U SAVED MY LIFE. I WAS REALLY BLUR THE WHOLE TIME WHEN MY LECTURER EXPLAINS THIS DURING MY MECHANICS CLASS BUT BRO U SAVED ME. NOW IM DOING MY HOMEWORK IN THE SPEED OF LIGHTNING AFTER WATCHING THIS. GOD BLESS U.
You are doing a deed which is the highest of ranks..you are serving knowledge!.. May god bless you for doing this in this century,where people are just spoiling others. Thanks a lot ,this helped me more than you think: )
I am doing engineering level 3 and I joined in late when they already finished this topic. I am grateful that I finally have learnt from you. Thanks for the video again. Keep on posting more great stuff.
What a brilliant video, I failed this topic first time around now I’m revising for it again and my lecture it’s the best. So this video has helped me a lot !
Thanks sir for the refreshment because it’s been like six years now I studied this. If I am not confused I believe the angle for the resultant force should be 360°-18.5° since all the angles of the other forces were taken from the posive x-axis for the calculation
Isn't the angle supposed to be read from the positive x-axis in an anticlockwise direction?? Which will make the reference angle for 18.5 degrees to 341.7?? I need clearance please
Yes, you are correct. 341.5 would be a suitable answer (-18.5 is also a suitable answer). The angle is to be read from the positive x-axis, in an anticlockwise direction based on the convention I have used. Some people may give you the requirement that the angle must be postive, and between 0 and 360 degrees.
This is a great video but I have a question?? I’ve been given a problem with a negative angle -30* would I assume this would be negative x and y axis so 330*?
The figure does help to point out the sign convention and I have used a symbol at 11:00 to indicate the sign convention. I do agree with John that including a diagram to indicate the sign convention could be useful to avoid any doubt as I have seen several questions about the angle and the negative sign with the 18.5 degree angle in the comments section of this video.
Thank u so much this video had helped me but , if i may ask why did u add all the forced and their angles together I thought there was a formula for this how can I use the formula to solve it
Not sure if I am answering your question but I will have a go. The reason for adding the forces together is because this could lead onto finding out the overall force acting on a system. This would/could then help us to find out loads and stresses within the system. You might notice that I am quite hesitant to write a formula. I have been stung in the past by being taught a formula only (it was a math exam when I was 17), but then I was given a question in a test that required proper understanding of what I was doing. As a result i wasn't able to even try the question. For this reason, I try to teach based on understanding the basic idea. However, here is a formula that may be useful for you Sum of forces in x direction = F1 * cos (theta1) + F2 * cos (theta2) + F3 * cos (theta3)+..... Sum of forces in y direction = F1 * sin (theta1) + F2 * sin (theta2) + F3 * sin (theta3)+..... Resultant = [ (sum of forces in x-direction)^2 + (sum of forces in y-direction)^2 ]^0.5 Angle = atan ( (sum of forces in y-direction)/(sum of forces in x-direction) ) **Note that for the angle you need to be aware that for tan there are multiple solutions between 0 and 360 deg and you will need to find the correct value.
Hello Tierra, I dealt with them by using an angle from the positive x-axis. The sine of an angle is positive from 0 degrees to 180 degrees, and negative from 180 degrees to 360 degrees. The cosine of an angle is positive from 0 to 90 degress, and 270 to 360 degrees; and negative from 90 degrees to 270 degrees. Check cos150 and you will see that this is a negative value. (x component for 5N force) Check sin150 and you will see that this a positive value. (y component for 5N force) Check cos300 and you will see that this is a positive value (x component for 15N force) Check sin300 and you will see that this is a negative value (y component for 15N force) Hope this helps
Please check your 5N force components. Why did you take 5cos150 as your x component? It should be y component as per the position of the angle 150deg. As the sine component always lies opposite to the angle whereas the other side is given to the cos component. Please check the resolution of the 5N force. I might be wrong too. Please correct me in that case. THANKS
Thanks for the tutorial, I really appreciate .. but why is the reference angle negative that is -18.5 I thought we make it positive... To get an accurate angle
No worries. The angle I have written as I am measuring the angle from the x-axis and assumed that anti-clockwise from this position is positive. This convention is fairly common. Since the direction is 18.5 degrees clockwise from the x-axis; I have written this as negative. Hope this helps.
You haven't considered the direction of sin and cosin, Why? I mean in ur video there is 15N acting downwardnso while adding the x component , it would be -15Cos(300) right?
Hi Mary, sorry for the delay. The direction is taken care of if we use all angles as measured from the x-axis because the sine curve is a negative when the angle is bigger than 180 and less that 360.
2 questions 1) How can u use cos and sin if you have angles like 300 meaning its not even a triangle anymore? 2)Why can you go clockwise for the final resultant answer but before all angles were measured anti clockwise?
1) Trigonometry is used in triangles, 3 sided shapes. It can not be used in others unless you split the shape into triangles and work it out from there. 2) The final resultant was negative, subtract this answer from 360 it will give you the anti clockwise angle. Hope this helped :)
Yep, you will get a different angle. You are using the tan equation to find an angle. Usually, I just draw the triangle that results in order to find an angle relative to either axis; then measure the angle from the x-axis. ------- tan equation below ------- Tan (angle) = opposite/adjacent In some countries they use Tan (angle) = perpendicular / base.. I dont like this naming convention because it confuses some people.
Hi Md ZI, there are different methods to solve this type of question. The 'tabular method' refers to the table being used. There are four other methods I am aware of: graphical method; analytical method; geometric method; unit vector. A special case of the unit vector method is to use matrices. For the second question, can you help me to understand what you mean by asking it in a slightly different way?
he get does degree from the reference angle which from Qudrant 1 cos going counter clockwise to the respected vector and then he subtract the given angle by. 90, 180, 270, and 360. (e.g F2 got 30 degree, so from the x axis from quadrant 1 counter clockwise to x axis of quadrant 2 therefore 180-30=150 degrees.
Thanks for the video, i learn a lot from it. I have a question, what will be the direction of a force whose vertical component is 0N and horizontal is 30N
Hi Albert, You would add the vectors head to tail; with the x-component pointing left (horizontal with the page) and the y-component pointing down (vertical with the page). You would have a triangle that looks like this... www.researchgate.net/figure/RightAngle-Triangle-Hopper-Scale-19-Therefore-from-the-right-angled-triangle-Fig_fig2_281274006 (ignore the y on this image) You could find the angle theta using the tan(theta)=O/A relationship Then to find the angle with respect to the x axis you would add 180 degrees to theta above. Note: If the vector is in the "third quadrant", the angle with respect to the x-axis should be between 180 degrees and 270 degrees. For the magnitude: you would do the same as in the video. Note that the square of a negative is a positive. For example (-4)^2 is equal to 16.
Hi Cephas Mwale. I'm assuming you mean the 'angle of the resultant of the net forces'. Answer: No, that is not correct. I have used the convention that a positive angle is measured anti-clockwise from the x-axis. In order for my answer to match that convention, I needed to calculate how big the angle is from the x-axis to the vector. In the video, I have found out the angle going clockwise. To get the anti-clockwise angle (from the positive x-axis), I used the idea that there is 360 degrees in a full rotation, and that the full 360 rotation is made up of the clockwise angle from the +ve x-axis and the anti-clockwise angle from the +ve x-axis. In short 360 = anti-clockwise angle from positive x-axis to the resultant vector + clockwise angle from positive x-axis to the resultant vector 360=anti-clockwise angle from positive x-axis to the resultant vector+18.5 anti-clockwise angle from positive x-axis to the resultant vector = 341.5
ani2000ify Hi there, this question shows a force system that is not balanced. That means the x component of the 5N force does not equal the x components of the 10N and 15N forces. One way to visualise this question is to replace the force vectors with distance vectors. Stand in a middle of a field, travel 10 metres at an angle of 45 degrees, then travel 5 metres at an angle of 150 degrees, then travel 15 metres at an angle of 300 degrees. The final location will not be the same as the starting location. Hope this answers your question.. if not let me know.
It would be more clear if I put it as the angle anti-clockwise as that is normal. At that time of making the video, I had made that decision because I had calculated the angle and was wanting to make it clear that angle was as measured clockwise from the axis. Both answers are right (measuring clockwise or anticlockwise); but different people have different conventions that they follow. In your case, you have been taught the convention that anti-clockwise measurement of angles is required. Using this anticlockwise is positive convention is good as it will set you up to use matrices in the future (should you learn this).
Greetings, are you interested in learning about and living for the saviour Jesus who can save your soul from Eternal Hell torment on Judgment day? If not don't read further. Are we the people still putting our trust in temporary things such as money, riches, pleasures of this world, politicians ect which cannot save us from Hell torment on Judgment day? Now is the time to put our trust instead on the eternal God which never dies rather than on temporary money and riches which get old and perish? Are we interested in living fully for our creator rather than being deceived and serving ourselves as our own god? If me and you aren't and want to continue putting our trust in perishable items and riches that cannot save us from Hell on Judgment day please let us not read any further. Originally man lived in pure happiness with God in Paradise but we sinned by disobeying God by eating fruit from the forbidden tree, because of this we were thrown out of Paradise and onto this earth, as we stubbornly found pleasure in eating from the forbidden tree although there were better trees to eat from in the Garden of Eden. God loves us so much that he made a way for us to enter back into paradise by sending his only son Jesus to die for our sins so that he can give us eternal life and save us from death and eternal punishment in Hell. Here is a pray that you and others can say to receive Jesus Christ as your Lord and saviour. Father in Heaven I receive your son Jesus as my Lord and saviour, I confess my sins and I ask you to forgive me for all my sins, wash and cleanse me and everything pertaining to me with the blood of your son Jesus and wash away all my spots, blemishes and wrinkles with the blood of your son Jesus. Father God in Heaven fill me with your Holy spirit every moment of my life and give me infinite oil for my spiritual lamps. I forgive and release all those who have done me wrong and I ask you to bless them and write my name permanently in the lambs book of life in Heaven in Jesus name I pray amen. Here is another pray to break curses and bind demons in our lives. Father God in Heaven I break and loose myself and my family from all curses going all the way back to Adam and Eve and I bind every demon and demonic influence in my life and in my family life permanently in Jesus name. I command all demons in my life and in my family life and those around me to leave and never return in Jesus name. Father God send your legions of Angels to fight for me until the end and send your ministering angels to keep ministering to me and always guide and protect me from all evil, I command Satan to get thee behind me and all of Gods creatures in Jesus name I pray amen. Pray always and study the KJV Bible to know more about Jesus and God's plan for our lives. Live a fully obedient life to God every moment of your life, no matter what Satan may throw against us continue to obey God's voice rather than Satan. Jesus bless you. Please pass on this message.
Sir could you please solve this question for me .I am not getting any idea to solve this Question What is the condition for equillibrium of concurrent force? 2 )A mass of 6 kg is suspended from ceiling by a rope of length 2 metre .A force of 50 N is applied at midpoint of rope in horizontal direction .What is the angle the rope making with vertical in equillibrium?(taking g = 10 m/s) 3 )what will be the angle made by the rope if its length is doubled?
U SAVED MY LIFE.
I WAS REALLY BLUR THE WHOLE TIME WHEN MY LECTURER EXPLAINS THIS DURING MY MECHANICS CLASS
BUT
BRO
U SAVED ME. NOW IM DOING MY HOMEWORK IN THE SPEED OF LIGHTNING AFTER WATCHING THIS.
GOD BLESS U.
Yuri Ikutsuki Glad I could help. Thanks for your message.
Cornelis Kok same
@@CornelisKok Fake account lmao
Wowohhhz
I'm watching in 2024❤
Same here
Same here
Same here
Me too got a test tomorrow 😅
Frr
This video has helped more than any textbook or lecture slide could ever do. Studying online isn't bad after all thank you!!
thanks a lot for the tutorial a lot has been learned....You have just educated a kid in Gaborone,Botswana,Africa through the power of internet
Glad this has been helpful for you!
How did it go with physics?
You are doing a deed which is the highest of ranks..you are serving knowledge!..
May god bless you for doing this in this
century,where people are just spoiling others.
Thanks a lot ,this helped me more than you think: )
If you look around closely, you will find that everyone is serving knowledge. One just have to open himself to get the effect!
Cheers mate
*G
The way my lecture calculated this was so confusing me, but now I get it, I will surely use this method..thank you so much
You are one of the best tutors I have ever met on TH-cam
this is much more easier than what our prof. taught us !! thank you so much!
I am doing engineering level 3 and I joined in late when they already finished this topic. I am grateful that I finally have learnt from you. Thanks for the video again. Keep on posting more great stuff.
Bro still in high school😢 and we do this in Fm
This was wayyyyyyyyyyy more easier than all of those laws that was needed to solve for this, thank you so much
What a brilliant video, I failed this topic first time around now I’m revising for it again and my lecture it’s the best. So this video has helped me a lot !
Thank you, I hope you did well in your assessment.
Imagins 6yrs ago and it's very useful for me today thanks man 🙏
Thanks sir for the refreshment because it’s been like six years now I studied this.
If I am not confused I believe the angle for the resultant force should be 360°-18.5° since all the angles of the other forces were taken from the posive x-axis for the calculation
Shout out to those who watching at exam time
Thanks to this man for making our maths classes easier
You do a much better job of explaining this than my tutor. Thanks.
THANK YOU SO MUCH YOU JUST SAVED MY LIFE IN THE HSC!!
thanx mate i was able to clear my internal exams thanx to you
Great to hear!
This is the best method, hands down. Cheers
shout out those watching at the time of quarantine
Meeeeh
Yessss. Let's get them grades!
@@moodymoe100 yes sirrrrrrrr!!!!!!
Late
Thanks for the lesson way more easier than the way my physics teacher taught me
Shout out to those watching before physics externals
GOOD lecture of high standard , thank you very much hope to see more in the subsequent days.
thankyou, you're a life saver from my physics class, you taught me very well than my prof, we love you :)
🥰
I UNDERSTAND WHAT I DONT UNDERSTAND I MY CLASS,THANKS.
Thanks very much, you have made me understand what i didn`t understand in class. Am humbled.
Thank you very much, i was totally confused when my lecturer taught me this. Thanks again for your help😊
I greatly appreciate. No wonder a day teaches for one to meet his destination.
thank u so much, i have mideterms coming up and this rly cleared stuff up
Awesome, good luck for your midterms.
Thank you so much..after searching a lot got your perfect video
thank u very much for helping me,love u my teacher,may god bless u
Wow you made this seem a lot more simple than when my teacher explained jt😂
I realy like your video .
U save my life those who going to darkness. Thank u sir g
You helped me.I didn't attend those lectures.now I understand
Great to hear, glad I could help.
@@corneliskok7794 where is your review finding forces vid? Cos sin....
Why do you choose negative angle when it is on the positive side of the horizontal line?
Great tutorial! This will help me out on my exam!
Thank you for the great lesson . How will we represent the angle if it has to be represented positively instead of negatively ?
you could add 360 degrees to the value to get an equivalent number.
-18.5+360 = 341.5
This is perfect thanks so much. God bless you and make you great in Jesus name amen
you might of just saved my T levels cheers boss
Isn't the angle supposed to be read from the positive x-axis in an anticlockwise direction??
Which will make the reference angle for 18.5 degrees to 341.7??
I need clearance please
Yes, you are correct. 341.5 would be a suitable answer (-18.5 is also a suitable answer). The angle is to be read from the positive x-axis, in an anticlockwise direction based on the convention I have used.
Some people may give you the requirement that the angle must be postive, and between 0 and 360 degrees.
Can you give a like if I say he is better than most of our lecturers in colleges
thanks for your teaching, help a lot
No worries, thank you for your appreciation.
You can write it -18.5 or 341.5
Really really great video!!! Thank you so much, it is very much appreciated.
Great that you have found it useful. You're welcome.
How did u find the 150° angle?
This is a great video but I have a question??
I’ve been given a problem with a negative angle -30* would I assume this would be negative x and y axis so 330*?
Sorry for the delay. Yes, that would be right.
It's more than a help,, thanks for the great job
An absolute legend this man!!!
THANKS SIR.
HOW TO SOLVE THE ONE WITH 4 FORCES ACTING ON THE POINT
You should include the sign convention on the angle theta
No, The direction is mentioned in the figure he made.
The figure itself justifies the direction.. this is amazing
The figure does help to point out the sign convention and I have used a symbol at 11:00 to indicate the sign convention. I do agree with John that including a diagram to indicate the sign convention could be useful to avoid any doubt as I have seen several questions about the angle and the negative sign with the 18.5 degree angle in the comments section of this video.
Thanks for making me understand this topic
Thank u so much this video had helped me but , if i may ask why did u add all the forced and their angles together I thought there was a formula for this how can I use the formula to solve it
Not sure if I am answering your question but I will have a go.
The reason for adding the forces together is because this could lead onto finding out the overall force acting on a system. This would/could then help us to find out loads and stresses within the system.
You might notice that I am quite hesitant to write a formula. I have been stung in the past by being taught a formula only (it was a math exam when I was 17), but then I was given a question in a test that required proper understanding of what I was doing. As a result i wasn't able to even try the question. For this reason, I try to teach based on understanding the basic idea.
However, here is a formula that may be useful for you
Sum of forces in x direction = F1 * cos (theta1) + F2 * cos (theta2) + F3 * cos (theta3)+.....
Sum of forces in y direction = F1 * sin (theta1) + F2 * sin (theta2) + F3 * sin (theta3)+.....
Resultant = [ (sum of forces in x-direction)^2 + (sum of forces in y-direction)^2 ]^0.5
Angle = atan ( (sum of forces in y-direction)/(sum of forces in x-direction) )
**Note that for the angle you need to be aware that for tan there are multiple solutions between 0 and 360 deg and you will need to find the correct value.
I understand this solution. Only thing is, how come we didn't account for the negative values in the 2nd and 4th quadrant?
Hello Tierra, I dealt with them by using an angle from the positive x-axis. The sine of an angle is positive from 0 degrees to 180 degrees, and negative from 180 degrees to 360 degrees. The cosine of an angle is positive from 0 to 90 degress, and 270 to 360 degrees; and negative from 90 degrees to 270 degrees.
Check cos150 and you will see that this is a negative value. (x component for 5N force)
Check sin150 and you will see that this a positive value. (y component for 5N force)
Check cos300 and you will see that this is a positive value (x component for 15N force)
Check sin300 and you will see that this is a negative value (y component for 15N force)
Hope this helps
Very great tutariol, how can we post some questions to you for help
this guy just save me, thanks !
Felt very good. I understood. Thanks you Sir 😊
Please check your 5N force components. Why did you take 5cos150 as your x component? It should be y component as per the position of the angle 150deg. As the sine component always lies opposite to the angle whereas the other side is given to the cos component. Please check the resolution of the 5N force. I might be wrong too. Please correct me in that case. THANKS
lifesaver, my maths lecturer only explained everything using 2 vectors but then gave us an assignment to find the resultant of 3 vectors
so thank you!
Very understandable and organised. Thanks!
This has helped a lot, thanks!
Thanks for the tutorial, I really appreciate .. but why is the reference angle negative that is -18.5
I thought we make it positive... To get an accurate angle
No worries.
The angle I have written as I am measuring the angle from the x-axis and assumed that anti-clockwise from this position is positive. This convention is fairly common.
Since the direction is 18.5 degrees clockwise from the x-axis; I have written this as negative.
Hope this helps.
You haven't considered the direction of sin and cosin, Why? I mean in ur video there is 15N acting downwardnso while adding the x component , it would be -15Cos(300) right?
Hi Mary, sorry for the delay. The direction is taken care of if we use all angles as measured from the x-axis because the sine curve is a negative when the angle is bigger than 180 and less that 360.
thankyou for sharing this method!!
This was very helpful.Thank you.
So to calculate the angles for the 5N,10N and 15N,do you have to start from the positive side of the x-axis?
If you use an angle from the positive x it gives you directly the sign where the force is going whether it is posive or negative.
How did the angle of the final answer became negative from positive 🙏
Who are you so wise in the ways of science
I hope it helped.
@@corneliskok7794 oh yeah it did, thanks!❤
Me watching this video in a lecture while the lecturer is busy reading exactly what's in the Slides.🙂
2 questions
1) How can u use cos and sin if you have angles like 300 meaning its not even a triangle anymore?
2)Why can you go clockwise for the final resultant answer but before all angles were measured anti clockwise?
1) Trigonometry is used in triangles, 3 sided shapes. It can not be used in others unless you split the shape into triangles and work it out from there.
2) The final resultant was negative, subtract this answer from 360 it will give you the anti clockwise angle. Hope this helped :)
Great vid!
Thank you so much sir. Helped me big time.
Thank you so very very very much
Thanks for your valuable help
For the resultant, do you have to go 'X' then 'Y' because the other way round would give the same magnitude R but a different angle right? cheers
Yep, you will get a different angle. You are using the tan equation to find an angle. Usually, I just draw the triangle that results in order to find an angle relative to either axis; then measure the angle from the x-axis.
------- tan equation below -------
Tan (angle) = opposite/adjacent
In some countries they use
Tan (angle) = perpendicular / base.. I dont like this naming convention because it confuses some people.
2:23
Excuse me, what's a tabular method?
Measured a the X-axis?:
10N
Hi Md ZI, there are different methods to solve this type of question. The 'tabular method' refers to the table being used. There are four other methods I am aware of: graphical method; analytical method; geometric method; unit vector. A special case of the unit vector method is to use matrices.
For the second question, can you help me to understand what you mean by asking it in a slightly different way?
In the beginning should it not be 5*cos(150) and 5*sin(150) instead of 30 degrees?
Wondering how you got 150° and 300°.
he get does degree from the reference angle which from Qudrant 1 cos going counter clockwise to the respected vector and then he subtract the given angle by. 90, 180, 270, and 360. (e.g F2 got 30 degree, so from the x axis from quadrant 1 counter clockwise to x axis of quadrant 2 therefore 180-30=150 degrees.
@@andresmichael359 thanks. I get now
Am I wrong if I just leave the answer as 10.8N and - 18.5 degrees without writing it the way u did it?
thank you so much, this really helped me so much!
Thanks for the video, i learn a lot from it.
I have a question, what will be the direction of a force whose vertical component is 0N and horizontal is 30N
can i say the x component for vector 15 N is 15*sin30 and y component as -15*cos30 ?
Yes
QUESTION:
what will you do when after adding the x-comp and you are getting a negative number and if same happens to the y-comp
Hi Albert, You would add the vectors head to tail; with the x-component pointing left (horizontal with the page) and the y-component pointing down (vertical with the page). You would have a triangle that looks like this... www.researchgate.net/figure/RightAngle-Triangle-Hopper-Scale-19-Therefore-from-the-right-angled-triangle-Fig_fig2_281274006 (ignore the y on this image)
You could find the angle theta using the tan(theta)=O/A relationship
Then to find the angle with respect to the x axis you would add 180 degrees to theta above.
Note: If the vector is in the "third quadrant", the angle with respect to the x-axis should be between 180 degrees and 270 degrees.
For the magnitude: you would do the same as in the video. Note that the square of a negative is a positive. For example (-4)^2 is equal to 16.
Oh MAN YOU'RE A FUCKING STAR...
Thank you so MUCH...
aren't you supposed to subtract them because they are not going on the same direction??
The video was great but aren’t you supposed to subtract 360-18.5 since it’s in the fourth quadrant
Yes, that would be suitable. Both answers represent the same direction.
loved the explanation.... I just subed!
Thank you for subbing and thanks for watching!
I have now understood thank you
How did the angle become a negative at the final answer
So does this mean that in the x component we are suppose to use a cosine and in the y component we use sin
I am still confused about the 5N < 150. Why 150? Isn't it supposed to be 160?
so is it always that the resultant of the net forces will be subtracted from 360 at the end yo workings
Hi Cephas Mwale. I'm assuming you mean the 'angle of the resultant of the net forces'.
Answer:
No, that is not correct.
I have used the convention that a positive angle is measured anti-clockwise from the x-axis.
In order for my answer to match that convention, I needed to calculate how big the angle is from the x-axis to the vector. In the video, I have found out the angle going clockwise. To get the anti-clockwise angle (from the positive x-axis), I used the idea that there is 360 degrees in a full rotation, and that the full 360 rotation is made up of the clockwise angle from the +ve x-axis and the anti-clockwise angle from the +ve x-axis.
In short
360 = anti-clockwise angle from positive x-axis to the resultant vector + clockwise angle from positive x-axis to the resultant vector
360=anti-clockwise angle from positive x-axis to the resultant vector+18.5
anti-clockwise angle from positive x-axis to the resultant vector = 341.5
Thank you for your explanation
why we did not subtract the x and y components of 5N force as 15N force will not overcome the 5 N force giving 10N force???
ani2000ify Hi there, this question shows a force system that is not balanced. That means the x component of the 5N force does not equal the x components of the 10N and 15N forces.
One way to visualise this question is to replace the force vectors with distance vectors. Stand in a middle of a field, travel 10 metres at an angle of 45 degrees, then travel 5 metres at an angle of 150 degrees, then travel 15 metres at an angle of 300 degrees. The final location will not be the same as the starting location.
Hope this answers your question.. if not let me know.
Pls a simple question i thought the angle for the resultant force was measured anticlockwise from the x axis so why did you measure it clockwise
It would be more clear if I put it as the angle anti-clockwise as that is normal.
At that time of making the video, I had made that decision because I had calculated the angle and was wanting to make it clear that angle was as measured clockwise from the axis. Both answers are right (measuring clockwise or anticlockwise); but different people have different conventions that they follow. In your case, you have been taught the convention that anti-clockwise measurement of angles is required. Using this anticlockwise is positive convention is good as it will set you up to use matrices in the future (should you learn this).
Good lecture
+Cornelis Kok my brother from another mother, thank you for this video! It's different to what I learnt, but it's easier I'm sure.
Greetings, are you interested in learning about and living for the saviour Jesus who can save your soul from Eternal Hell torment on Judgment day? If not don't read further. Are we the people still putting our trust in temporary things such as money, riches, pleasures of this world, politicians ect which cannot save us from Hell torment on Judgment day? Now is the time to put our trust instead on the eternal God which never dies rather than on temporary money and riches which get old and perish? Are we interested in living fully for our creator rather than being deceived and serving ourselves as our own god? If me and you aren't and want to continue putting our trust in perishable items and riches that cannot save us from Hell on Judgment day please let us not read any further.
Originally man lived in pure happiness with God in Paradise but we sinned by disobeying God by eating fruit from the forbidden tree, because of this we were thrown out of Paradise and onto this earth, as we stubbornly found pleasure in eating from the forbidden tree although there were better trees to eat from in the Garden of Eden. God loves us so much that he made a way for us to enter back into paradise by sending his only son Jesus to die for our sins so that he can give us eternal life and save us from death and eternal punishment in Hell. Here is a pray that you and others can say to receive Jesus Christ as your Lord and saviour.
Father in Heaven I receive your son Jesus as my Lord and saviour, I confess my sins and I ask you to forgive me for all my sins, wash and cleanse me and everything pertaining to me with the blood of your son Jesus and wash away all my spots, blemishes and wrinkles with the blood of your son Jesus. Father God in Heaven fill me with your Holy spirit every moment of my life and give me infinite oil for my spiritual lamps. I forgive and release all those who have done me wrong and I ask you to bless them and write my name permanently in the lambs book of life in Heaven in Jesus name I pray amen.
Here is another pray to break curses and bind demons in our lives.
Father God in Heaven I break and loose myself and my family from all curses going all the way back to Adam and Eve and I bind every demon and demonic influence in my life and in my family life permanently in Jesus name. I command all demons in my life and in my family life and those around me to leave and never return in Jesus name. Father God send your legions of Angels to fight for me until the end and send your ministering angels to keep ministering to me and always guide and protect me from all evil, I command Satan to get thee behind me and all of Gods creatures in Jesus name I pray amen.
Pray always and study the KJV Bible to know more about Jesus and God's plan for our lives. Live a fully obedient life to God every moment of your life, no matter what Satan may throw against us continue to obey God's voice rather than Satan. Jesus bless you. Please pass on this message.
Thanks
You are welcome :-)
OMG, YOU SAVED ME
Sir What about the direction of components of other two forces..? X component is negative in 3 quadrant please guide me
Sir could you please solve this question for me .I am not getting any idea to solve this Question
What is the condition for equillibrium of concurrent force?
2 )A mass of 6 kg is suspended from ceiling by a rope of length 2 metre .A force of 50 N is applied at midpoint of rope in horizontal direction .What is the angle the rope making with vertical in equillibrium?(taking g = 10 m/s)
3 )what will be the angle made by the rope if its length is doubled?
Hi Reshmi, at this moment I am unable to help. Maybe someone following this page can assist.