds. I legit started answering the question the same way. Knew hwo to do it. Start on the next part of my answer. Then the exam finishes. Like stfu.
I got the same answer with a different method. I split the the two intersecting shapes into two identical segments, then found the area of one of those segments and multiplied by 4. This was a very fun and challenging question, and one of the hardest GCSE questions I've seen.
No marks for u
Why not? It’s a valid approach to the question
@@ryankelly4830 it says on the mark scheme BJ made that it has to be this method
It stated u can’t be related to a gay nonce to get full marks
What are you talking about? I used a valid method. That’s not how mark schemes work. The mark scheme has not even been released yet.
wishing everybody who found this question easy a very bad evening
Excuse me sir, I feel personally attacked
@@mr.e7005 good, have a bad evening
i had fun doing it in exam
@@mr.e7005 why? u definitely got it wrong
I actually support allah
I found the area of 1 circle, 16 pi, then I thought “that’s looks like about a quarter of one circle all together” so I just put 4 pi
George Kelly rollercoasters
use me as a ''i got to 16pi and couldnt possibly get further" button 🙃
Just keep rewatching
This question was great; I managed to do it in about 10 minutes because of a method I have for geometry questions. Advice people: If you ever can see a method for a geometry question within 2-3 minutes, just draw lines. Where ever you want. Just draw them. It will really help, trust me. - Anonymous Internet Person. Thanks GCSE Maths Tutor for finding this question on the latest GCSE paper :D
yhh thats what I did too but in the end, I got 8 pie which is obviously wrong.
wdym 'just draw lines' 💀
i got the answer to be 64-16π... if you draw a square over the middle circle...!Which will be tangent to three of the circles..and join tge diameter of two of the circles vertically! and a line drawn from tge centre of the circle to the tangent is perpendicular...so the figure was a square..and since diameter was 4+4 cm = 8cm....so the square was of area 64cm^2.. and then inside that we got two identical semi circles...i have subtracted the area of semi circle from the square and then got the shaded regionn...There are many ways to solve a question!
Only one person in my whole school got it, the only reason she got it was because there was a similar question on the UKMT pink kangaroo (2nd round)
no wayyy luckyyyy
LUCKYYYYYYYY!
no-one in my school got it rip
I also got it as well. I got (48sqrt(3)/3) - (16pi/3)
@@krish4134 wow u smART SMART 🤩🤩 hope u get a well-deserved 9
I found it much easier to simply work out the small lens-shaped bits by subtracting the hexagon from the circle dividing by six and then subtracting four of these lenses from one-third of the area of the circle. Just use Pythagoras for the triangles. Doesn't need any trigonometry at all. Hope this helps, shows that it is good to look for shapes in these questions.
OMG THAT IS GENIUS ARE U A MATH TEACHER
POV: You memorise the exact trig values and don't even get to use them.
Couldn't be me.
Hi sir, can you please make very difficult questions similar to this level for the next 2 edexcel maths papers :D would be much appreciated!
Daddy
This question is so much easier when you know what a radian is. But that is from a year 1 A-level perspective
or additional mathematics student
Then why tf is Edexcel slapping us questions beyond Seconday school education. The GCSE -> General Certificate of Secondary school is only meant to measure secondary education. :(
@@H8ssan Because it is possible to do at GCSE level as you learn about areas of sectors in circles. It just becomes easier in A level when you learn what a radian is
This was indeed a challenging question and i did it by subtracting 4 equal segments from one circle and convinced it is a lot quicker, although i do like your approach. It’s always nice and refreshing to see a different approach. Thank you.
I did the same
How would you subtract 4 equal segments?
That’s a brilliant idea! Did you get the right answer?
Bruh fr this question is why they said good luck on the advice part 😂
I know haha. I was so shocked and almost happy when I saw that and then seen this question and was like ahh that’s why.
can you please make some predicted paper videos with interweaving topics for paper 2 and 3
Yes that would help alot if they use the same format for the 2 papers
init
That’s stupid how does he know what the questions r
@@watchmojofan253 bro he said predicted paper videos not exact paper videos 🤦♂️
AGUEROOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOO!
I did the aqa exam last week and my respect for Edexcel students just went up. I’m normally in the border of 8-9 and this made me think hard
So I am guessing aqa is easier ? Damn I wish I was edexel
@@human-kg8nu Easier and harder doesn’t exist. Grade boundary does. Aqa may be easy but grade 9 is 90% whereas Ed excel is 85
@@nelzhang161 okay cool I don't gcses anymore so it doesn't matter to me
Could you do something slightly lengthy ( but not too much ) on the next maths gcse paper, without it being the day prior as I have an exam then
Videos to come very soon! I've already posted the "everything on paper 2" video in my playlists!
@@TheGCSEMathsTutor Could you do more Questions that are like 5 markers. :)
Hi are these videos also for igcse H2
@@TheGCSEMathsTutor
Hi are these videos also for igcse H2
@@TheGCSEMathsTutor Some people are saying this question got first leaked in this channel gcse maths tutor I saw somewhere there was a comment like “first the last question got leaked in Gcse maths tutor” just wanted to tell you because I don’t think it is true that you can do something like this you helped me a lot so I thought I should tell you
Looks like the whole country did badly here (and also with some of the other ones at the end of the paper), so maybe the exam board will make an exception?
LEts hope so~
wdym make an exception ? btw stuff like this is put in every year to identify prodigies nobody ever gets these marks
hope so
@@Georgeg15 not in a year when after 2 yrs of lockdown and chaos we have exams. And not in a yr when they said it'll be easier but then hit us with a question I haven't even since in past papers PRE PANDEMIC
@@Georgeg15 I did all the past papers and by far this shit was the hardest question ever, they expect too much from a 16 year old
The paper genuinely wasn’t too hard, it’s just I made the silly mistake of crossing out the right answer for the tangent of a circle question and adding the values of y and x and the algebraic fraction question caught me off guard too
silly billy
Algebraic question was pretty simple 16 if I remember
@@vglspud lmfao u made me laugh out loud
@@haych8726 YESS
@@haych8726 that’s the indices question
You explain even the trickiest topics so well.
I got a 9 in GCSE Maths and an A* in A Level Maths and Further Maths. Almost shamefully, this question took me 20 minutes to work out. If you couldn’t work this out in the exam, please don’t beat yourself up about it!
what a liar
waffle waffle, till the very next day bop bop bop bopity bop,
who’s here after the paper was found leaked?
How was your paper today maths
Where did you find it ?
is that true??
Bruh how
Not true
I sat the IGCSE and saw this on reddit after, took less than 2 mins to figure out.
Area of an equilateral triangle can easily be calculated by dividing into two right angled triangles and using pythagoras - no need to remember any trigonometry.
Absolutely hated this question and so pissed they made the origin for the circle not be (0,0) for that tangent one
Honestlyy, “generous year”
@@riaasx FR LIKE RE AND BIO WERE SO NICE
@@riaasx Ye~ 💥GENEROUS💥
@@BIFFALA FRR, even kino and the scorpion were better 😭
@@riaasx lmao fr
Hi, thanks for this great video explaining how you solved it. I attempted it (but failed miserably) before watching your video about a month ago. I tried to solve it again today after 2 cups of strong coffee and managed to get the correct answer....after 30 minutes, which is way too long to spend on just one question. The solution, broadly speaking is "Area of two segments minus area of four sectors." The sectors in question are the fractional area (60/360th) of full circle minus the area of the equilateral triangle formed by AB (or BC) and the circle intersects.
The first time i tried this problem, i thought using the area of an elipse might do the trick, but then i realised that it's not really an elipse
waffle waffle, till the very next day bop bop bop bopity bop,
he went to the exam and saw the question and thought "wait is that an elipse?"
no its a circle, can you go away,
ok, but he waffle waffled till the very next day bop bop bop bopity bop
he gave up the question and saw another question and said "got anymore"
yes yes yes you dummy dumb dumb
this is an exam, your gcse
don't think its going to be easy
basically what I'm tryna say "e e why are you waffaklin for in de examdey ask you a question and you go say , ehe is this an elipse?"
well boohoo u got it wrong nigga
YES, I JUST UPLOADED THE SOLUTION TO THIS,
in the exam, i had NO CLUE 💀
argh thats annoying ..oh well
same lets gooooo
I got this right in the exam
The way I did it was at 2:09 the area of that half oval section is two overlapping circle sectors with an equilateral Trinangle ( and each circle sector had 60 degree angles cuz of the equilateral)
So find the area then multiply by 4 and subtract that from 16(pi)
I am in second year at uni and it still took me about 10-15 mins or so answering this question. Got the answer right in the end, but definitely a question that targets the grade 8 and 9 students.
I used pythagorus on the equilateral triangle to get the area. Then took that away from a sixth of the circle area to get the segment bit, then to that away from the triangle. A bit quicker than the above.
Can u even use Pythagoras on an eq triangle
@@estherereyemi9309 If you split the equilateral triangle in half, you have 2 right-angled triangles. You know the hypotenuse (in this case 4cm), and you know the short leg (2cm), so you can use Pythagoras to calculate the long leg, and thus you have the height of the equilateral triangle. You already know the base, so just use the standard formula to calculate the area.
It's basically the way that the formula for the area of an equilateral triangle [ = (√3/4)a² ] is derived.
@@Grizzly01 wait that's so smart
so now i know. i was never going to get it
This whole paper was a mess!!! Tnks for being soo generous with impossible questions🙄
Please make some predicted paper for 2 and 3 btw this question was hard...
inits
I got till 16 pi then i did not know that we have to draw the triangle and use cosine rule, I feel they dashed this down from A level To GCSE
It's more of an old-fashioned problem from something like Durell's book "New Geometry for Schools" (published in 1956) that was used extensively in secondary schools into the early 1980s for the O-level. More recently, they turn up as Math Olympiad questions from time to time. It used only GCSE techniques (construction of equilateral triangle, area of sector and segment, sin 60° = √3 / 2) but presented in an unfamiliar form as a challenge for grade 9 students.
I didn’t do this test but I got it slightly differently. If you split the shape into the equilateral triangles, instead of working out the sector, I just worked out that 3*(area of one triangle) + 3*(outer semi-circle looking shapes) = 8pi, and then I worked out the area of one small semi-circle thing by dividing this by 3, and then the area of the shaded region is 2(area of equilateral triangle - area of one semi-circle thing). Rip to ppl who got this question but extra rip to further maths students
Once I figured out about the equilateral triangles it took me 2 minutes… too bad I didn’t see it in the exam
Great video sir good job hard question.
Glad you liked it!
You get a lot questions like this in the UKMT
I loves this question ^v^
I'm actually a predicted 6 student but had the exact same methodology in my head, if only I trusted my gut I could've surprised my whole year 10 group XD
I wanted to cry in that usually get grade 9 and managed to zoom through paper and then spent half an hour slamming my head against the table in this question 😭😭
I find it beneficial for questions like this to break it down into a 'shape equation'.
Half of shaded area (split vertically) = semicircle - lens.
Half of lens = sector + (sector - equilateral triangle) = 2 x sector - equilateral triangle.
Areas of sectors (60°, r = 4), equilateral triangles (side = 4) and semicircles (r = 4) are all pretty straightforward to calculate.
Your honesty an amazing teacher, I literally have a playlist of your video, they are so helpful
I’m fully convinced this is the hardest gcse maths question I’ve ever seen (not including further maths)
it takes people with degrees in maths 2 hours to figure it out but they expect 16 year olds to do it
I loved this question! the reason im taking double maths next year 😄
good luck
This question convinces me to take math in university :)
Hope this question have lowered the grade boundaries 😢😅 cause I got my GCSE next year and I’m scared
grade boundaries are different each year and it doesn't matter from previous years. they are created after all the papers are marked each year to tailor it to the year 11 that did the exams that year. Hope this helps
Your grade boundaries will depend on how YOU and your year 11’s in the country do next year
I'm an A Level student who solved this problem in like 5 minutes, but even then, this is by no means an easy problem.
I bet you that 80% of my further math class dont know how to solve it.
I really have 0 idea how edexcel could have put a question like this.
Go on lad
I was just flipping through the paper almost having fun at some points and then… then I was faced with the ultimate boss… I couldn’t believe my eyes… the dreaded last questions of the paper 💀🪦 rip, my final brain cell
Don’t reply. Just give my brain cell a moments silence 🙏
I had fun with ur mum last night
I belive in you 😢
Does anyone think that writing 1 circle = 16 pi is worth a mark😂 I doubt it
Lol, I did the same thing
Yes it probs is worth a mark
it should be as working that out is necessary to figuring out the complete answer (props only 1 mark tho)
same here lol
I wrote that as well. I doubt it too. Perhaps if we'd written the formula down for the area of a sector of a circle we might have got a mark?
i had this exact question in a mock on monday, just wish i’d seen this earlier 😩
My first impulse was to use polar integration. Then I realised this question is for 16 year olds.
The key to this question is knowing that the circles intersect like hexagons, without that your stumped. I think it’s unfair to expect any gcse students to know this and apply it in an exam in such an obscure way
It is only simple geometry - the area of a circle and the area of a triangle, nothing too challenging there!
@@karhukivi the method and working out was light work, but ACTUALLY noticing the triangle at the very beginning under EXAM PRESSURE is nearly impossible
@@kardoxcenna260 I know what you mean, but you have to try to break down the problem by drawing lines, noticing that the three circles have the same radius length etc. Perhaps teachers are not teaching methods of problem-solving and just concentrating on memorising things.
@@karhukivi I got it right, at first I had no idea what to do but I started annotating the drawing and broke one of the semi-oval shapes into circle sectors and an equilateral triangle
@@novagod2107 That's the way to solve problems - good work!
only the smartest of the smart got this becuz this was acc mad
I've finished solving this with the correct answer. However, it took me around half an hour. I had a blast while solving it :)
Hey dude, what did you do at 9:26 to minus the bracket? Did you make the 8 root3 a fraction over 1, then multiply it by 3?
Okay, I see, I think you did 8pi/3 - 16pi/3 to make it -8pi/3
This solution is WAY over-complex, simply it is the area of a parellelogram minus area of sector (1//6 of a circle) this gives 1/2 . r . sqr(12) - pi.r^2 / 6 then double it !
ooops! ... that should be ..... r.sqr(12) - pi . r^2 / 6 then double it (where r=4 and Sqr(12) is height of //ogram using pythagorus on the equilateral triangle))
Using a parallelogram you would have to subtract the area of a sector and a segment before doubling it, which is the same method I used except you also have to incorporate Pythagoras to find the area of a parallelogram rather than the area of a triangle.
A really nice method but I wouldn’t say it’s easier, nor would I say it’s more or less complex! But definitely another interesting way of looking at it that I had considered!
All in all I used 5 different methods - this one included! And the method presented here was the preferred method by my students 😁
Of course we are all different and I would always encourage using the method that you prefer!
Thanks for sharing this one!
@@TheGCSEMathsTutor Tut tut tut ... look again , not so ... the equivalent of the exterior segement is incorporated in the //ogram so it is simply area of //ogram minus area of sector ... then double it ... elegant !
Bro this question, the vector one and the ratio one fucking killed me
I spent over 10 minutes on the ratios one and still couldn't solve it!!! The vector one was easier tho, you had to show they are multiples of ach other :)
How do u even practice questions of this type?
u need to love maths on another level and to be on a professional level of sad to actually get this question. Do u fit the criteria?
no one does
People have made "Gold tier questions", such as Save My Exams. Try those?
@@supahas3821 thank you.
Thanks so much for your help!
I feel like I’ve aced the exam today!
Am glad someone is actually confident about it~ I completely messed up mine 😭
@@Osamu_Dazaiii ah no I’m sure you did great!
Even if you have messed this one up there is room to improve with the other two papers!
You’ve got this!
@@shanz0663 Tysm... and ur right~ stressing over this would just affect my upcoming exams' guess I really needed to hear dis :)
Good luck for ur exams toooo ❤
The exam board are so mean for putting this as a question on the exam
I haven’t had that question on an exam before so there’s a high chance of it appearing
tbh I've come across no A Level question harder than this - and this is GCSE?!
How can a human being think of making question like this?
How do we know that the top-shaded segment is the same as the unshaded segment? BTW, you are soo helpful @TheGCSEMathsTutor
because the triangle is equilateral
didnt get this in the exam, but i had a go at it afterwards to see if i could do it without the time limit and it made me really happy to see that i got the answer right
shame i couldnt do it in the exam though :(
I did most of this but i forgot how to work out a sector so i just named it X and wrote my answer in terms of X
I just received the maths practice booklets from ur website sir, thank u so much!!
Amazing news! Hope you find them useful 😁🙏🏼
@@TheGCSEMathsTutor yes definitely ✨
Damn this took me a whole lot more steps than it took him. I didn't clock that the 3 segments mentioned are all equal. I did a different method I correctly reacehd the same solution. Goes to say that there are many routes to the right answer.
him a maths tutor doing this in 12 mins. edexcel wanting us to do it in 5 mins. make it make sense.
So my way of getting the 5 marks was actually way easier, I first worked out the area of the 3 circles added them together then skipped the rest of the question to get back the 5 marks through not wasting my time on this dumb question and doing an easier question instead
Todays paper was atrocious, I hope the boundaries are low
yeah 😭 i am just hoping w my whole heart boundaries are lowwww bc there r some questions that lit NOBODY got so..yh
HOPES SO TOOO!
@@not...not...no.643 nah bc what was the triangle and semi circle one 😭
@@riaasx I just wrote Pythagoras theorem
@@riaasx the ex in edexcel stands for exploitation atp 💔 we have been destroyed thru and thru.
If it took him more than 6ms how does edexcel expect us to do it in 5minutes lol
Edexcel maths is crazy. so glad we do OCR
came up in our mocks today and i smashed it
Do you have ocr specific videos for paper 5 ( second higher tier paper which is non calc)
fianlly a well explained video on this heack of a question!
Could you make 2 triangles with base AB and BC
Then work out those tiny segments
Add them together
Then work out the area of a semi circle
Then subtract the area of the semi circle from that?
mabye
After the exam, I worked out a general formula for any 3 circles laid out in the way that it was laid out in the question, with a radius of r.
The formula was: (r^2)sqrt(3)-(r^2)/3 pi
Don't ask why- the question was plaguing my mind
@Ciara Williams nice bit of basic primary school maths there lol good for you 🤣 here basically your formula is this 1x8x2/3-1x8x2/3(pi) lmao nice bit of nursery style maths for ya whoohoo go you 👍
Is this actually the formula?
@@estherereyemi9309 NO 🤣
@@estherereyemi9309 formula is A=PIr2 or A=804.25 🤓 which ever tickles your fancy 😜
@@estherereyemi9309 Yeah. I've tested it on questions similar to this on a website I trust. All of the answers were correct.
this is giving me war flashbacks man
I ended up wasting my time trying to do this, which made me lose dumb marks on other areas. If I had just ignored this I would of got like 70 but now it's like 60-65 :/
My maths teacher showed me how to do this, I usually have like 40 mins by the time I finish the paper but I doubt I would've worked it out myself in that time.
Yes it’s a tricky one under time pressure for sure!
How do people think this was an easy questions I’m either dumb or just really dumb😢
it is easy once you actually solve it
yo so many ppl hated that question at skl😭😭
2 of my maths teachers couldent do it and they expect people to do it
It honesty wasnt that bad, but i left my answer as 8 root 3 minus pi 4.6 reoccuring, would i get full marks for the question?
Thanks to your videos and the way u explain these type of difficult question I think I was able to to grab at least one or two marks for this questions as I too also drew a triangle attempting to find out the segment,but ran out of time as most the time I was just stuck! Also wanted to tanks u for ur videos which made most of this paper a breeze.
A nice clear explanation.
Thank you 😁🙏🏼
Im pretty sure this question was inspired by the olympic rings. Nevertheless, thanks, this will really help me when I do my GCSEs next year.
Just had this question in my paper 1 for my GCSE, took me 20 minutes of checking to make sure there were no mistakes. Shame to learn that this question was leaked so who knows whether ill get the marks for it but it was fun walking out of the exam hall learning I was the only person who even answered it. Sadly that 20 mins spent meant that i couldn't check my paper for stupid mistakes and i learned that i have made like simple addition mistakes in the 3 other final questions soooooooooooooooo rip me.
Edit: info about bad additions
Well done for completing it. Several of our students did too, but we enter a cadre into the Math Olympiad to give them a wider experience of questions than those in the text book.
Don't worry about the marks, that's up to the exam board to sort out. Given the surprise over the question, my thinking is that the leak was not widespread and the board will look for clusters of anomalous correct answers above an ability indicated in the rest of the papers; if that's the case, most students will gain marks for answering it.
that one there was a violation personally i wouldnt take that
and the fact that the gcse's get harder each year. this was already too hard
This paper went horrible for me 😭 plz help with paper 2 I am devastated
Wish u luck for ur next exams!
It was a really hard exam that a lot of people struggled with so the grade boundaries would probably be low, try not to stress over it too much or it may effect ur upcoming exams~ Just hope for the best and try hard. GOOD LUCK :)