U SAVED MY LIFE. I WAS REALLY BLUR THE WHOLE TIME WHEN MY LECTURER EXPLAINS THIS DURING MY MECHANICS CLASS BUT BRO U SAVED ME. NOW IM DOING MY HOMEWORK IN THE SPEED OF LIGHTNING AFTER WATCHING THIS. GOD BLESS U.
You are doing a deed which is the highest of ranks..you are serving knowledge!.. May god bless you for doing this in this century,where people are just spoiling others. Thanks a lot ,this helped me more than you think: )
I am doing engineering level 3 and I joined in late when they already finished this topic. I am grateful that I finally have learnt from you. Thanks for the video again. Keep on posting more great stuff.
What a brilliant video, I failed this topic first time around now I’m revising for it again and my lecture it’s the best. So this video has helped me a lot !
Thanks sir for the refreshment because it’s been like six years now I studied this. If I am not confused I believe the angle for the resultant force should be 360°-18.5° since all the angles of the other forces were taken from the posive x-axis for the calculation
Isn't the angle supposed to be read from the positive x-axis in an anticlockwise direction?? Which will make the reference angle for 18.5 degrees to 341.7?? I need clearance please
Yes, you are correct. 341.5 would be a suitable answer (-18.5 is also a suitable answer). The angle is to be read from the positive x-axis, in an anticlockwise direction based on the convention I have used. Some people may give you the requirement that the angle must be postive, and between 0 and 360 degrees.
Please check your 5N force components. Why did you take 5cos150 as your x component? It should be y component as per the position of the angle 150deg. As the sine component always lies opposite to the angle whereas the other side is given to the cos component. Please check the resolution of the 5N force. I might be wrong too. Please correct me in that case. THANKS
This is a great video but I have a question?? I’ve been given a problem with a negative angle -30* would I assume this would be negative x and y axis so 330*?
Thank u so much this video had helped me but , if i may ask why did u add all the forced and their angles together I thought there was a formula for this how can I use the formula to solve it
Not sure if I am answering your question but I will have a go. The reason for adding the forces together is because this could lead onto finding out the overall force acting on a system. This would/could then help us to find out loads and stresses within the system. You might notice that I am quite hesitant to write a formula. I have been stung in the past by being taught a formula only (it was a math exam when I was 17), but then I was given a question in a test that required proper understanding of what I was doing. As a result i wasn't able to even try the question. For this reason, I try to teach based on understanding the basic idea. However, here is a formula that may be useful for you Sum of forces in x direction = F1 * cos (theta1) + F2 * cos (theta2) + F3 * cos (theta3)+..... Sum of forces in y direction = F1 * sin (theta1) + F2 * sin (theta2) + F3 * sin (theta3)+..... Resultant = [ (sum of forces in x-direction)^2 + (sum of forces in y-direction)^2 ]^0.5 Angle = atan ( (sum of forces in y-direction)/(sum of forces in x-direction) ) **Note that for the angle you need to be aware that for tan there are multiple solutions between 0 and 360 deg and you will need to find the correct value.
Hello Tierra, I dealt with them by using an angle from the positive x-axis. The sine of an angle is positive from 0 degrees to 180 degrees, and negative from 180 degrees to 360 degrees. The cosine of an angle is positive from 0 to 90 degress, and 270 to 360 degrees; and negative from 90 degrees to 270 degrees. Check cos150 and you will see that this is a negative value. (x component for 5N force) Check sin150 and you will see that this a positive value. (y component for 5N force) Check cos300 and you will see that this is a positive value (x component for 15N force) Check sin300 and you will see that this is a negative value (y component for 15N force) Hope this helps
he get does degree from the reference angle which from Qudrant 1 cos going counter clockwise to the respected vector and then he subtract the given angle by. 90, 180, 270, and 360. (e.g F2 got 30 degree, so from the x axis from quadrant 1 counter clockwise to x axis of quadrant 2 therefore 180-30=150 degrees.
Idk if this is too late but He already took into account the opposite directions when taking the angles from the x axis. You would only do the subtraction stuff if you left the angles the way they were given in the diagram.
The figure does help to point out the sign convention and I have used a symbol at 11:00 to indicate the sign convention. I do agree with John that including a diagram to indicate the sign convention could be useful to avoid any doubt as I have seen several questions about the angle and the negative sign with the 18.5 degree angle in the comments section of this video.
Hi Md ZI, there are different methods to solve this type of question. The 'tabular method' refers to the table being used. There are four other methods I am aware of: graphical method; analytical method; geometric method; unit vector. A special case of the unit vector method is to use matrices. For the second question, can you help me to understand what you mean by asking it in a slightly different way?
Thanks for the video. But while working I didn't see you taking into consideration the quadrant of the various functions (sin, cos) 🙄Like in the second quadrant cos is negative
You haven't considered the direction of sin and cosin, Why? I mean in ur video there is 15N acting downwardnso while adding the x component , it would be -15Cos(300) right?
Hi Mary, sorry for the delay. The direction is taken care of if we use all angles as measured from the x-axis because the sine curve is a negative when the angle is bigger than 180 and less that 360.
Thanks for the tutorial, I really appreciate .. but why is the reference angle negative that is -18.5 I thought we make it positive... To get an accurate angle
No worries. The angle I have written as I am measuring the angle from the x-axis and assumed that anti-clockwise from this position is positive. This convention is fairly common. Since the direction is 18.5 degrees clockwise from the x-axis; I have written this as negative. Hope this helps.
It would be more clear if I put it as the angle anti-clockwise as that is normal. At that time of making the video, I had made that decision because I had calculated the angle and was wanting to make it clear that angle was as measured clockwise from the axis. Both answers are right (measuring clockwise or anticlockwise); but different people have different conventions that they follow. In your case, you have been taught the convention that anti-clockwise measurement of angles is required. Using this anticlockwise is positive convention is good as it will set you up to use matrices in the future (should you learn this).
ani2000ify Hi there, this question shows a force system that is not balanced. That means the x component of the 5N force does not equal the x components of the 10N and 15N forces. One way to visualise this question is to replace the force vectors with distance vectors. Stand in a middle of a field, travel 10 metres at an angle of 45 degrees, then travel 5 metres at an angle of 150 degrees, then travel 15 metres at an angle of 300 degrees. The final location will not be the same as the starting location. Hope this answers your question.. if not let me know.
I should have put -3.42 into the pythagoras theorem. However, it doesn't change the result because the negative is squared (-3.42) squared = 11.6964 (notice that this is positive, if you are getting a negative number make sure you have the number -3.42 in brackets before squaring) (10.24) squared = 104.8576 11.6964 + 104.8576 = 116.554 square root of (116.554) = 10.80 kN
If you are representing the forces as phasors (like I am in the video above) then you would. Some people, including me, sometimes solve these questions by treating each of the forces as the hypotenuse of a triangle and use the values obtained at @2:15.
Greetings, are you interested in learning about and living for the saviour Jesus who can save your soul from Eternal Hell torment on Judgment day? If not don't read further. Are we the people still putting our trust in temporary things such as money, riches, pleasures of this world, politicians ect which cannot save us from Hell torment on Judgment day? Now is the time to put our trust instead on the eternal God which never dies rather than on temporary money and riches which get old and perish? Are we interested in living fully for our creator rather than being deceived and serving ourselves as our own god? If me and you aren't and want to continue putting our trust in perishable items and riches that cannot save us from Hell on Judgment day please let us not read any further. Originally man lived in pure happiness with God in Paradise but we sinned by disobeying God by eating fruit from the forbidden tree, because of this we were thrown out of Paradise and onto this earth, as we stubbornly found pleasure in eating from the forbidden tree although there were better trees to eat from in the Garden of Eden. God loves us so much that he made a way for us to enter back into paradise by sending his only son Jesus to die for our sins so that he can give us eternal life and save us from death and eternal punishment in Hell. Here is a pray that you and others can say to receive Jesus Christ as your Lord and saviour. Father in Heaven I receive your son Jesus as my Lord and saviour, I confess my sins and I ask you to forgive me for all my sins, wash and cleanse me and everything pertaining to me with the blood of your son Jesus and wash away all my spots, blemishes and wrinkles with the blood of your son Jesus. Father God in Heaven fill me with your Holy spirit every moment of my life and give me infinite oil for my spiritual lamps. I forgive and release all those who have done me wrong and I ask you to bless them and write my name permanently in the lambs book of life in Heaven in Jesus name I pray amen. Here is another pray to break curses and bind demons in our lives. Father God in Heaven I break and loose myself and my family from all curses going all the way back to Adam and Eve and I bind every demon and demonic influence in my life and in my family life permanently in Jesus name. I command all demons in my life and in my family life and those around me to leave and never return in Jesus name. Father God send your legions of Angels to fight for me until the end and send your ministering angels to keep ministering to me and always guide and protect me from all evil, I command Satan to get thee behind me and all of Gods creatures in Jesus name I pray amen. Pray always and study the KJV Bible to know more about Jesus and God's plan for our lives. Live a fully obedient life to God every moment of your life, no matter what Satan may throw against us continue to obey God's voice rather than Satan. Jesus bless you. Please pass on this message.
U SAVED MY LIFE.
I WAS REALLY BLUR THE WHOLE TIME WHEN MY LECTURER EXPLAINS THIS DURING MY MECHANICS CLASS
BUT
BRO
U SAVED ME. NOW IM DOING MY HOMEWORK IN THE SPEED OF LIGHTNING AFTER WATCHING THIS.
GOD BLESS U.
Yuri Ikutsuki Glad I could help. Thanks for your message.
Cornelis Kok same
@@CornelisKok Fake account lmao
Wowohhhz
This video has helped more than any textbook or lecture slide could ever do. Studying online isn't bad after all thank you!!
thanks a lot for the tutorial a lot has been learned....You have just educated a kid in Gaborone,Botswana,Africa through the power of internet
Glad this has been helpful for you!
How did it go with physics?
You are doing a deed which is the highest of ranks..you are serving knowledge!..
May god bless you for doing this in this
century,where people are just spoiling others.
Thanks a lot ,this helped me more than you think: )
If you look around closely, you will find that everyone is serving knowledge. One just have to open himself to get the effect!
Cheers mate
*G
The way my lecture calculated this was so confusing me, but now I get it, I will surely use this method..thank you so much
this is much more easier than what our prof. taught us !! thank you so much!
I am doing engineering level 3 and I joined in late when they already finished this topic. I am grateful that I finally have learnt from you. Thanks for the video again. Keep on posting more great stuff.
Bro still in high school😢 and we do this in Fm
You are one of the best tutors I have ever met on TH-cam
This was wayyyyyyyyyyy more easier than all of those laws that was needed to solve for this, thank you so much
I'm watching in 2024❤
Same here
Same here
Same here
Me too got a test tomorrow 😅
Frr
What a brilliant video, I failed this topic first time around now I’m revising for it again and my lecture it’s the best. So this video has helped me a lot !
Thank you, I hope you did well in your assessment.
lifesaver, my maths lecturer only explained everything using 2 vectors but then gave us an assignment to find the resultant of 3 vectors
so thank you!
Imagins 6yrs ago and it's very useful for me today thanks man 🙏
You do a much better job of explaining this than my tutor. Thanks.
Thanks for the lesson way more easier than the way my physics teacher taught me
thankyou, you're a life saver from my physics class, you taught me very well than my prof, we love you :)
🥰
thanx mate i was able to clear my internal exams thanx to you
Great to hear!
Thanks to this man for making our maths classes easier
Thanks very much, you have made me understand what i didn`t understand in class. Am humbled.
THANK YOU SO MUCH YOU JUST SAVED MY LIFE IN THE HSC!!
Thank youuuu, I did not understand this at all until now
Thank you so much..after searching a lot got your perfect video
This is the best method, hands down. Cheers
I greatly appreciate. No wonder a day teaches for one to meet his destination.
Thanks sir for the refreshment because it’s been like six years now I studied this.
If I am not confused I believe the angle for the resultant force should be 360°-18.5° since all the angles of the other forces were taken from the posive x-axis for the calculation
Shout out to those who watching at exam time
GOOD lecture of high standard , thank you very much hope to see more in the subsequent days.
thank u so much, i have mideterms coming up and this rly cleared stuff up
Awesome, good luck for your midterms.
I UNDERSTAND WHAT I DONT UNDERSTAND I MY CLASS,THANKS.
Thank you!
May God bless u and you loved ones.
Shout out to those watching before physics externals
Thank you very much, i was totally confused when my lecturer taught me this. Thanks again for your help😊
You helped me.I didn't attend those lectures.now I understand
Great to hear, glad I could help.
@@corneliskok7794 where is your review finding forces vid? Cos sin....
Great tutorial! This will help me out on my exam!
thank u very much for helping me,love u my teacher,may god bless u
you might of just saved my T levels cheers boss
clear,neat and understandable for all pupil thanks a lot.
shout out those watching at the time of quarantine
Meeeeh
Yessss. Let's get them grades!
@@moodymoe100 yes sirrrrrrrr!!!!!!
Late
Later😢@@ratava2285
Really really great video!!! Thank you so much, it is very much appreciated.
Great that you have found it useful. You're welcome.
Why do you choose negative angle when it is on the positive side of the horizontal line?
Is the force measured anticlockwise or clockwise just at the description and is it going to be
negative
If I understood your question correctly it's measured anticlockwise. Just like how the unit circle is.
It's more than a help,, thanks for the great job
Wow you made this seem a lot more simple than when my teacher explained jt😂
Isn't the angle supposed to be read from the positive x-axis in an anticlockwise direction??
Which will make the reference angle for 18.5 degrees to 341.7??
I need clearance please
Yes, you are correct. 341.5 would be a suitable answer (-18.5 is also a suitable answer). The angle is to be read from the positive x-axis, in an anticlockwise direction based on the convention I have used.
Some people may give you the requirement that the angle must be postive, and between 0 and 360 degrees.
thanks for your teaching, help a lot
No worries, thank you for your appreciation.
Thanks for making me understand this topic
This has helped a lot, thanks!
Can you give a like if I say he is better than most of our lecturers in colleges
Felt very good. I understood. Thanks you Sir 😊
How did u find the 150° angle?
This was very helpful.Thank you.
this guy just save me, thanks !
Please check your 5N force components. Why did you take 5cos150 as your x component? It should be y component as per the position of the angle 150deg. As the sine component always lies opposite to the angle whereas the other side is given to the cos component. Please check the resolution of the 5N force. I might be wrong too. Please correct me in that case. THANKS
thank you so much, this really helped me so much!
This is a great video but I have a question??
I’ve been given a problem with a negative angle -30* would I assume this would be negative x and y axis so 330*?
Sorry for the delay. Yes, that would be right.
I realy like your video .
U save my life those who going to darkness. Thank u sir g
Thank you so much sir. Helped me big time.
You can write it -18.5 or 341.5
This is perfect thanks so much. God bless you and make you great in Jesus name amen
Thank u so much this video had helped me but , if i may ask why did u add all the forced and their angles together I thought there was a formula for this how can I use the formula to solve it
Not sure if I am answering your question but I will have a go.
The reason for adding the forces together is because this could lead onto finding out the overall force acting on a system. This would/could then help us to find out loads and stresses within the system.
You might notice that I am quite hesitant to write a formula. I have been stung in the past by being taught a formula only (it was a math exam when I was 17), but then I was given a question in a test that required proper understanding of what I was doing. As a result i wasn't able to even try the question. For this reason, I try to teach based on understanding the basic idea.
However, here is a formula that may be useful for you
Sum of forces in x direction = F1 * cos (theta1) + F2 * cos (theta2) + F3 * cos (theta3)+.....
Sum of forces in y direction = F1 * sin (theta1) + F2 * sin (theta2) + F3 * sin (theta3)+.....
Resultant = [ (sum of forces in x-direction)^2 + (sum of forces in y-direction)^2 ]^0.5
Angle = atan ( (sum of forces in y-direction)/(sum of forces in x-direction) )
**Note that for the angle you need to be aware that for tan there are multiple solutions between 0 and 360 deg and you will need to find the correct value.
An absolute legend this man!!!
thankyou for sharing this method!!
Who are you so wise in the ways of science
I hope it helped.
@@corneliskok7794 oh yeah it did, thanks!❤
Watching in 2024 thank you so much 🙏🇿🇲🇿🇲
loved the explanation.... I just subed!
Thank you for subbing and thanks for watching!
I understand this solution. Only thing is, how come we didn't account for the negative values in the 2nd and 4th quadrant?
Hello Tierra, I dealt with them by using an angle from the positive x-axis. The sine of an angle is positive from 0 degrees to 180 degrees, and negative from 180 degrees to 360 degrees. The cosine of an angle is positive from 0 to 90 degress, and 270 to 360 degrees; and negative from 90 degrees to 270 degrees.
Check cos150 and you will see that this is a negative value. (x component for 5N force)
Check sin150 and you will see that this a positive value. (y component for 5N force)
Check cos300 and you will see that this is a positive value (x component for 15N force)
Check sin300 and you will see that this is a negative value (y component for 15N force)
Hope this helps
Wondering how you got 150° and 300°.
he get does degree from the reference angle which from Qudrant 1 cos going counter clockwise to the respected vector and then he subtract the given angle by. 90, 180, 270, and 360. (e.g F2 got 30 degree, so from the x axis from quadrant 1 counter clockwise to x axis of quadrant 2 therefore 180-30=150 degrees.
@@andresmichael359 thanks. I get now
aren't you supposed to subtract them because they are not going on the same direction??
Idk if this is too late but He already took into account the opposite directions when taking the angles from the x axis. You would only do the subtraction stuff if you left the angles the way they were given in the diagram.
You should include the sign convention on the angle theta
No, The direction is mentioned in the figure he made.
The figure itself justifies the direction.. this is amazing
The figure does help to point out the sign convention and I have used a symbol at 11:00 to indicate the sign convention. I do agree with John that including a diagram to indicate the sign convention could be useful to avoid any doubt as I have seen several questions about the angle and the negative sign with the 18.5 degree angle in the comments section of this video.
Thank you for the great lesson . How will we represent the angle if it has to be represented positively instead of negatively ?
you could add 360 degrees to the value to get an equivalent number.
-18.5+360 = 341.5
Very great tutariol, how can we post some questions to you for help
THANKS SIR.
HOW TO SOLVE THE ONE WITH 4 FORCES ACTING ON THE POINT
2:23
Excuse me, what's a tabular method?
Measured a the X-axis?:
10N
Hi Md ZI, there are different methods to solve this type of question. The 'tabular method' refers to the table being used. There are four other methods I am aware of: graphical method; analytical method; geometric method; unit vector. A special case of the unit vector method is to use matrices.
For the second question, can you help me to understand what you mean by asking it in a slightly different way?
But our x is negative where we use the Pythagoras theorem
Thanks for the video.
But while working I didn't see you taking into consideration the quadrant of the various functions (sin, cos)
🙄Like in the second quadrant cos is negative
Cos 150 is already negative so the symbol doesn’t need to be there
How did the angle of the final answer became negative from positive 🙏
Oh MAN YOU'RE A FUCKING STAR...
Thank you so MUCH...
can i say the x component for vector 15 N is 15*sin30 and y component as -15*cos30 ?
Yes
You haven't considered the direction of sin and cosin, Why? I mean in ur video there is 15N acting downwardnso while adding the x component , it would be -15Cos(300) right?
Hi Mary, sorry for the delay. The direction is taken care of if we use all angles as measured from the x-axis because the sine curve is a negative when the angle is bigger than 180 and less that 360.
Thanks for the tutorial, I really appreciate .. but why is the reference angle negative that is -18.5
I thought we make it positive... To get an accurate angle
No worries.
The angle I have written as I am measuring the angle from the x-axis and assumed that anti-clockwise from this position is positive. This convention is fairly common.
Since the direction is 18.5 degrees clockwise from the x-axis; I have written this as negative.
Hope this helps.
So does this mean that in the x component we are suppose to use a cosine and in the y component we use sin
Love it ❤️🫡
Thanks for your valuable help
Pls a simple question i thought the angle for the resultant force was measured anticlockwise from the x axis so why did you measure it clockwise
It would be more clear if I put it as the angle anti-clockwise as that is normal.
At that time of making the video, I had made that decision because I had calculated the angle and was wanting to make it clear that angle was as measured clockwise from the axis. Both answers are right (measuring clockwise or anticlockwise); but different people have different conventions that they follow. In your case, you have been taught the convention that anti-clockwise measurement of angles is required. Using this anticlockwise is positive convention is good as it will set you up to use matrices in the future (should you learn this).
I have now understood thank you
In the beginning should it not be 5*cos(150) and 5*sin(150) instead of 30 degrees?
why we did not subtract the x and y components of 5N force as 15N force will not overcome the 5 N force giving 10N force???
ani2000ify Hi there, this question shows a force system that is not balanced. That means the x component of the 5N force does not equal the x components of the 10N and 15N forces.
One way to visualise this question is to replace the force vectors with distance vectors. Stand in a middle of a field, travel 10 metres at an angle of 45 degrees, then travel 5 metres at an angle of 150 degrees, then travel 15 metres at an angle of 300 degrees. The final location will not be the same as the starting location.
Hope this answers your question.. if not let me know.
thank you so much
Glad I could help.
Please why is it that when solving using the Pythagoras theorem the y-value the negative was neglected when solving. The y -value was -3.42N
I should have put -3.42 into the pythagoras theorem.
However, it doesn't change the result because the negative is squared
(-3.42) squared = 11.6964 (notice that this is positive, if you are getting a negative number make sure you have the number -3.42 in brackets before squaring)
(10.24) squared = 104.8576
11.6964 + 104.8576 = 116.554
square root of (116.554) = 10.80 kN
Do you always have to read anti clockwise
If you are representing the forces as phasors (like I am in the video above) then you would. Some people, including me, sometimes solve these questions by treating each of the forces as the hypotenuse of a triangle and use the values obtained at @2:15.
Am I wrong if I just leave the answer as 10.8N and - 18.5 degrees without writing it the way u did it?
Thank you so very very very much
How do u know that the angle is negative?
How did the angle become a negative at the final answer
Wow
Very explained
Good lecture
+Cornelis Kok my brother from another mother, thank you for this video! It's different to what I learnt, but it's easier I'm sure.
Greetings, are you interested in learning about and living for the saviour Jesus who can save your soul from Eternal Hell torment on Judgment day? If not don't read further. Are we the people still putting our trust in temporary things such as money, riches, pleasures of this world, politicians ect which cannot save us from Hell torment on Judgment day? Now is the time to put our trust instead on the eternal God which never dies rather than on temporary money and riches which get old and perish? Are we interested in living fully for our creator rather than being deceived and serving ourselves as our own god? If me and you aren't and want to continue putting our trust in perishable items and riches that cannot save us from Hell on Judgment day please let us not read any further.
Originally man lived in pure happiness with God in Paradise but we sinned by disobeying God by eating fruit from the forbidden tree, because of this we were thrown out of Paradise and onto this earth, as we stubbornly found pleasure in eating from the forbidden tree although there were better trees to eat from in the Garden of Eden. God loves us so much that he made a way for us to enter back into paradise by sending his only son Jesus to die for our sins so that he can give us eternal life and save us from death and eternal punishment in Hell. Here is a pray that you and others can say to receive Jesus Christ as your Lord and saviour.
Father in Heaven I receive your son Jesus as my Lord and saviour, I confess my sins and I ask you to forgive me for all my sins, wash and cleanse me and everything pertaining to me with the blood of your son Jesus and wash away all my spots, blemishes and wrinkles with the blood of your son Jesus. Father God in Heaven fill me with your Holy spirit every moment of my life and give me infinite oil for my spiritual lamps. I forgive and release all those who have done me wrong and I ask you to bless them and write my name permanently in the lambs book of life in Heaven in Jesus name I pray amen.
Here is another pray to break curses and bind demons in our lives.
Father God in Heaven I break and loose myself and my family from all curses going all the way back to Adam and Eve and I bind every demon and demonic influence in my life and in my family life permanently in Jesus name. I command all demons in my life and in my family life and those around me to leave and never return in Jesus name. Father God send your legions of Angels to fight for me until the end and send your ministering angels to keep ministering to me and always guide and protect me from all evil, I command Satan to get thee behind me and all of Gods creatures in Jesus name I pray amen.
Pray always and study the KJV Bible to know more about Jesus and God's plan for our lives. Live a fully obedient life to God every moment of your life, no matter what Satan may throw against us continue to obey God's voice rather than Satan. Jesus bless you. Please pass on this message.
Me watching this video in a lecture while the lecturer is busy reading exactly what's in the Slides.🙂
The video was great but aren’t you supposed to subtract 360-18.5 since it’s in the fourth quadrant
Yes, that would be suitable. Both answers represent the same direction.
Thank you for your explanation